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Effective Date
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Devil's Isle Survivor:
Chaos... That's right. That's the best word I can use to describe it...
It was like something ripped a hole in reality itself. Both captain and crew were sucked in...
I later heared that power is called Kamaloka or Pailaka or somesuch. They say that it will engulf the entire world.
That's when my nightmares came... Soon after closing my eyes, I dream of strenge and horrible monsters who forture me until I wake again. Ah, but the real problem was something else... Do you know what it is?
Ask him to tell you.


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{% verbatim %}
A model is an output of the training process. One complete model consists of two parts, the topology and the parameters. In order to support industrial deployment, the model format must be self-complete and must not expose any training source code.
As a result, In PaddlePaddle, the topology is represented as a ProgramDesc, which describes the model structure. The parameters contain all the trainable weights in the model. We must support large size parameters and efficient serialization/deserialization of parameters.
The topology is saved as a plain text in a detailed self-contain protobuf file.
The parameters are saved as a binary file. As we all know, the protobuf message has a limit of 64M size. We have done a benchmark experiment, which shows that protobuf is not fit for the task.
As a result, we design a particular format for tensor serialization. By default, an arbitrary tensor in Paddle is a LoDTensor, and has a description information proto of LoDTensorDesc. We save the DescProto as the byte string header. It contains all the necessary information, such as the dims
, and the LoD
information in LoDTensor. A tensor stores values in a continuous memory buffer. For speed we dump the raw memory to disk and save it as the byte string content. So, the binary format of one tensor is,
The table below shows a tensor's byte view in detail. Note that all the signed values are written in the little-endian format.
| field name | type | description |
|---|---|---|
| version | uint32_t | Version of saved file. Always 0 now. |
| tensor desc length | uint32_t | TensorDesc(Protobuf message) length in bytes. |
| tensor desc | void* | TensorDesc protobuf binary message |
| tensor data | void* | Tensor's data in binary format. The length of `tensor_data` is decided by `TensorDesc.dims()` and `TensorDesc.data_type()` |
| lod_level | uint64_t | Level of LoD |
| length of lod[0] | uint64_t | [Optional] length of lod[0] in bytes. |
| data of lod[0] | uint64_t* | [Optional] lod[0].data() |
| ... | ... | ... |


Soldier who survived IRA attack thanks first responders as he returns to scene
A British soldier badly injured in an IRA bus attack has paid tribute to those who helped him, as he revisited the scene for the first time.
Eight servicemen were killed in the Ballygawley bombing in Co Tyrone in 1988.
Members of the Light Infantry Regiment, from England, were returning to a base near Omagh after a short holiday.
Dave Hardy was among the 28 injured, and he suffered broken bones and a brain injury.
On the eve of Remembrance Sunday, a special gathering was held in Omagh.
Mr Hardy said: “I am asking questions and getting answers that I have never been able to get before, like how did I get to hospital.
“I am very happy that I was not alone.”
Someone walked out and said everything is going to be okay
The IRA set off a 200-pound roadside Semtex bomb as the bus was travelling between Ballygawley and Omagh.
Members of the Omagh Protestant Boys Band returning from a parade were among the first at the scene and tried to resuscitate soldiers, who were lying on the road.
Mr Hardy, 53, from Durham, was trying to sleep on the bus and the first thing the then private remembers is lying on the road unable to get up, but no pain.
He added: “I heard crying, it was the horrible, stomach-wrenching cry of pain.”
He was in hospital in a coma for a month or more and underwent rehabilitation in Surrey before being medically discharged from the Army.
He said he had been suppressing emotion associated with the attack.
“It is a weird sensation, there is no emotion, I think it could be just a defence mechanism.”
Members of the public, including nearby residents and two flute bands who were travelling on the road, comforted the wounded until emergency services arrived.
Mr Hardy was taken to hospital in nearby Dungannon in one of the first ambulances.
He recalled seeing a bright light.
“Someone walked out and said everything is going to be okay.”


