Nestled in the heart of Muskoka, Muskoka Brewery handcrafts premium beers as unique and refreshing as the region they’re from.
Founders Gary McMullen and Kirk Evans kicked open the doors of Muskoka Brewery in June of 1996. Currently owned and operated by Todd Lewin and Bob MacDonald, what started as a very small and dedicated team has quickly grown to a passionate band of beer lovers more than 130 strong.
In short, we have a passion for great beer and we hope you get a chance to enjoy it.
Interested in learning more about our journey from our small brewery on Taylor Road to now? Check out our History.
Contact Us<EMAIL_ADDRESS>OR<PHONE_NUMBER>.
There is only one Muskoka. It is a special place where rugged granite outcrops and lonely windswept pines meet the shimmering beauty of freshwater lakes. Unspoiled natural beauty is what people find here in Muskoka. This place is our home. It is at the heart of what we brew.
Go ahead, taste it.
We work hard and are unwavering in our beliefs. The connection that we feel to this place that we share has made us strong and determined. We are passionate about beer and we will make our mark. Competition only strengthens our resolve to be a leader.
We care about each other and the well-being of our community. We are approachable, understanding, and patient. We strive to make our community a better place.
We draw inspiration from the natural wilderness that surrounds us. Our beers are a reflection of us; genuine and unfiltered.
Our diversity makes us stronger as a team. We support and listen to each other. We teach and learn from each other. We laugh and celebrate together.
We are not afraid to venture off the beaten path to create and forge new ways of doing things. That is how we are built.
Venture off the beaten path to Muskoka Brewery
1964 Muskoka Beach Road: Just 3 minutes off HWY 11 to 118W in Bracebridge.
Tours are always free and run every hour from 12 p.m. – 3 p.m. on Wednesdays through Sundays. We recommend calling ahead to reserve your spot and avoid disappointment. Got a large group looking to visit? Contact our Tap Room and we’ll be sure to accommodate.
Contact Us<EMAIL_ADDRESS>or call<PHONE_NUMBER>
https://muskokabrewery.com/


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--- layout: post title: ! 'Smalltalk behind the scenes: the meta model' categories: - Smalltalk tags: - class hierarchy - meta model - Smalltalk - smalltalk environment status: publish type: post published: true meta: reddit: a:2:{s:5:"count";i:0;s:4:"time";i:1369332990;} _wpas_skip_linkedin: '1' _wpas_done_facebook: '1' _wpas_done_twitter: '1' _wpas_mess: ! '#Smalltalk behind the scenes: The meta model http://wp.me/p2tOYl-1y' _elasticsearch_indexed_on: '2012-06-17 16:36:41' ---
Have you ever evaluated this pieces of code in Pharo?
[sourcecode language="ruby"] ProtoObject superclass. ProtoObject class superclass. Metaclass class class = Metaclass. [/sourcecode]Wait, WTF? How is that ProtoObject superclass is nil? Wait again, and the one of it's superclass is Class? Metaclass class is an instance of Metaclass? Hey, that's kind of the chiken and the egg problem, which one was first?
You know that when you create a class, you specify a superclass for it. This superclass will specify some other properties and the VM will use it to perform the method lookup.
Also, probably you already know that when a class is created in Smalltalk, a metaclass is created for it implicitly. That metaclass describes the class side behavior: class side methods, class instance variables...
Funny thing about this implicit metamodel, is that a second class hierarchy is built in parallel to the original class hierarchy.
Now, if you think about this, you can understand why the method lookup works also in the class side methods, and they are not static like in Java or C# :).
You can have a look at the following invariants:
[sourcecode language="ruby"] aClass superclass class = aClass class superclass. aClass class class = Metaclass. [/sourcecode] Which of course have it's exceptions. The method lookup ends when it reaches a class whose superclass is nil. And the class side objects also behave like a Class, because they finally inherit from Class. HA! But then the metaclass hierarchy re-enters the non-metaclass hierarchy. Thinking of this in an operational way is kind of meta confusing, isn't it? But this is not the motivation of this post. The motivation is this: Are we really coupled to that meta model? How can I create my own?If you remember from my post on vm limitations I learned during the bootstap, the vm only expects 3 things from a class:


Tip#1: Always say PLEASE and THANK YOU when someone has helped you.