@* * Copyright 2023 HM Revenue & Customs * * Licensed under the Apache License, Version 2.0 (the "License"); * you may not use this file except in compliance with the License. * You may obtain a copy of the License at * * http://www.apache.org/licenses/LICENSE-2.0 * * Unless required by applicable law or agreed to in writing, software * distributed under the License is distributed on an "AS IS" BASIS, * WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied. * See the License for the specific language governing permissions and * limitations under the License. *@ @import config.ApplicationConfig @this( govuk_wrapper: views.html.govuk_wrapper ) @()(implicit request: Request[_], messages: Messages, appConfig: ApplicationConfig) @govuk_wrapper(pageTitle = messages("unauthorised.error.page.title")) {
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| www.procontechnology.com.au
MATHS TRICKS AND TIPS |
In my opinion, Kjartan Poskitt does for maths what J.K.Rowling (of Harry Potter fame) and Paul Jennings (an Australian author) do for reading! Check out Kjartan Poskitt's latest book 'Professor Fiendish's book of diabolical brain-benders' with lots of Murderous Maths problems and puzzles.
Don’t forget, if you find this page useful (or even if you don’t) why not look around our website - you just might find something useful, such as the fischertechnik robotic construction set or weather station or other things for yourself or that unique gift. Check the links below for more hot items.
The famous Galileo Galilei once wrote an elegant tribute to the power of mathematics. It said, "This grand book 'The Universe' could only be understood if one learnt to comprehend the language of the alphabet in which it was composed. This is the language of mathematics. That is triangles, circles and geometic figures. Without which it is impossible, humanly impossible, to understand a word of it. Without it one wanders, as in a dark labyrinth."
Here's another interesting quote from the movie 'Enigma'. When Tom is asked "Why are you a mathematician - do you like sums?" He replies, "I like numbers, because with numbers truth and beauty are the same thing. You know you're getting somewhere when the equations start looking beautiful. Then you know the numbers are taking you closer to the secret of how things are."
Before I start, here’s a joke...
The US president, George Bush, gave a press conference where he explained how US forces stormed an Iraqi primary school and captured a teacher. It was found that this teacher had in his possession; a compass, a protractor and a calculator. After a slight pause, the president added 'clearly, here is the evidence that Iraq has weapons of maths instruction.'
LIST OF TRICKS AND TIPS ON THIS WEBPAGE:
2. No elephants in Demark trick
3. The ultimate missing number trick
4. Mental maths and not-so-mental maths*
5. Mental as anything (more mental maths)*
6. Devising your own divisibility tests*
7. Fun and games on a calculator*
8. Computer maths (or 2 fingered maths)*
9. Problem solving made easy (well, easier anyway)*
10. FEEDBACK (your comments here)*
1. THE MISSING NUMBER TRICK.
(a) Ask someone to write on a piece of paper (so you can’t see it) a large
number (I suggest 5 digits to start with).
(b) Ask them to rearrange the digits in that number and write it above the
first number if it is larger but below it if smaller.
(c) Then tell them to subtract the two numbers (they can use a calculator if
they wish).
(d) Ask them to circle any digit in the result except zero.
(e) They can then read out (slowly), all the other digits in random order.
And you will tell them what the digit is that they circled.
(f) To find the missing digit, simply add up all the digits that they give
you - repeatedly - until a single digit 1 to 9 is obtained. If this value is 9,
then the number they circled was 9. Otherwise, add a value to the number until
it is 9. This value is the number they circled! e.g. If the digits are 9, 8, 8
and 4, then 9+8+8+4=29, 2+9=11, 1+1=2. 9-2=7. Therefore the number circled was
7.
Variations of this trick
(a) Ask them to write the largest number possible (10 or maybe 20 digits) and
repeat the trick. Remember, if they are using a calculator, the maximum number
of digits that can be entered on the calculator may be 8, 10 or 12 digits.
(b) Instead of rearranging the digits, ask them to add up the digits and
subtract this total from the number. This may also be done as an extra step! Or,
for a real interesting variation, ask them to add up only the odd digits (units,
hundreds ...) then subtract this value from the number. Then add up the even
digits (tens, thousands ...) and add this to that result - then add it again.
Finally, multiply the result by three!
(c) As an extra step (before or after the subtraction), ask them to subtract
a number (e.g. 1, 2 ,3) from one digit and add it to another digit - even having
a carry or borrow is OK! They could also subtract a number from one digit and
place this value as an extra digit anywhere in number (on the left or right of
the other digits is best). Also as an extra step (after the subtraction), you
can ask them to add the number 3456 for example. Once you discover the 'secret'
of this trick you'll see that many other numbers can be 'safely' added or
subtracted and the trick still works! Finally, as an interesting variation, ask
them to remove any digit from the number (cross it off) multiply this digit by 8
and then subtract this value from any digit(s) in the number. You can even ask
them to split the value into two digits and subtract these separately anywhere
in the their number!
(d) Ask them to circle any digit except nine. Then, in step (f), if the sum
of digits is 9 the number circled will be zero!
(e) Ask them to write all digits (except that circled) on a piece of paper
and hand it to you. This makes it easier if you’re not great at mental
arithmetic.
(f) Instead of adding the digits mentally, enter them on a calculator and
then divide by 9. If there is no decimal part, the number circled was nine (or
zero if the variation above is used). Otherwise, the digit to the right of the
decimal point is subtracted from nine to get the digit circled!
(g) This trick also works with other number systems. e.g. octal (base 8) or
hexadecimal (base 16). Only one small variation is needed to determine the
missing number. What is it? Most people can’t add or subtract in other number
systems mentally, so you might like to try this with a calculator such as the
Casio fx-100 which does binary, octal and hexadecimal calculations. You should
note that binary (base 2) is useless for this trick...why?
How does this trick work?
This is a truly great trick that can be used to amaze your friends and
relatives and it works very simply. How?  For now, this trick works because of what is
called ‘digital roots’. There are other interesting things you can do with
‘digital roots’ which I’ll also explain over the coming weeks and months.
2. NO ELEPHANTS IN DEMARK TRICK.
This trick starts the same as the one above ... variations a, b and c can
also be used!
(a) Ask someone to write on a piece of paper (secretly so you can’t see it) a
large number (I suggest 5 digits to start with).
(b) Tell them to rearrange the digits in that number and write it above the
first number if it is larger but below it if smaller.
(c) Ask them to subtract the two numbers (they can use a calculator if they
wish).
 If the digits are 9, 8, 5, 4 and 3, then 9+8+5+4+3=29, 2+9=11, 1+1=2.
(e) Tell them to add 4 to this number and then add the two digits together
again.
(f) Ask them to use this number to get a letter of the alphabet such that
A=1, B=2 etc.
(g) Now, tell them to come up with the name of any country in the world that
starts with this letter (get them to write it down).
(h) Then look at the second letter in the countries name and come up with an
animal (or an Australian animal) that starts with this letter (get them to write
it down).
(i) Then say, "the only trouble is that there are no elephants (or echidnas)
in Denmark" and watch their faces drop with amazement at your psychic powers!
How does this trick work?
This trick works for the same reason that the one above works - ‘digital
roots’. The country and animal part is just a bit of window dressing ... you
will see immediately how this part of the trick works after you do it a couple
of times!
3. THE ULTIMATE MISSING NUMBER TRICK.
This trick is a bit more difficult then number 1 above, but once you discover
'the secret' and once you have practised this trick a few times (perhaps using
pen and paper to begin with) you'll find it quite easy!
(a) Ask someone to write on a piece of paper (so you can’t see it) a large
number (I suggest 5 digits to start with).
(b) Ask them to add up all the digits of the number and tell you the result.
Now, you don't need to remember this result, just continue adding the digits of
the number that they tell you until you get a single digit 1 to 9 only. e.g. for
29, 2+9=11, 1+1=2, just remember 2! Call this number N.
(c) Then tell them (trying to seem like you are making these numbers up as
you go) to add 6543 and write down the result. Then subtract 567 and write down
this result. You can also continue and ask them to add or subtract other numbers
like 432. Once you discover the 'secret' of this trick you'll see that many
other numbers can be 'safely' added or subtracted and the trick still works!
(d) Now, as an option, you can let them choose which of the above results
they wish to use. But whatever, ask them to add up the digits of the number and
satisfy themselves that it is not the same as before!
(e) Ask them to circle any digit in the number selected except zero.
(f) They can then read out (slowly), all the other digits in random order.
And you will tell them what the digit is that they circled.
(g) To find the missing digit, simply add up all the digits that they give
you - repeatedly - until a single digit 1 to 9 is obtained. If this value is the
same as the number N (see b. above), then the number they circled was 9.
Otherwise, subtract this value from N. If this result is positive this is the
number they circled! If negative, add 9 to the value and this is the number
circled! e.g. If the digits are 9, 8, 8, and 4 then 9+8+8+4=29, 2+9=11, 1+1=2,
If N=5, then 5-2=3 Therefore the number circled was 3. If N=1, then 1-2=-1,
-1+9=8, the number circled was 8.
How does this trick work?
This trick works for the same reason that the first 'missing number trick'
works - ‘digital roots’.
4. MENTAL MATHS AND NOT-SO-MENTAL MATHS.
Here I'm going to explore some of the ways that 'digital roots' can be used
in mental arithmetic. Perhaps you could use it at school (as a teacher or
student) or at home to amuse yourself or the kids. Whatever, I find these
techniques fascinating and I only wish I knew about them when I was at school! I
should explain, first up, that what we are using here is the 'additive digital
root' or 'digit sum'. Which is, of course, where you add the digits. There is
also the 'multiplicative digital root' where you multiply the digits - however,
I would suggest that if the same 'rules' were to apply - ALL multiplicative
digital roots would be ZERO! In any case, just like 'perfect numbers', 'happy
numbers' and 'vampire numbers' and other weird and wonderful things that
mathematicians come up with, I'm yet to find ANY sort of use for multiplicative
digital roots! If you'd like to find out more about this and other 'absolutely
useless' numbers just go to - mathworld.wolfram.com. I am also going
to explore other forms of 'digital roots'. One, which I call the 'true digital
root' or 9's digital root and others I call the 3's digital root and the
'alternating digital root' or 11's digital root (I don't know if anyone else has
come up with this before, but a quick search of the internet suggests not).
(a) The nine times table... The first thing you'll discover about
digital roots is that if it equals 9 then the number is divisible by 9. Let's
see: 9, 1+8=9, 2+7=9, 3+6=9 ... But what about 9+9=18, don't forget we need to
keep going until we have only a single digit. So 9+9=18, 1+8=9 OK? Well, I don't
know about you, but the way I did my nine times table was to multiply by ten and
then subtract. i.e. 9x7 = 70-7 = 63. But once you know that the two digits of
the number MUST add to 9 it becomes MUCH easier! Try it and see. In fact, using
this technique, your 9 times table becomes almost as easy as the 11 times table!
Here's another fact that will help you with your 9 times table. Any number N
multiplied by nine, if you subtract the units digit of N from 10 this will equal
the units digit of the result. e.g. 8 x 9 = 72, 10-8=2, note the unit digit of
the result is 2. Try 12 x 9 = 108, 10-2=8, units digit of result is 8! This fact
always works except when the units digit of N is 0, then the result units digit
will also be 0.
We can use this fact to help us multiply all numbers from 11 to 99 by 9. Of
course you could simply use long multiplication or multiply by 10 and subtract
but you might find this next technique easier. If multiplying N x 9, take the
tens digit of N and add 1. Subtract this value from N, this is the first part of
the answer. The final units digit is worked out as above. OK, let's try 12 x 9,
1+1=2, 12-2=10, 10-2=8, result is 108. Get it? Another one, 63 x 9, 6+1=7,
63-7=56, 10-3=7, answer 567. How about 99 x 9 = 891 - did you get this? Of
course there's the special case of 0. It's best to remove the 0, multiply by 9
and then add the 0 to the result. i.e. for 70 x 9, 7x9=63, answer 630.
If you know your nine times table up to 5x9=45 but are having trouble with
6x9 up to 9x9 then here's a little curiosity that might help! Just subtract the
number from eleven, multiply that by 9 and swap the digits around (e.g. switch
the tens and units digits). Let's see? 8x9, 11-8=3, 3x9=27, therefore 8x9=72
easy! Again, 7x9, 11-7=4, 4x9=36 then 7x9=63 right?
Finally, if you've forgotten your 9 times table just enter on a calculator
(minimum 9 digit calculator is required) 102030405 and multiply by 9, the answer
is 918273645. Get it? 9, 18, 27, 36, 45. Then reverse the digits. 54, 63, 72, 81
and 90 (i.e. imagine there's a leading zero). For other interesting tricks on a
calculator see: fun
and games on a calculator below.
(b) Divisibility by nine and remainders... You may wonder why
divisibility tests are important. If you wish to be quick and efficient in maths
then recognising divisibility is important when simplifying fractions,
simplifying or solving algebraic equations and for pattern recognition...plus
more! I think most people know that any number divisible by 2 will end in
0,2,4,6,8 (even numbers), divisible by 5 will end in 0 or 5 and divisible by 10
will end in 0. And, with a little bit of thought, you'll probably be able to
work out the remainder of any number divided by 2, 5 or 10. But what about other
numbers? Digital roots, once again, allow us to quickly work out, not only, if a
number is divisible by 9 but also the remainder - if necessary. Let's try the
number 3644. 3+6+4+4=17, 1+7=8. This number is NOT exactly divisible by 9, it
would have a remainder of 8. In fact I can also tell you that 3645 is the next
number divisible by 9 because 8+1=9. And that 3636 is the prior number divisible
by 9 (just subtract 8). You should also note that any number divisible by 9 has
a digital root of 9 - the remainder is 0 not 9 in this case. Now, for the 'true
digital root' or 9's digital root. This method makes it quicker and easier to
work out the remainder or divisibility of a number by 9, particularly if you
have a pen and paper handy and can write down the number and cross off digits.
The rule is simple - 'any digit which is nine is crossed off and replaced by
zero'. You can even extend this further by saying any combination of digits that
sum to 9, 18, 27 etc. can also be crossed off! I can now write a number like
1234567892 on paper and within a few seconds tell you that this number has a
remainder of 2 if divided by 9. How? First cross off the 9, then 1+8, 2+7, 3+6,
4+5 and all you have left is 2. Or, if you prefer, as soon as the sum equals or
exceeds 9 - subtract 9 (or add the two digits) and continue. Remember, with this
method, you can never be left with 9 because it is simply crossed off and
replaced with zero - automatically giving you the correct remainder!
In fact, you should never have to add ANY sums bigger than 8+8=16, because
16-9 or 1+6=7. You can simply continue with 7 added to the next digit etc. For
example with 567862. 5+6=11, 1+1=2, 2+7=9 (becomes 0), 8+6=14, 1+4=5, 5+2=7. Or
maybe it's easier with, 5+6+7=18 (becomes 0), 8+6+2=16, 1+6=7. You decide!
Finally, after first learning about digital roots, I wondered how useful
they'd be for solving problems. Then I came across a question on an ACER
scholarship test, which read: 'In Russia a calendar was introduced in 1923 in
which all years had 365 days, except those which, when divided by 9, had either
2 or 6 as a remainder. These were given an extra day (leap years). Which of the
following was a leap year in Russia? A. 1929 B. 1934 C. 1936 D. 1937.' Well, I
could almost see the answer 'pop out' at me! D. By-the-way, as far as I'm aware,
this question is not entirely factual. The Russians did devise a system, like
this, however to work out which century years (1900, 2000, 2100 etc.) would be a
leap year which was more accurate than the Gregorian calendar we use today! e.g.
the Russian leap years would be in 2000, 2400, 2900, 3300, 3800 ... By-the-way,
if you'd like more information about ACER or ITSA scholarship tests - click here.
(c) Divisibility by three and remainders... I'm sure that anyone can
recognise that 3 divides into 9 exactly. So, if we divide the digital root by 3
we will get the remainder. If that remainder is zero then the number is
divisible by 3, otherwise we will get 1 or 2. Let's try the number 1416.
1+4+1+6=12. 1+2=3. 3/3=1 with no remainder! Again, there's a simplier way of
working this out. Obtaining what I call the 3's digital root. In this case you
cross out any digit that is 3, 6 or 9. And any combination of digits that sum to
3, 6, 9, 12 etc. Let's try the number<PHONE_NUMBER>. Cross off 3, 6. Also 4+8, 5+4,
1+2. You are left with 5+2. 7/3 = 2 with 1 remainder. Simple. Or, if you prefer,
cross off 3, 6 or 9. Replace both 4 and 7 with 1's and replace both 5 and 8 with
2's (the remainders if divided by 3). Then cross off any pairs of 1 and 2, then
simply add up any 1's or 2's remaining - divide that by 3 and bingo!
Finally, out of interest, there is another (more complex) method of testing
for divisibility by 3 - AND for finding the remainder! First add all the ODD
positioned digits (let's call it A), then add all the EVEN positioned digits
(B). If A-2B is divisible by 3 so is the original number! If it's the remainder
you're after, the result must be between -9 and +9 (a single digit), otherwise
do it again and again if necessary. Once you have a single digit, divide it by 3
to obtain a remainder. If it's negative, add 3 giving a value of positive 1 or
2. Let's try 82134682. A=2+6+3+2=13, B=8+4+1+8=21, A-2B=13-42= -29, -(9-4)= -5,
-5/3 = -1 and -2 remaining, -2+3=1. The number has a remainder of 1 when divided
by 3! Let's try another, 213468. A=1+4+8=13, B=2+3+6=11, A-2B= 13-22= -9. This
number is exactly divisible by 3. One interesting observation about this method
is that it implies that any two digit number where one digit is twice the other
digit will ALWAYS be divisible by three. Let's see - 12, 21, 24, 42, 36, 63, 48
and 84 - all divisible by three! It also implies that any three digit number
where the digits are the same will also be divisible by three. 111, 222, 333 ...
and 999 are all divisible by three!
(d) Divisibility by eleven and remainders... To test whether a number
is divisible by 11 or to get the remainder, we need to find, what I call, the
'alternating digital root' or the 11's digital root. Start by doing what we did
with the second method for divisibility by 3. Add up all the ODD positioned
digits (A), then add up all the EVEN positioned digits (B). Subtract A-B, stop
if the result is between -9 and +10 (you can stop earlier if any result is
exactly divisible by 11 or you can determine the remainder) , otherwise do it
again and again if necessary. Finally, if the result is zero or positive that is
the remainder when divided by 11. If the result is negative, add 11 and that
becomes the remainder (from this you will see that if the result is -1, adding
11 will give a remainder of 10. If the remainder is zero then the original
number is divisible by 11. Please note, if the remainder is required the SIGN of
each result is important and must flow through the calculations correctly! e.g.
Let's try 567862. A=2+8+6=16. B=6+7+5=18. A-B=16-18=-2. The remainder, if
divided by 11, is -2+11=9. Again, methods can be used to simplify the procedure.
First, you can cross off any SAME two digits in odd and even positions. You can
go further and cross off any combination of odd or even positioned digits which
sum to 11, 22, 33 etc. Or, if you prefer, as soon as the sum equals or exceeds
11 - subtract 11 and continue.
Just as with the test above for divisibility by 3, you should be able to make
some interesting observations about numbers divisible by 11. With the A-B
formula, any two digit number where the digits are the same will be divisible by
11. e.g. 11, 22, 33... (pretty obvious). But how about numbers like, 123321 or
1234554321 or<PHONE_NUMBER>87654321? Test them and see.
Note, if you are only interested in testing for divisibility by 11 and NOT
the remainder then it doesn't matter whether you do A-B or B-A ... you can just
ignore the sign anyway as long as the result is zero! If however, you wish to
find the remainder but have forgotten whether it is evens from odds or odds from
evens just think of the number 12. when divided by 11 the remainder is 1...which
is 2-1 (i.e. evens from odds). If you do it the opposite way 1-2= -1, the
remainder is -1+11= 10 (obviously wrong). By-the-way, I have called this the
'alternating digital root' because you are effectively adding the unit's digit
and then subtracting the ten's digit and adding the hundred's digit and so on.
Get it?
How does this all work?
Sorry, I'll be posting a full explaination (with proofs) later.
5. MENTAL AS ANYTHING (MORE MENTAL MATHS).
(a) The six, seven and eight times table... I think most people have
difficulty learning (and remembering) their 6, 7 and 8 times tables. Note, the
'trick' for the 9 times table is discussed above. Since we really only need to
deal with products involving these three numbers, all you need to remember is
6x6, 6x7, 6x8, 7x7, 7x8 and 8x8 ... that's all! Here's a trick to help you
remember. Let's take 7x8. Subtract 7 from 10 = 3 and 8 from 10 = 2. Now, 7-2 or
8-3 = 5 (that's your tens digit) and 2x3=6 (that's your units digit) i.e. 56.
Let's try 6x8. 10-6 = 4, 10-8 = 2, 8-4 or 6-2 = 4, 4x2=8, answer 48. Doing 6x7
is a little bit more difficult. 10-6=4, 10-7=3, 6-3 or 7-4 = 3 and 4x3=12.
Therefore 30+12=42. Squaring 6, 7 or 8 (6x6, 7x7 or 8x8) is even easiler. With
6x6, 10-6=4, 6-4=2, 4x4=16, 20+16=36. With 7x7, 10-7=3, 7-3=4 and 3x3=9, answer
49. With 8x8, 10-8=2, 8-2=6, 2x2=4, answer 64. Alternatively, instead of doing
10-8=2 and 8-2=6, use 8+8 or 8x2 = 16 and take the units digit (i.e. subtract
10).
P.S. I'm not sure how 'practical' the above method really is, it does however
provide an interesting introduction to (b) below. A more practical method might
be to get the 5 times value and add. e.g. 6x6 = 5x6+6 = 36. 7x8 = 8x5+16 = 56.
etc.
(b) Multiplying numbers between 11 and 19... Now, to do this in your
head, we are going to use a similar technique to that in (a) above. As long as
you know your times tables and can add some simple sums you'll be able to do
this - with practice! First let's try 12x13. 12-10=2 and 13-10=3 (i.e. just take
the units digits). Either add 13+2 or 12+3 = 15 (this is the tens digit = 150).
Multiply 2x3 = 6 (this is the units). Add 150+6 = 156 is the answer. Let's try
17x18. Add 17+8 or 18+7 = 25. Multiply 8x7 = 56. Add 250+56 = 306 is the answer.
How about squaring numbers between 13 and 19...easy! Let's do 16 squared.
16+6=22, 6x6=36, then 220+36 = 256 is the answer!
P.S. Once you have mastered doing this in you head, you will then be able to
multiply any numbers between 0 and 20 in your head. But what about single digit
(2..9) multiplied by double digit numbers? Easy. You can simply use long
multiplication! Here's how. Try 8x19 = 8x9 + 80 = 152. Try 6x14 = 6x4 + 60 = 84.
(c) Multiplying any two digit number by 11... Any two digit number (10
to 99) can be multiplied by 11. Simply by adding the digits together and placing
this in the tens column, whilst the tens digit goes in the hundred's column and
the units digits remains. e.g. Let's try 45x11 = 4(4+5)5 = 495. 32x11 = 3(3+2)2
= 352. 65x11= 6(6+5)5 = 715. 99x11 = 9(9+9)9 = 1089. Pretty simple eh?
(d) Dividing by 9... Any two digit number (10 to 99) can be divided by
9, the result is simply the tens digit plus the sum of the digits as the
remainder. If the remainder is 9 or greater divide it by 9 and add the result to
the previous one. e.g. divide 71 by 9. result is 7 with 7+1=8 remainder = 7r8 =
7.8888.... 84 divided by 9 = 8 with 8+4=12 remainder, since 9 divides into 12
once with 3 (1+2) remaining the answer is 9r3 = 9.3333.... 97 divided by 9 =
9r16 = 10r7. For 3 digit numbers (100...999) the result is the hundred's digit
added to the tens with the sum of digits as the remainder. Again if the
remainder is 9 or greater divide by 9 again. e.g. 123 divided by 9 = 12+1=13
with remainder 1+2+3=6, 13r6 = 13.6666.... 517 divided by 9 = 51+5=56 remainder
5+1+7=13 = 57r4 = 57.4444.... Larger numbers can be divided by 9 simply by added
the higher digit to the next lower repeatedly! And, summing the digits provides
the remainder...if the remainder is greater than 9 divide this by 9 again etc.
e.g divide 1245 by 9 the result is 124+10=134, 134+3= 137. With remainder 7+5 =
12. 137r12 = 138r3 = 138.3333.... Of course, it get's harder when digit sums
become greater than 9. e.g. 6782 divided by 9. 6+7=13, 13+8=21, 21+2=23. Answer:
600+130+21= 751 and 23 remaining = 753r5.
(e) Multiplying numbers between 91 and 109... Let's start with numbers
between 101 and 109, this is even easier than multiplying numbers between 11 and
19! First let's try 102x103. 102-100=2 and 103-100=3 (i.e. just take the units
digits). Either add 103+2 or 102+3 = 105 (this becomes the first 3 digits of the
answer). Multiply 2x3 = 6 (this is the last 2 digits of the answer). e.g.
102x103=10506. Let's try 107x108. Add 107+8 or 108+7 = 115. Multiply 7x8 = 56.
11556 is the answer. How about squaring numbers between 101 and 109...easy!
Let's do 106 squared. 106+6=112, 6x6=36. 11236 is the answer!
Multiplying numbers between 91 and 99 is almost as easy. Let's try 96x98.
100-96=4, 100-98=2, then either subtract 96-2 or 98-4 = 94 (this is the first 2
digits of the answer). Then 4x2=8 (is the last 2 digits of the answer). e.g.
98x96=9408. Squaring is easy. 91 squared is 91-9=82. 9x9=81, answer 8281.
The hardest thing to do is to multiply a number less than 100 (91..99) by a
number greater than 100 (101..109). Let's try 92x104, 100-92=8, 104-100=4, 92+4
or 104-8 = 96. Then subtract 8x4=32 from 9600 = 9568 is the answer. It is easier
with numbers of equal distance from 100. e.g. 95x105, 100-95=5, 105-100=5, 95+5
or 105-5 =100, subtract 10000-5x5= 9975. Easy?
How does this all work?
Sorry, I'll be posting a full explaination (with proofs) later.
6.
(a) Combining divisibility tests... It should be pretty obvious that
tests for other numbers can be obtained by combining divisibility tests. For
example to test for divisibility by six. Simply test for divisibility by two and
three (because 2x3=6). But what about divisibility by four? We know that the
number must first be divisible by two (because 2x2=4). We could then divide the
number by two and check that the result is even (last digit 0, 2, 4, 6 or 8).
That's one way! However, we also know that 100 divided by 4 is 25. Therefore if
the last two digits can be divided by four - so can the number! More
specifically, if the tens digit times 2 plus the units digit is divisible by 4
so is the number. So now we can use this test and the test for three to test if
a number is divisible by 12 (because 3x4=12). But what about divisibility by
eight? Well, the number must be divisible by two (even) and the number must be
divisible by four. We could divide the number by two and then test if the number
is divisible by four (because 2x4=8), right? However, we also know that 1000
divided by 8 is 125. Therefore the last three digits must be divisible by eight!
More specifically, if the hundreds digit times 4 plus the tens digit times 2
plus the units digit is divisible by 8 so is the number.
(b) Other divisibility tests... We can see by (a) above that most
divisibility tests are now covered. The exception being prime numbers such as 7,
13, 17 ... So, here's the trick for divisibility by prime numbers (or multiples
of). First find the first multiple of the number (let's call it N) that ends in
9 or 1 (e.g. 9, 11, 19, 21, 29...). Second, round up or down the number to the
nearest multiple of ten (10, 20, 30...). Now your multiplying contant (let's
call it K) becomes the tens digit (1, 2, 3...). If you rounded up it is positive
(for add), if you rounded down it is negative (for subtract). Now take the
number you wish to test for divisibility and multiply the units digit by K. This
value is then added to the tens column or subtracted if K is negative. If the
number that results is divisible by the number N then so is the original number!
Of course, by logical extension, this process can be repeated until you
recognize a number that is divisible by N.
Let's see if we can use this method to find a divisibility test for 7. First,
multiply 7 until we have a number ending in 9 or 1. OK. 7, 14, 21. Now, we need
to round this down to 20, so K = -2. Lets' test it. Try 3199. 319 - 2x9 = 301.
30 - 2 = 28. 28 is divisible by 7 so is 3199. Note, we could have gone further
with 28. As 2-16 = -14. And 1-8 = -7. The factor K = -2 is also a test for
divisibility by 21. The difference, being that we need to check if the result is
divisible by 21 rather than 7! Let's try 9576. 957 - 2x6 = 945. 94 - 2x5 = 84. 8
- 2x4 = 0. The number 9576 is divisible by 21 (and 7 and 3 in fact). A couple of
very interesting observations can be made. Firstly, all two digit numbers where
the tens digit is twice the units digit (21, 42, 63 and 84) are all divisible by
21 (and by default 7 and 3). You should also notice the similarity of this test
with the second test for divisibility by 3 above. In fact, this test can also be
used to test for divisiblity by 3!
Alternatively, when testing for divisibility of 7, since 7x7 = 49, we can use
K=+5. Let's try this with 294. 29 + 5x4 = 49. 49 is divisible by 7 and so is
294! Interestingly, we can't go any further with 49, since 4 + 5x9 = 49!
Note, despite what some books may tell you, tests for divisiblity by seven
are not very 'practical'. I would recommend simply dividing the number by seven
(you can discard the result if you're only interested in the remainder) and if
the final remainder is zero then the number is divisible by seven! If you are
using pen and paper then the number can be simplified first by crossing out 7's
or any 2 digit multiple of 7 (make them 0), changing 8's to 1 and 9's to 2 (i.e.
the remainders when divided by 7) and, since 7 divides into 1001, 10010, ...
exactly, subtract one digit from another which are separated by 2 digits.
Remember any leading or trailing zeros can be removed. e.g. Try 59633, cross off
63 = 59003, make 9 a 2 = 52003, subtract 3 from 2 = 49000, 49 is divisible by 7
so is 59633. Note, after obtaining 59003, the result could be obtained easier by
taking the 3 from the 9 = 56000, 56 is divisible by 7! Also, since 1001 is a
multiple of 7, K= -100. Which is the same as subtracting it from the 4th digit!
How about a divisibility test for 13? First 13, 26, 39. Round up to 40,
therefore K = +4. Testing it, let's try 585. 58 + 4x5 = 78. 7 + 4x8 = 39. 39 is
divisible by 13 and so is 585. What's real interesting about this method is that
if testing for divisibility by 3 or 9, the value of K = +1. In other words, you
repeatedly add the units digit to the tens column. If you continue to do this
you end up with the digital root of the number! The value of K for other prime
numbers is; K= -1 for 11. K= -5 for 17. K = +2 for 19. K= +7 for 23. Note, it's
pretty easy to work out the values for K as required. i.e. There's no need to
memorize them!
Finally, you may wish to find a negative value for K rather than use a
positive value (the number reduces quicker and therefore the answer is found
quicker). Simply subtract the number N from K. e.g. for N=3 and K=+1, the
alternate value for K is 1-3 = -2. Try it and see if it works! To convert a
negative K to a positive we can use N + K. e.g. for N=7 and K= -2, the alternate
value of K is +5. For N=9, we can also use K= -8. For N=11, K= +10. etc. Note,
with K= +10 for divisibility by 11, we can simply take the units digit and add
it to the thousands column, if the resulting number is divisible by 11 so is the
original number! Let's try 517, (5+7)1 = 121 we could stop here, but if we do it
again (1+1)2 = 22. Clearly divisible by 11. Note, you can't go any further with
this method (K= +10) once you have a 2 digit number. Of course, you could always
continue with K= -1.
(b) Using divisibility tests to check for prime numbers... To test if
a number is prime (divisible by itself and one only), you only need to test if
it is divisible by other prime numbers up to the square root of the number you
are testing. So, let's say we'd like to find all the prime numbers up to 100. We
need to know all the prime numbers up to 10 (i.e. the square root of 100). They
are 2, 3, 5 and 7. Now we know that: (a) All even numbers greater than two can
be eliminated (they divide by two). (b) Starting from 9 we can eliminate every
third odd number (e.g. 9, 15, 21 ...) as they are all divisible by three. Or, if
you prefer the digital root of these numbers is 3, 6 or 9. (c) All other numbers
ending in 5 can also be eliminated as they divide by five. (d) Finally, any
number divisible by 7 can be removed. There is only three numbers here, 7x7= 49,
7x11= 77 and 7x13= 91. (Note, 11 and 13 are the next two prime numbers).
You can continue, if you wish, testing for prime numbers up to 169 (13x13)
adding the test for divisiblity by 11. And, as long as you know that 169 is not
a prime number, you can continue until 221 (13x17). You can go further using
divisibility tests for 13, 17 and 19 etc. Finally, to generate prime numbers on
your computer take a look at the QBASIC program on our puzzle page.
How does this all work?
Sorry, I'll be posting a full explaination (with proofs) later.
7. FUN AND GAMES ON A CALCULATOR.
Here we are going to explore some of the things you can do on a calculator.
Things that you may not have thought about. A simple add, subtract, multiply and
divide calculator is needed. For the advanced exercises you will need a modern
scientific calculator. I would suggest that if your calculator is more than a
few years old you might wish to update to a new 2 line type (Casio FX-82 or
FX-100, Texas TI-30 or Sharp EL-531). They are now commonly used in primary and
junior secondary schools and cost as little as AUS$16 and are well worth it! You
may also wish to use the calculator on your PC. In Windows, look under
'Accessories' - either an ordinary or scientific calculator can be selected.
(a) Digital roots on a calculator ... You might think that to work out
the digital root of a number you would need to add each individual digit and
then repeat the process until a single digit is obtained - BUT NO! All you need
do is to enter the entire number on the calculator and divide it by nine. Then
look at the digit to the right of the decimal point (d.p.) that represents the
remainder of the number when divided by nine! Note, if there is nothing to the
right of the d.p. then the number is exactly divisible by nine and the digital
root is nine. Also ensure that at least two digits to the right of the d.p. are
shown because the calculator may round up the number giving you an incorrect
result. Finally, make sure that the number is NOT displayed in scientific
notation!
To try this out, let's see if we can solve the problem in 4(b) above. Divide
1929 by 9 = 214.333.. The digital root or remainder when divided by 9 is 3.
Divide 1934 by 9 = 214.888..9 Divide 1936 by 9 = 215.111.. Divide 1937 by 9 =
215.222.. The remainder or digital root is 2, therefore 1937 is a leap year -
problem solved!
(b) Alternating digital roots on a calculator ... This is simply the
remainder when a number is divided by 11. So, first divide your number by 11.
Then look at the digit to the right of the decimal point (d.p.) and ADD ONE -
that represents the remainder of the number when divided by eleven! Of course,
if there is nothing to the right of the d.p. then the number is exactly
divisible by 11 and the alternating digital root or remainder is zero.
To try this out let's use the example above. 567862 when divided by 11 gives
51623.8181... Therefore the remainder when divided by 11 is 8+1 = 9.
(c) Finding remainders on a calculator ... This is something that most
calculators don't do well at all! Special case solutions are shown in (a) and
(b) above, but what about generally finding remainders? On your computer's
scientific calculator (see 'Accessories' and select 'View..Scientific') you will
find a function called 'Mod' which is short for Modulus. Enter '11 Mod 9' and
the answer is 2 etc. On a normal calculator you can do the division, then remove
the integer part (i.e everything on the left of the d.p.) by subtracting it and
then multiplying by the divisor. Unfortunately, this is all very clumsy but is
made easier if you use a 2-line calculator such as the Casio FX-82. This
calculator also allows you to display the result as a fraction (press a.b/c) in
which case the numerator is the remainder (if, and only if) the denominator is
the divisor! HINT, HINT, one might think that a smart calculator manufacture
would provide the 'Mod' function given that it's commonly available on your
computer! I've just spoken to Casio about this (by email) and apparently only
the French version of their calculator has this function. The Australian version
doesn't...seems the Education Department has to request it!
TO BE CONTINUED
8. COMPUTER MATHS (OR 2 FINGERED MATHS)
UNDER CONSTRUCTION
9. PROBLEM SOLVING MADE EASY (WELL, EASIER ANYWAY)
UNDER CONSTRUCTION
10. FEEDBACK (your comments here).
Kjartan Poskitt author of the book
'Numbers - the key to the universe' says: 'Nice to hear from you - I've
never seen as many variations of the digital root thing before in one place!
Ingenious.'
Bill Handley author of the
book 'Speed Mathematics' says: 'Hi Peter, Thank you for your email...I
looked at your website and found it good and informative. I have always been
intrigued by mathematical shortcuts and still can't resist checking out any that
are offered.'
Priyank, India. I saw your website, I want to ask you a trick to
multiply numbers between 20 to 999. If you know more tricks then please send me
... I am waiting for your reply. REPLY: The trick to multiplying numbers up
to 999 is to USE A CALCULATOR! Only joking, I will be showing you how to
multiply numbers up to 99 and slightly beyond in your head.
Why don't you book mark this page and come back again and check for more
interesting maths tricks and tips .. they may even save your life one day -
perhaps in a maths test or perhaps from boredom!
If you have any tricks or tips or short-cuts that you think should be added
to this page or wish to ask a question, why not email me at<EMAIL_ADDRESS>© Copyright by Procon Technology,
PO Box 655, Mount Waverley 3149, Melbourne, Australia.
In Australia Phone:
1300304125 (local call cost) or 03-98306288 FAX: 03-98306481.
International
Phone: +61-3-98306288 FAX: +61-3-98306481. Created by: Peter E.
King.