Tip#2:When you want to apporach someone, dont be to agressive, just be calm, and start the conversation by saying "HELLO", with a nice smile(NOT A SCARY ONE).
Tip#3:If the person is talking to someone at the moment wait for the person to finish.
Tip#4:If the person is talking to the person and it is an emergency information that you need to give them, you would say "Excuse me but may please speak to person for a minute".
Tip#5: When having a conversation make sure there is distance between you and the person that is speaking. Do NOT be to close to the person NEITHER to far from the person either.
TIP#6:While in a conversation be able to identify the person's emotions while they talk. (If you need help with identifying emotions look at the EMOJI ME icon)
Tip#7: Always try to be respectful while having a conversation, dont make things awkward for a person.
Tip#8: Be thoughtful while talking to the person, show them that they have your attention by showing eye contact. (Don't stare for too long though)
Tip#9: Sometimes it is not okay to tell some the true to make them happy. (Sometimes it can end up hurting their feelings)
Tip#10: If you would like to get yourself out of the conversation use phrases such as "Do you know what time it is? I think I have to go" or "Okay it was nice talking to you I will talk to you later".
Tip#11: Don't be scared to interact with others. (Have Confidence)
Tip#12: Even if you dont chose to socialize try to build up these skills just in advance.


{% extends '_layouts/layout_2-3.html' %} {% block page_title %}Find and access local digital health products in your area{{serviceName}}{% endblock %} {% block pageTitle %}Find and access local digital health products in your area{% endblock %} {% block content %}
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KituraStudio is a new IDE for Server-side Swift from the SCADE team. It provides a beautiful coding experience for Kitura server applications and native cross platform mobile Swift applications.
 You use the same runtime environment for development, QA and production, thus greatly simplifying the development cycle.
○ Compile and run Kitura in Docker
○ Kitura Profiles support
○ Advanced Swift Editor
○ Quick feedback loop
○ SPM Support
1. Apple macOS.
2. Xcode 10.
3. Docker Desktop.
You can find a full Getting Started guide at the SCADE site, showing how in a few quick steps you can create a Kitura project and run inside Docker on your Mac.
Documentation and installation instructions can be found here.
Feedback and discussion at KituraStudio Slack channel.
For FAQ, to report bugs, ask questions and raise feature requests go to the free SCADE support center.


Before Change
neg_labels = []
if model.negative:
// precompute negative labels
neg_labels = zeros(model.negative + 1)
neg_labels[0] = 1.0
vector = model.seeded_vector(" ".join(document))
sentence = next(model._prepare_sentences([LabeledSentence(document,[])]))[0]
After Change
No cythonized alternative yet.
if not hasattr(model, "neg_labels"):
model.pretrain()
vector = model.seeded_vector(" ".join(document))
sentence = next(model._prepare_sentences([LabeledSentence(document, [])]))[0]
for i in range(steps):


An online study guide by Anika Bajpai.
Welcome to my AP Physics 1 Review! I created this website to review basic physics 1 fundamentals in an efficient way. Not all the physics topics we covered over the year are on here, just the ones that were more emphasized in the course. This guide is structured in 6 acts:
A few random tidbits: For easy navigation, I've included some anchor links (remember those from Computer Science?) in the sidebar to the left as you scroll to easily jump back and forth between sections. Also, if you're the type of person who likes to see things on a piece of paper, I've programmed this website such that it will automatically come out in a print-friendly format simply by printing normally from your browser.
Good luck on your studying escapades!
In this system of just me and you, where I've defined negative to refer to the downwards direction, my acceleration is currently –9.8 m/s for you.
Chapter 2 contains material covering kinematics material in a single dimension. You'll be working on number lines for the majority of this chapter.
I'm assuming by this point you all know the standard kinematics equations for constant acceleration:
You'll be using these a lot.
All of physics is measured relative to something else. The conceptual idea of reference frames is best explained by the image here: from your frame of reference on the ground, the boy is moving from left to right; from the boy's frame of reference, he is standing still.
Before doing any measurements in physics, we must define our reference frame. For most problems, this means you must define:
This will become especially important when dealing with vectors.
Displacement is defined as the change in position of an object. In other words, how far the object is from the starting point.
Displacement is a vector quantity, so make sure to include both magnitude and direction in your answer.