package gridfs
- Alphabetic
- By Inheritance
- gridfs
- AnyRef
- Any
- Hide All
- Show All
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Type Members
-
trait
AsyncInputStream
extends AnyRef
The Async Input Stream interface represents some asynchronous input stream of bytes.
The Async Input Stream interface represents some asynchronous input stream of bytes.
See the org.mongodb.scala.gridfs.helpers package for adapters that create an
AsyncInputStream
- Since
1.2
-
trait
AsyncOutputStream
extends AnyRef
The Async Output Stream interface represents some asynchronous output stream of bytes.
The Async Output Stream interface represents some asynchronous output stream of bytes.
See the org.mongodb.scala.gridfs.helpers package for adapters that create an
AsyncOutputStream
- Since
1.2
-
case class
GridFSBucket
(wrapped: com.mongodb.async.client.gridfs.GridFSBucket) extends Product with Serializable
Represents a GridFS Bucket
Represents a GridFS Bucket
- Since
1.2
-
type
GridFSDownloadOptions = com.mongodb.client.gridfs.model.GridFSDownloadOptions
The GridFS download by name options
The GridFS download by name options
Controls the selection of the revision to download
-
case class
GridFSDownloadStream
(wrapped: com.mongodb.async.client.gridfs.GridFSDownloadStream) extends AsyncInputStream with Product with Serializable
A GridFS InputStream for downloading data from GridFS
A GridFS InputStream for downloading data from GridFS
Provides the
GridFSFile
for the file to being downloaded as well as theread
methods of aAsyncInputStream
- Since
1.2
-
type
GridFSFile = com.mongodb.client.gridfs.model.GridFSFile
The GridFSFile
-
case class
GridFSFindObservable
(wrapped: GridFSFindIterable) extends Observable[GridFSFile] with Product with Serializable
Observable representing the GridFS Files Collection.
Observable representing the GridFS Files Collection.
- Since
1.2
-
type
GridFSUploadOptions = com.mongodb.client.gridfs.model.GridFSUploadOptions
GridFS upload options
GridFS upload options
Customizable options used when uploading files into GridFS
-
case class
GridFSUploadStream
(wrapped: com.mongodb.async.client.gridfs.GridFSUploadStream) extends AsyncOutputStream with Product with Serializable
A GridFS OutputStream for uploading data into GridFS
A GridFS OutputStream for uploading data into GridFS
Provides the id for the file to be uploaded as well as the write methods of a AsyncOutputStream
- Since
1.2
- implicit class JavaAsyncInputStreamToScala extends AsyncInputStream
- implicit class JavaAsyncOutputStreamToScala extends AsyncOutputStream
-
type
MongoGridFSException = com.mongodb.MongoGridFSException
An exception indicating that a failure occurred in GridFS.
- implicit class ScalaAsyncInputStreamToJava extends com.mongodb.async.client.gridfs.AsyncInputStream
- implicit class ScalaAsyncOutputStreamToJava extends com.mongodb.async.client.gridfs.AsyncOutputStream
Value Members
-
object
GridFSBucket
extends Serializable
A factory for GridFSBucket instances.
A factory for GridFSBucket instances.
- Since
1.2
This is the documentation for the MongoDB Scala driver.
Driver structure
The mongodb scala driver.
To get started you need a MongoClient instance, either from a connection string or via a org.mongodb.scala.MongoClientSettings.
Notable packages include:


Find Week 12 waiver pickups, fantasy sleepers using snap counts
Fantasy football owners should consider more than targets and carries to find waiver pickups and sleepers for Week 12. Snap counts can help show the true usage a player might get going forward. We have notes for all 32 teams.
by @billyheyenAn inquisitive mind might ask where Ty Johnson is in the photo at the top of the article. A fair question. Once Johnson was cleared for concussion protocol, everyone expected him to resume his role in the Lions' backfield. But just as your fantasy scoreboard surely showed you, our snap counts showed us the same thing: Johnson was an afterthought for Detroitand very well couldbe again in Week 12. Instead, Bo Scarbroughsaw more work than Johnson (who was nearly even with J.D. McKissic), with Scarbrough being a potential waiver wire add this week.
There was no way to see Scarbrough coming. He'd been activated from the practice squad only on Saturday. The snap count report wouldn't have saved you last week, asScarbrough hadn't taken an NFL snap this season before Sunday. But we will try to save you from missing out on other things like that.
WEEK 12 NON-PPR RANKINGS:
Quarterback | Running back | Wide receiver | Tight end | D/ST | Kicker
There are other running back situations taking new shapes. In Denver, Phillip Lindsay might be taking over much like Devin Singletary did a few weeks ago. In Washington, Derrius Guice is back while Wendell Smallwood made a surprisingly large impression in his Week 11 playing time.
WEEK 12: Top waiver pickups
Wide receiver is actually pretty quiet this week. Both Tennessee and Green Bay, which have had two of the more fluid WR situations in the league this season, were on bye in Week 11 and will bear watching when they come back in Week 12.
WEEK 12 PPR RANKINGS: Running back | Wide receiver | Tight end
There were two large tight end developments in Week 11. The Rams played Tyler Higbee way more than Gerald Everett, although Higbee didn't do anything. The Buccaneers played Cameron Brate a lot more than O.J. Howard, and Brate caught 10 passes. That comparison shows you everything you need to know -- playing time isn't the magic formula, but it can back up what already happened.
Ideally, we won't get blindsided by another Scarbrough-esque performance this season. It's one thing not to see a strong performance coming;it's another not to see any playing time coming at all. Hopefully our team-by-team breakdown will prevent any such surprises.
Note: Snap counts via pro-football-reference.com.
#1
Arizona Cardinals
RB snaps (out of 69):Kenyan Drake (61), David Johnson (9)
No idea why they keep having DJ active if he's obviously not healthy enough to really play. As soon as Chase Edmonds (hamstring) returns, Johnson could get phased out entirely if he's not healthy. If you're really in need of production the next two weeks to squeak into the playoffs and need to drop someone, Johnson is a legit candidate, although perhaps the Cardinals are just waiting until after their Week 12 bye to give him regular touches again.
#2
Atlanta Falcons
TE snaps (out of 65):Luke Stocker (43), Jaeden Graham (34)
Graham caught both of his targets for 23 yards, while Stocker caught his lone target for 18 yards. With the Buccaneers up next for these two, one could have a good game against a TE-friendly defense, but it's hard to say which.
Also of note: Brian Hill was on the field for 39 offensive plays, compared to 14 for Kenjon Barner and 12 for Qadree Ollison.
#3
Baltimore Ravens
TE snaps (out of 72):Nick Boyle (55), Hayden Hurst (30), Mark Andrews (25)
This has sort of been the case all season --and the blowout didn't help us really figure anything out --but that's a massive gap between Boyle and Andrews. Obviously Andrews comes in the game to catch the ball, so we're not worried about him. It's just about the only fascinating takeaway from a blowout that skews all the playing time numers.
#4
Buffalo Bills
TE snaps (out of 72):Dawson Knox (51), Tyler Kroft (24), Lee Smith (7)
After it looked like Kroft was making this job his again, the rookie Knox reasserted himself. Knox caught two-of-threetargets for 32 yards and a touchdown, and if he maintains this playing time, he could have some fantasy utility heading toward the fantasy playoffs.
#5
Carolina Panthers
At this point, we could remove the Panthers from this report and no one would notice. Ron Rivera, for all the funky stuff he does, doesn't mess with his lineups at all.
#6
Chicago Bears
WR snaps (out of 76):Allen Robinson (75), Taylor Gabriel (69), Anthony Miller (65), Javon Wims (15), Cordarrelle Patterson (2)
So with Jalen Ramsey shadowing Robinson, Gabriel saw 14 targets and Miller 11. It's hard to say that either is a great option going forward, although we've already been recommending Gabriel as a fine PPR play. The more three-WR sets in Chicago, the better for week-to-week fantasy sleepers.
#7
Cincinnati Bengals
John Ross watch
It will be rare for Bengals to hold fantasy value down the stretch, especially with Auden Tate leaving Sunday with a rough-looking neck injury. But this is a lookahead to the idea that John Ross can return from IR in Week 13 (and A.J. Green remains out). Ross was on the field for at least two-thirds of snaps in the first four games of the season.
#8
Cleveland Browns
RB snaps (out of 71):Nick Chubb (51), Kareem Hunt (39)
Chubb saw about a 10-percent decline in snap usage this week, while Hunt's remained nearly constant -- that suggests there were more plays with just Hunt on the field without Chubb. Chubb received 27 carries, though, so there's no reason to worry about him or Hunt, who had six carries and six catches on eight targets.
#9
Dallas Cowboys
WR snaps (out of 74):Michael Gallup (61), Randall Cobb (46), Amari Cooper (41), Tavon Austin (30), Ventell Bryant (4)
Cooper has been dinged up all season, and not counting Week 6 where he was injured at the outset, this is the least Cooper has played in a game. Gallup took advantage by catching nine passes for 141 yards, and Cobb also surpassed the century mark. Keep an eye on Cooper this week, and if he remains at all dinged up, Cobb is a good add.
#10
Denver Broncos
RB snaps (out of 81):Phillip Lindsay (52), Royce Freeman (24), Devontae Booker (5)
Before Sunday's game, reports were that Lindsay would get much more work than Freeman, but that didn't make tons of sense based on what we'd seen through 10 weeks. Yet that's exactly what happened. It wasthe biggest workload split between the two all year, and Lindsay had 16 carries to Freeman's eight. It's no guarantee this continues, but if it does, their values will break down much the same as they did last season.
#11
Detroit Lions
RB snaps (out of 65):Bo Scarbrough (32), Ty Johnson (19), J.D. McKissic (15)
Scarbrough came out of nowhere to be the top dog here, and against Washington in Week 12, Scarbrough will be a fantasy-relevant RB as a borderline RB2/FLEX playas long as no reports indicate otherwise.
#12
Green Bay Packers
What to watch coming off bye:
Marquez Valdes-Scantling's usage. He was the fifth-most played Green Bay receiver before the bye, but there's a chance that was attributable to snow at Lambeau Field.
#13
Houston Texans
Keke Coutee update
After not playing for two-straight weeks even with Will Fuller V (hamstring) out, Coutee was back on the field as Houston's third WR behind DeAndre Hopkins and Kenny Stills on Sunday. That could change very soon when Fuller does return, though.
#14
Indianapolis Colts
RB snaps (out of 68):Jonathan Williams (31), Nyheim Hines (24), Marlon Mack (21)
With Mack (hand) set to miss at least Thursday night, Williams will take over early-down duty (assuming Jordan Wilkins is still out because of an ankle injury). Williamsrushed for 116 yards in his playing time Sunday, so he's worth a fantasy start against Houston. Hines will be usable in PPR as he'll see about half the plays himself. If Wilkins is active, there's no telling how this backfield will shake out.
#15
Jacksonville Jaguars
Tight end situation
Nothing unusual happened here, so we'll just let you know that Josh Oliver is set to miss the rest of the season due to a back injury. With James O'Shaughnessy, Geoff Swaim, and Seth DeValve all hurt, any TE production in Jacksonsville will have to come from Nick O'Leary and Ben Koyack.
#16
Kansas City Chiefs
Backup RB snaps (out of 68):LeSean McCoy (27), Darrel Williams (12)
McCoy becomes the option to own here if Damien Williams misses time with his injury, although McCoy was being worked in early on and it truly appears Week 11 was a load management week for him.
#17
Los Angeles Chargers
WR snaps (out of 80):Keenan Allen (74), Mike Williams (71), Andre Patton (59), Jason Moore (15)
Patton continues to play a ton as the third wideout, although that hasn't necessarily translated to production. It's worth keeping an eye on with two injury-prone WRs in front of him.
#18
Los Angeles Rams
TE snaps (out of 55):Tyler Higbee (42), Gerald Everett (14)
This makes no sense. Brandin Cooks (concussion) and Robert Woods (personal) were out. Everett had 12 targets in Week 10, yet the Rams only played their second-best healthy pass-catcher on 14 plays. This gives us a ton of pause about playing Everett going forward, although we'd probably need to see another week like this to totally go away from him. If the Rams stick with their run-heavy game plan, Everett falls into the "TD-or-bust" TE camp like so many others.
#19
Miami Dolphins
RB snaps (out of 69):Kalen Ballage (53), Patrick Laird (16), Myles Gaskin (7)
Ballage picked up 17 total yards on 14 touches, yet he continues to be the leading man in this backfield. If nothing else, it's a good way for the Dolphins to tank. As long as Ballage keeps getting that many touches, he should at least be on fantasy rosters, although recommending him to start in any given week seems odd.
#20
Minnesota Vikings
TE snaps (out of 63):Kyle Rudolph (55), Irv Smith Jr. (51), Tyler Conklin (9)
Heading into the Vikings' bye, the two tight ends continue to each see the high majority of playing time. They'll see less targets coming out of the week off with Adam Thielen (hamstring) presumably back, but both will remain on the field enough to have fringe fantasy value.
#21
New England Patriots
WR snaps (out of 74):Julian Edelman (66), Mohamed Sanu (41), Phillip Dorsett (34), N'Keal Harry (32), Jakobi Meyers (19)
Dorsett left the game with a concussion, which helped boost Harry's and Meyers' snap counts. But all that excitement about Sanu never coming off the field in the previous game was met with the harsh reminder that Bill Belichick and Josh McDaniels will gameplan individually each week and that one week's usage isn't always indicative of the next week's playing time.
#22
New Orleans Saints
WR snaps (out of 70):Michael Thomas (57), Tre'Quan Smith (42), Ted Ginn Jr. (38), Krishawn Hogan (13)
Smith again played more than Ginn, but it was TGJ who caught the short-yardage touchdown. The playing time for Smith is encouraging, but he has to do something with it. Until he does, he's not worth owning.
#23
New York Giants
What to watch for coming off bye
Health and usage of Saquon Barkley.
#24
New York Jets
Ryan Griffin watch
Griffin was the most played Jets' skill position player Sunday, and he turned it into a career day of five catches for 109 yards and a touchdown. With the Jets taking on Oakland in Week 12, Griffin should remain a valuable and frequently used piece of the New York offense.
#25
Oakland Raiders
TE snaps (out of 70): Darren Waller (66), Foster Moreau (41), Derek Carrier (20)
This actually isn't Moreau's highest snap total this season, but he wastargeted inside the 10-yard line for the third time - all three of which have turned into touchdowns. He's not quite in the Dallas Goedert realm yet, but Moreau is a potentially useful backup to Darren Waller and probably would be a great fantasy option if Waller were to get hurt.
#26
Philadelphia Eagles
RB snaps (out of 75):Miles Sanders (64), Boston Scott (14)
With Jordan Howard (stinger) out, this was the Sanders show. Newly signed Jay Ajayi dressed but didn't play. Sanders and the Eagles struggled to put anything together against New England, but if Howard remains out, bet on Sanders having better days ahead.
#27
Pittsburgh Steelers
WR snaps (out of 74):James Washington (63), Johnny Holton (44), Diontae Johnson (38), Tevin Jones (36), JuJu Smith-Schuster (22)
Johnson and Smith-Schuster both sustained concussions on Thursday night. If they both miss Week 12, Washington becomes Pittsburgh's top target against Cincinnati. Holton is a deep threat and only a boom-or-bust possibility in the deepest of leagues.
#28
San Francisco 49ers
WR snaps (out of 77):Deebo Samuel (61), Kendrick Bourne (42), Emmanuel Sanders (36), Marquise Goodwin (23), Richie James (10), Dante Pettis (2)
Sanders (ribs) obviously isn't fully right, and it led to another 100-yard game for Deebo and another touchdown for Bourne. Deebo is owned in about half of leagues, but that ownership should keep rising. And oh, what a fall it's been for Pettis.
#29
Seattle Seahawks
What to watch coming off bye
Health of Tyler Lockett and playing time of Josh Gordon.
#30
Tampa Bay Buccaneers
TE snaps (out of 68):Cameron Brate (51), O.J. Howard (17)
We barely heard from Howard again after he basically handed an INT to the Saints early, and Brate went on to have 10 catches. This still seems like a fluid situation, but Brate is currently holding the edge.
#31
Tennessee Titans
What to watch coming off bye
Health of Corey Davis and Delanie Walker.
#32
Washington Redskins
RB snaps (out of 68):Wendell Smallwood (31), Derrius Guice (20), Adrian Peterson (17)
I didn't look at these numbers expecting to see Smallwood first (likely a result of garbage time), but I'm going to take encouragement out of Guice being ahead of Peterson. The Lions surrender a lot of rushing yards, so Guice should be ready to take advantage in Week 12.