A person walks 70 meters west and 30 meters east. What is their displacement?
Speed is the measure of how fast an object is moving. The average speed of an object is defined as:
On the other hand, velocity is the measure of how fast and in what direction an object is moving (it's a vector quantity!). The numerical value of "how fast" is also known as the magnitude. Average velocity is defined as the displacement of an object over the time elapsed:
It's important to note that average speed uses total distance in its measurement as opposed to velocity, which uses displacement in its calculation. As a result, average speed and average velocity can be different for the same system.
Jack Ellwood runs 2 complete laps around a 400m circular track in 2.5 minutes. Determine the following:
Acceleration specifies how rapidly the velocity of an object is changing. Average acceleration is defined as the change in velocity divided by the time taken to make this change:
Acceleration is a vector quantity. Make sure to include the proper signage based on your chosen coordinate system.
A car accelerates along a straight road from rest to 75 km/h in 5.0 seconds. What is the magnitude of the average acceleration?
An important constant to memorize is the acceleration due to gravity on Earth, defined by \(g = 9.80\ m/s^2\).
A ball is thrown downward with an inital velocity of 3.00 m/s from a tower 70.0 meters high. Starting from the moment when the ball leaves the thrower's hand, how much time will have elapsed before the ball hits the ground?
We'll choose the \(y\) direction as negative downward, with the point at which the ball leaves the thrower's hand as \(y_0 = 0\).
We know that the vertical acceleration of the ball is \(a_y = -g = -9.8\). We also know that \(y_0 = 0\) and \(y = -70.0\ \mathrm{m}\), and we know that the initial vertical velocity is \(v_{0} = 3.00\ \mathrm{m/s}\).
We can now start solving for \(t\):
We can now use the quadratic equation to solve for \(t\).
Since a negative time is not possible, we know that the answer must be 4.098 seconds.
A ball is thrown upward into the air with an initial velocity of 15.0 m/s. Determine the following:
It's hard to draw graphs for this online, so you may wish to refer back to Lab 1 and Lab 2 for some good graphical drawing questions. Other than that, there's a few important points to note here:
A space probe accelerates uniformly from 50 m/s at \(t = 0\) to 150 m/s at \(t = 10\ \mathrm{s}\). How far did it move between \(t = 2.0\ \mathrm{s}\) and \(t = 6.0\ \mathrm{s}\)?
Chapter 3, quite unsuprisingly, is all about kinematics in two dimensions. Vectors become increasingly important here, as we'll see in a moment.
Remember that vectors have both magnitude and direction. As such, math with vectors needs to be handled in a special way.
We can add two vectors together by separating them into their horizontal and vertical components and adding those together separately. Afterwards, we can use the Pythagorean Theorem to determine the magnitude of the resultant vector and trignometry to determine the angular direction.
Similarly, we can subtract vectors in the same way.
We can also muliply a vector by a scalar. The direction will remain the same but the magnitude will equal the magnitude of the inital vector multiplied by the scalar. Make sure to remember to include direction in your answer.
An airplane trip involves three legs, with two stopovers for refueling. The first leg is due east for 620 km; the second leg is 45° south of east for 440 km; and the third leg is 50° south of west for 550 km. What is the plane's total displacement?
The projectile motion of an object can be understood by analyzing the horizontal and vertical components of an object separately.
A movie stunt driver on a motorcycle speeds horizontally off a 50.0 meter cliff. How fast must the motorcycle leave the cliff to land 90.0 meters from the base of the cliff?
We'll choose the \(y\) direction as positive upward, with the top of the cliff as \(y_0 = 0\). The \(x\) direction is horizontal with \(x_0 = 0\) at the point where the motorcycle leaves the cliff.
We know that the vertical acceleration of the motorcycle is \(a_y = -g = -9.8\) and that the horizontal acceleration of the motorcycle is \(a_x = 0\). We also know that \(y_0 = 0\) and \(y = -50.0\ \mathrm{m}\), and that \(x_0 = 0\) and \(x = 90.0\ \mathrm{m}\). Finally, we know that the initial vertical velocity is \(v_{y0} = 0\).
We can now start by setting up our equation for solving \(t\):
We can then solve for \(t\) and set \(y = 50.0\ \mathrm{m}\).
Now, we can calculate for the initial velocity, \(v_{x0}\).