A data structure usually a class that is kept of the heap.
Heap
A place in remory where a program can reference memory out of order. See stack.
Stack
A place in memory that can only be access from one side. It is called a stack because they way it works is similar to a stack of plate. Most stacks are First in, First Out or FIFO.


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Gateway
BOT
04-Jul-18 08:22 AM
[dscrdeql] <jellysmash> uuuhhhh...good to get home
[dscrdeql] <jellysmash> riding wild motorscooter
[dscrdeql] <jellysmash> peak hour traffic...OMG
[dscrdeql] <jellysmash> glad to get through it on a small motorscooter
[dscrdeql] <jellysmash> suck being in a car stuck in all that
[dscrdeql] <Cypher - Founder> morning
[dscrdeql] <jellysmash> morning @Cypher - Founder
[dscrdeql] <jellysmash> it's nighttime here in Aus
[dscrdeql] <jellysmash> but have a on me
[dscrdeql] <jellysmash> just in case that wasn't enough...here's another
[dscrdeql] <Cypher - Founder> haha thanks
[dscrdeql] <Cypher - Founder> need it
[dscrdeql] <Cypher - Founder> hehe went to sleep about 4am hehe
[dscrdeql] <jellysmash> Yea, know what it's like waking up very sleepy
[dscrdeql] <jellysmash> I can't survive much with less than about 4 hours sleep
[dscrdeql] <Cypher - Founder> no rest for the wicked as they say
[dscrdeql] <Cypher - Founder> xD
[dscrdeql] <Cypher - Founder> checking my todo list
[dscrdeql] <jellysmash> yea, wicked
[dscrdeql] <Cypher - Founder> how was your day ?
[dscrdeql] <jellysmash> ok
[dscrdeql] <jellysmash> tried debugging something and couldn't work it out
[dscrdeql] <jellysmash> I hate that
[dscrdeql] <Cypher - Founder>
[dscrdeql] <jellysmash> I'll have to sort it out tomorrow
[dscrdeql] <Cypher - Founder> oh i know that feel too well
[dscrdeql] <jellysmash> I think maybe I shojuld just reboot the server and see if that fixes it
[dscrdeql] <Cypher - Founder> the worst one is when it is a semi colon or a messed up llambda
[dscrdeql] <Cypher - Founder> but its awesome when you fix it
[dscrdeql] <Cypher - Founder>
[dscrdeql] <jellysmash> yea, well I checked the configuration, c# code, MS Dynamics layer workflows and Javascript and it all looks ok
[dscrdeql] <jellysmash> and yet on the UAT server it doesn't work properly
[dscrdeql] <jellysmash> can't say....gee it work on my PC
[dscrdeql] <jellysmash> -avatar @CowboyCrypto- Founder
[dscrdeql] <jellysmash> have you got a new avatar?
[dscrdeql] <jellysmash> that picture above looks like you're going for a job interview
[dscrdeql] <jellysmash> Did you get the job?
[dscrdeql] <jellysmash> lol....
[dscrdeql] <jellysmash> -avatar @Cypher - Founder
[dscrdeql] <jellysmash> Ok, now I got it
[dscrdeql] <jellysmash> wrong avatar....wrong person
[dscrdeql] <jellysmash> wooops...sorry
[dscrdeql] <jellysmash> Like the moving pics and avatars...really bring to life
[dscrdeql] <jellysmash> Maybe I can learn how to make mine flash a bit
[dscrdeql] <jellysmash> that'd be good
[dscrdeql] <!!! Thorth !!!> hey.....
[dscrdeql] <AndronicusBass-Founder> -avatar @AndronicusBass-Founder thats me
[dscrdeql] <!!! Thorth !!!> u drink @jellysmash coffee... and not mine
[dscrdeql] <!!! Thorth !!!>
[dscrdeql] <!!! Thorth !!!>
[dscrdeql] <!!! Thorth !!!>
[dscrdeql] <jellysmash> you look like a model
[dscrdeql] <!!! Thorth !!!> here's a hot one
[dscrdeql] <!!! Thorth !!!>
[dscrdeql] <!!! Thorth !!!>
[dscrdeql] <AndronicusBass-Founder> a hot model lol
[dscrdeql] <jellysmash> haha...hot coffees for everyone
[dscrdeql] <jellysmash> reminds me of that old tv series Hercules
[dscrdeql] <AndronicusBass-Founder> kevin sorbo
[dscrdeql] <!!! Thorth !!!> hehe :)) on AXN ... is still on.... from time to time
[dscrdeql] <AndronicusBass-Founder> i think his name was
[dscrdeql] <Cypher - Founder> jellysmash - 2018-07-04 09:40 +01:00
Maybe I can learn how to make mine flash a bit
that'd be good
[dscrdeql] <Cypher - Founder> its if you pay for discord
[dscrdeql] <AndronicusBass-Founder> i watched that when i was younger
[dscrdeql] <AndronicusBass-Founder> gif avatar
(edited)
[dscrdeql] <jellysmash> I think there was a guy before Kevin sorbo
[dscrdeql] <jellysmash> had browner hair
[dscrdeql] <jellysmash> no maybe kevin sorbo


protected
Constants (that is, variables marked static or final) are not reported.
static
final
Example:
public class A { protected Object object; // warning protected final static int MODE = 0; // constant, no warning }


GIRO (Global Ionospheric Radio Observatory) comprises records of subpeak
ionospheric characteristics, including altitude profiles of electron
density and plasma drift velocity, in the altitude range 90 km to the
peak height of the F2 layer, measured by a global ground-based network
of active high frequency (HF) radiowave remote sensing instruments,
ionosondes. The ionosonde uses stepped- or fixed-frequency probing
radio signals transmitted from the ground for propagation into ionosphere,
total reflection from an area of matching plasma density, and return to
the same or different ionosonde location for detection. The detected
echoes are evaluated for their travel time and other characteristics
such as amplitude, phase, polarization, Doppler frequency shift, and
angle of arrival. The signal travel time is commonly translated to
the virtual range to the reflecting area in the ionosphere in the
assumption of the signal propagating at the speed of light.
Stepped-frequency measurements provide adequate information to compute
true range of reflections by accounting for refractive properties of plasma.
The ionosonde designs are commonly divided in two classes, (1) a pulsed sounder
with stepped frequency that transmits short pulses to detect the echo arrival
in the time domain, and (2) a chirp-sounder that transmits a continuous
swept-frequency signal to detect its reflections in the frequency domain.
The stepped- or swept-frequency sounders produce inherently 2-dimensional
data record (frequency x travel time), ionogram. Each element of the 2D
ionogram structure holds multiple signal characteristics measured in the
ionosonde's receiver channels. Thus acquired information is processed to
detect echoes and use their attributes to derive ionospheric characteristics
along the propagation path.
The fixed-frequency measurement, while using the same concept of radio
sounding by total reflection, targets specific plasma densities in the
ionosphere, and usually provides higher Doppler frequency resolution by
transmitting pulses at the same frequency for several seconds.
Simultaneously occurring reflection points in a structured ionosphere
are identified by their different echo Doppler frequencies allowing the
computation of Doppler skymaps and plasma drift velocity.
Version:2.2.2
GIRO (Global Ionospheric Radio Observatory) comprises records of subpeak
ionospheric characteristics, including altitude profiles of electron
density and plasma drift velocity, in the altitude range 90 km to the
peak height of the F2 layer, measured by a global ground-based network
of active high frequency (HF) radiowave remote sensing instruments,
ionosondes. The ionosonde uses stepped- or fixed-frequency probing
radio signals transmitted from the ground for propagation into ionosphere,
total reflection from an area of matching plasma density, and return to
the same or different ionosonde location for detection. The detected
echoes are evaluated for their travel time and other characteristics
such as amplitude, phase, polarization, Doppler frequency shift, and
angle of arrival. The signal travel time is commonly translated to
the virtual range to the reflecting area in the ionosphere in the
assumption of the signal propagating at the speed of light.
Stepped-frequency measurements provide adequate information to compute
true range of reflections by accounting for refractive properties of plasma.
The ionosonde designs are commonly divided in two classes, (1) a pulsed sounder
with stepped frequency that transmits short pulses to detect the echo arrival
in the time domain, and (2) a chirp-sounder that transmits a continuous
swept-frequency signal to detect its reflections in the frequency domain.
The stepped- or swept-frequency sounders produce inherently 2-dimensional
data record (frequency x travel time), ionogram. Each element of the 2D
ionogram structure holds multiple signal characteristics measured in the
ionosonde's receiver channels. Thus acquired information is processed to
detect echoes and use their attributes to derive ionospheric characteristics
along the propagation path.
The fixed-frequency measurement, while using the same concept of radio
sounding by total reflection, targets specific plasma densities in the
ionosphere, and usually provides higher Doppler frequency resolution by
transmitting pulses at the same frequency for several seconds.
Simultaneously occurring reflection points in a structured ionosphere
are identified by their different echo Doppler frequencies allowing the
computation of Doppler skymaps and plasma drift velocity.
| Role | Person | |
|---|---|---|
| 1. | PrincipalInvestigator | spase://SMWG/Person/Bodo.W.Reinisch |
| 2. | DataProducer | spase://SMWG/Person/Ivan.A.Galkin |
Access to real-time data and software tools


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Daniel Fandino is a PhD student at Michigan State University. His academic interests focus on the relationship between the United States and Japan, American and East Asian popular culture and technology. He is one of the editors Assembling the Marvel Cinematic Universe: Essays on the Social, Cultural and Geopolitical Domains. His most recent academic work is a chapter entitled “Remembering Fictional History and Virtual War in Eve Online” in the edited volume Virtual Dark Tourism: Ghost Roads.


| lesson 6 Smash-and-grab |
| The expensive shops in a famous arcade near Piccadilly were just opening. |
| At this time of the morning, the arcade was almost empty. |
| Mr. Taylor, the owner of a jewellery shop was admiring a new window display. |
| Two of his assistants had been working busily since eight o'clock and had only just finished. |
| Diamond necklaces and rings had been beautifully arranged on a background of black velvet. |
| After gazing at the display for several minutes, Mr. Taylor went back into his shop. |
| The silence was suddenly broken when a large car, with its headlights on and its horn blaring, roared down the arcade. |
| It came to a stop outside the jeweller's. |
| One man stayed at the wheel while two others with black stockings over their faces jumped out and smashed the window of the shop with iron bars. |
| While this was going on, Mr. Taylor was upstairs. |
| He and his staff began throwing furniture out of the window. Chairs and tables went flying into the arcade. |
| One of the thieves was struck by a heavy statue, but he was too busy helping himself to diamonds to notice any pain. |
| The raid was all over in three minutes, for the men scrambled back into the car and it moved off at a fantastic speed. |
| Just as it was leaving, Mr. Taylor rushed out and ran after it throwing ashtrays and vases, but it was impossible to stop the thieves. |
| They had got away with thousands of pounds worth of diamonds. |


--- layout: post title: Crazy Places M Likes to Read... categories: [] tags: - emma - family status: publish type: post published: true meta: _original_post_id: '' _original_import_author: John Duprey author: ---
M starts school tomorrow. This, for me, signals the end of summer... wow.. where did the time go? I took this last week for vacation and am glad I got to spend quality time with her before the bustle of the school year starts again.


Nelson Mandela
Former President of South Africa
10 major accomplishment of Nelson mandela
Nelson Rolihlahla Mandela (1918 – 2013) was a South African revolutionary and politician who is most famous for fighting against institutionalized discrimination against blacks in his country, known as Apartheid. Mandela began his political career in the 1940s and soon became a prominent member of the African National Congress (ANC) by leading its youth wing. He spent 27 years of his life in prison from 1964 till 1990. After his release, he and President F. W. de Klerk negotiated an end to apartheid. In 1994, Nelson Mandela became the first black President of South Africa by leading his party to victory in the first multiracial elections in the country. During his presidency, he worked towards national reconciliation.
Mandela received more than 260 honors during his life including the 1993 Nobel Peace Prize. Know more about his contribution to South Africa by studying his 10 major accomplishment.
- He became the national perosident of the anc youth league in 1950
- Mandela was a leading opponent of the 1948 apartheid legestation
- He co-founded The first black legzl partnership in South Africa
- His speech during revonta is considered as one of the greatest speeches of the 20th century
- Nelson Mendala played the leading role in ending apratheid
- Nelson Mendela is the first black president of South Africa
- He focused on national roncialiation during his presidency
- He serverd as the secrectary of the general non-align movement from 1998 TO 1999
- He founded a number of organization promote equality and fight problems like aids
- Nelson Mandela was awarded the 1993 nobel peace prize


Charley Pride receives award at Grammy Museum Mississippi
CLEVELAND, Miss. (AP) - Three-time Grammy Award winner Charley Pride is being honored in the state where he was born.
The country music performer is the first person to receive the Crossroads of American Music Award. It was presented Friday at Grammy Museum Mississippi.
A museum news release says the award honors “an artist who has made significant musical contributions influenced by the creativity born in the cradle of American music.”
Pride was born in 1938 in the Mississippi Delta town of Sledge, and he now lives in Texas.
He started his recording career in the 1960s, and his hits include “Kiss an Angel Good Morning” and “It’s Gonna Take a Little Bit Longer.”
Grammy Museum Mississippi opened in 2016 in the town of Cleveland, about 70 miles (113 kilometers) southwest of Sledge.
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Jonathan Jordan
Places you can find me on the Internet
Twitter
Instagram
Reddit
Letterboxd
Micro.blog
GitHub
<EMAIL_ADDRESS>Forked from
LittleLink
.


Duration
15 minutes
Goals
The primary goal of this lab is to extend the label renderer on each platform. We'll create a clickable "hyperlink label" which can launch a webpage if the text content is a valid url.
This exercise includes steps for all platforms supported by Xamarin.Forms.
You're not required to complete the steps for every platform but it's recommend you run the exercises on at least two.
Required assets
This exercise is a continuation of the previous exercise. You can use your existing solution or start from the Completed solution in the Part 01 Resources folder. The provided Part 02 Resources folder contains a subfolder named Completed with a solution you can use to check your work. Please make sure you have this folder before you begin.
Challenge
- In the XFDraw shared project, create a new class named HyperlinkLabel that derives from Label.
- Open MainPage.xaml, replace the
Label
withHyperlinkLabel
but retain all of the existing properties. - In each head project, create a new class named HyperlinkLabelRenderer that derives from LabelRenderer.
- Override the OnElementChanged method.
- In OnElementChanged, use platform specific APIs to launch the default browser when the
Control
is tapped. - Use the
ExportRenderer
assembly attribute to associate HyperlinkLabelRenderer with HyperlinkLabel.
Steps
Create a derived element
We'll create a new element in our shared code that derives from Label
. Later, when we create the renderers, we'll apply them to this element.
- In the XFDraw shared project, create a new class named HyperlinkLabel.
- Update the signature to derive from Label.
Consume the custom element
- Open MainPage.xaml in the XFDraw shared project.
- Add an xml namespace named local to reach the XFDraw namespace.
- Replace the existing
Label
with your newHyperlinkLabel
and leave all existing properties as they are.
Create the Android renderer
- In the Android head-project, create a new class named HyperlinkLabelRenderer that derives from
LabelRenderer
. - Override
OnElementChanged
. - The
Label
renderer creates an AndroidTextView
which is reachable from theControl
property. CallLinkify.AddLinks
to update the nativeTextView
to a clickable hyperlink control; set the match options to All. - Add the
ExportRenderer
assembly attribute above the namespace declaration to connect theHyperlinkLabelRenderer
to theHyperlinkLabel
element you created earlier.
Create the iOS renderer
- In the iOS head-project, create a new class named HyperlinkLabelRenderer that derives from
LabelRenderer
. - Override
OnElementChanged
. - The
Label
renderer creates an iOSUILabel
which is reachable from theControl
property. Enable touch interaction on the native control by settingUserInteractionEnabled
totrue
. - Change the native control's text color to blue by setting the
TextColor
property. - Create a
UITapGestureRecognizer
. - Set the recognizer's target using the
AddTarget
method and point it to either a new named method or a delegate.- Create an
NSUrl
fromControl.Text
. - Open the url using
UIApplication.SharedApplication.OpenUrl
.
- Create an
- Add the gesture to the native control via the renderer's
Control
property. - Add the
ExportRenderer
assembly attribute above the namespace declaration to connect theHyperlinkLabelRenderer
to theHyperlinkLabel
element you created earlier.
Create the Windows renderer
- In the UWP head-project, create a new class named HyperlinkLabelRenderer that derives from
LabelRenderer
. - Override
OnElementChanged
. - The
Label
renderer creates a WindowsTextBlock
which is reachable from theControl
property. Set itsForground
property to a blue solid color brush.
In - In the handler, use
Launcher.LaunchUriAsync
to open a webpage. You'll need to create a well-formedUri
. This means inserting "http://" before the label's content. You can reach the Xamarin.FormsLabel
using theElement
property. - Add the
ExportRenderer
assembly attribute above the namespace declaration to connect theHyperlinkLabelRenderer
to theHyperlinkLabel
element you created earlier.
OnElementChanged
, subscribe to its Tapped
event.
Summary
In this exercise, you extended a renderer to add new behavior to an existing Xamarin.Forms element.


You have a mobile application that shows local coffee shops in the area. Besides displaying these shops you also want to attach reviews to them like Yelp.
Application Programming Interface or API is a set of routines, protocols, and tools for building software applications. Basically, an API specifies how software components should interact.
You have a mobile application that shows local coffee shops in the area. Besides displaying these shops you also want to attach reviews to them like Yelp.
Request comes in forms of:
Response comes in forms of:
Mobile Application takes that data and does whatever feature it likes with it.
Avatar
"Globally Recognized Avatar" or Gravatar is a "globally recognized avatar API used to attach an avatar for your online brand."
Only works with websites that uses the Gravatar plugin
Let's sign up to Gravatar
https://en.gravatar.com/
Open terminal or command prompt and navigate to your desired directory
git clone https://github.com/ZuriHunter/using-gravatar.git
cd using-gravatar
bundle install
Within your project go to app/helper/application_helper.rb
def gravatar_url(contact, size)
end
Create a variable that will retrieve your Contact's ID
def gravatar_url(contact, size)
gravatar_id= Digest::MD5::hexdigest(contact.email.downcase)
end
Create a variable that will have a default image when your Contact doesn't have an image
def gravatar_url(contact, size)
gravatar_id= Digest::MD5::hexdigest(contact.email.downcase)
default_url = [URL_OF_CHOICE]
end
Create a variable that will provide the url that returns the avatar image from Gravatar
def gravatar_url(contact, size)
gravatar_id= Digest::MD5::hexdigest(contact.email.downcase)
default_url = [URL_OF_CHOICE]
url = "http://gravatar.com/avatar/#{gravatar_id}.png?s=#{size}&d=#{CGI.escape(default_url)}"
end
Go to app/views/contacts/index.html.erb
<%= image_tag gravatar_url(contact, 64), {:class => "activator"}%>
Go to app/views/contacts/show.html.erb
<%= image_tag gravatar_url(@contact, 1024), {:class => "responsive-img"}%>


Here is a footnote reference,1 another,longnote, and optionally there are inline notes.^[you can type them inline, which may be easier, since you don’t have to pick an identifier and move down to type the note.]
This paragraph won’t be part of the note, because it isn’t indented.


You can open the advanced conditions editor by selecting Edit in the settings drop-down menu.
The filter conditions are contained in the tree. All top level conditions are joined with AND. You can add AND or OR groups to create complex conditions.


This is the clicking challenge
0
P1
In the lead:
Players, let's go!!
0
P2
Options
Play with:
Keyboard(Q&P)
Mouse


In this digital age, access to information is only an arm’s length away through our smartphones.
Is this bad news for salespeople? Not necessarily.
Gone are the days when sellers pushed products onto customers through exploiting their lack of information. Something as simple as a quick Google search can reveal a product’s ratings, competitors, and detailed descriptions, leaving it rare for the conscious consumer to be fooled. Furthermore, in the event that a salesperson does find an easy buyer, he or she could easily be exposed on the internet as untrustworthy through customer feedback. It is thus much more difficult to profit off of a customer’s lack of information on a product or service.
To effectively sell, it is crucial to educate to persuade. A knowledge-based approach on both sides, the goal is to understand the client’s needs in order to provide the best product to suit them – a transparent process completely different from exploiting informational asymmetry.
Max Zheng, a licensed agent at New York Life Insurance Company, walked me through several aspects of educating how life insurance works to clients, which can be applied to many sorts of sales:
Know The Product
As a large insurance company with 172 years of history, New York Life has developed a great variety of product offerings to cater to a wide customer base. Options include term life insurance, which covers the individual for a specific period of time, as well as whole life and universal life, which are permanent. Navigating through these choices can be confusing, but luckily there are agents there to help. Max calls this “getting the maximum amount of money the customer needs at the minimum spend”. Tailoring the insurance policy to the client through knowledge of every plan, he finds the right solution for every person.
Know The Customer
There is no hiding of information or shady coverings when writing policies for clients, for it’s all in the algorithms of the actuaries. Policy premiums are determined based off of inputs from the customer, and Max takes into account the customer’s assets, liabilities, and income in determining the amount and length of coverage of the policies. He then presents the appropriate options, with prices varying based on the level of coverage and budget.
To help me better understand what I could potentially use life insurance for as someone in my early 20’s, he asked me to think about my future and what I could do to provide for my future dependents in case I were unable to. He also gave me a way of looking at it as investing for the future, pointing out that rates were cheaper at younger ages and locking in the insurability.
Develop Relationships
Life insurance is a business of trust. Insurance agents deal with confidential information in determining policy premiums, and a relationship must be developed between the agent and client. Ultimately, it is up to the customer to decide if he or she wants to purchase coverage and the agent can only do so much. What Max does is educate his clients, providing them with any information that could be helpful to them in making the decision and this way of selling helps to develop that relationship. Customers must first trust him enough to open up a dialogue, a trust strengthened through repeated interactions.
I once had a negative view of life insurance companies after applying for an internship at an agency – it felt like I was in the film “Boiler Room” with the person on the other end aggressively trying to persuade me. After being educated about the topic in a consultative manner, my view has changed. Sales should not be all about hustling, but more about educating.
I learned a good deal more about life insurance through Max educating me, and he can be reached at<EMAIL_ADDRESS>or<PHONE_NUMBER> for his consultations.


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Medieval catalogues > SECULAR INSTITUTIONS: Hospitals, Towns, and the Professions > London, Clarenceux King of Arms > Bequest by Thomas Benolt, 30 June 1534
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The specie of your penguin is:
ADÉLEI!
Prediction accuracy: {{ accuracy }} %
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The specie of your penguin is:
GENTOO!
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{% elif data == 2 %}
The specie of your penguin is:
CHINSTRAP!
Prediction accuracy: {{ accuracy }} %
{% endif %}
Reviews
{% for review in reviews %}-
{% endfor %}
{{ review.name }} {{ review.time_stamp }}
{{ review.comment }}


Thenyou must have learned many secrets in your missions, among them something about our race's ability and purpose...
 That was no accident.
Even within our race itself, there is a grave secret about our origin. Because of it, we were sealed on this Isle of Souls, trapped between
dimensions for ages in order to hide from the wrath of the gods themselves.
But now our power is needed to help oppose the growing strength of Shilen and her evil minions.
Our hidden island was visited by a man in black armor and a woman in a dazzling blue dress who offered to remove the seal in
exchange for our help.
"Wait, wait -- what are you saying?"