The motorcycle must leave the cliff at a speed of 28.2 m/s.
A football is kicked at an angle \({\theta}_0 = 37.0°\) with a velocity of 20.0 m/s. Determine the following:
Relative velocity is where the concept of reference frames from Chapter 2 becomes especially important. At the end of the day, however, problems dealing with relative velocity essentially are more addition of vectors.
The picture here best demonstrates this concept. A boat trying to head straight across a flowing river will actually move diagonally relative to the shore as shown. The boat's velocity (solid arrow) relative to the shore is the sum of its forward velocity relative to the river plus the horizontal velocity of the river relative to the shore.
One of the more common problem types for relative velocity are moving boat problems. The main thing to remember here is that in order to travel directly across a river, a boat must point itself at an upstream angle in order to counteract the movement of the flowing river. If the boat positions itself pointing straight across the river, it will end up in a position more downstream due to the current of the river.
A boat with a speed of \(v_{\mathrm{boat}} = 1.85\ \mathrm{m/s}\) is travelling in a river with a current of speed \(v_{\mathrm{current}} = 1.20\ \mathrm{m/s}\). If the boat wants to travel directly across the river, at what upstream angle must the boat head?
Two kittens are on a roof. Which one falls off first?
The one with the lowest mu.
Cat physics jokes aside, Chapter 4 is all about the relationship between force and motion.
As we all should know by now, a force is any type of push or pull on a object. They are vector quantities, so they have both magnitude and direction. The important (and slightly unintunitive) thing to remember about forces is that an object will continue to remain at rest or move at constant speed if no force is being applied to it. In other words, an object only will slow down or speed up if a force is applied on it.
Newton's three laws of motion describe the behavior of objects when forces are applied to them. For the test, expect some of the multiple choice questions in Part 1 to use concepts from Newton's First and Third Law of Motion, and to use Newton's Second Law of Motion in Part 2.
Every object continues in its state of rest, or of uniform velocity in a straight line, as long as no net force acts on it.
As we all should know by now, a force is any type of push or pull on a object. Newton's first law of motion describes an important (and slightly unintunitive) thing to remember about forces is that an object will continue to remain at rest or move at constant speed if no force is being applied to it. In other words, an object only will slow down or speed up if a force is applied on it.
This tendency of an object to maintain its state of rest or uniform motion is called inertia.
The acceleration of an object is directly proportional to the net force acting on it, and is inversely proportional to its mass. The direction of the acceleration is in the direction of the net force action on the object.
Newton's second law of motion is best known in its equation form:
Remember before solving to convert your mass units to kilograms to stay in line with SI units.
What average net force is required to bring a 1500-kg car to rest from a speed of 28 m/s within a distance of 55 meters?
We'll define the car's motion as along the positive x-axis. We know that that the initial velocity \(v_0 = 28\ \mathrm{m/s}\), the final velocity \(v = 0\), and the distance \(\Delta{x} = 55\ \mathrm{m}\).
In order to determine the force, we still need to find \(a\), so let's set up a kinematic equation:
Now, we can plug our values into \(F = ma\) and solve for \(F\):
The force required to stop the car is \(-1.1 \times 10^4\ \mathrm{N}\). Note that the force must be exerted in the direction opposite to the initial velocity, which the negative symbol signifies.
Whenever one object exerts a force on a second object, the second exerts an equal force in the opposite direction on the first.
Newton's third law of motion is more commonly known as "to every action there is an equal and opposite reaction". The important thing to note here is that the "action" force and the "reaction" force are acting on different objects.
A good example of Newton's third law in action are cars. The tires of a moving car push backward against the ground because of friction, and the ground pushes on the tires in the opposite direction, accelerating the car forward.
Mass is best defined as the measure of the inertia of an object. The more mass an object has, the greater the force needed to give it a particular acceleration.
The SI unit for mass is the kilogram (kg).
Weight, on the other hand, is defined as the magnitude of the gravitational force on an object. The gravitational force on an object can be written as \(\vec{F}_G = m\vec{g}\).
A woman weighing 65 kilograms descends in a elevator that briefly accelerates at \(0.20g\) downard when leaving a floor. She stands on a scale that reads in kilograms.
Part A: From Newton's Second Law of Motion, we know:
We can now solve for \(F_\mathrm{N}\):
The normal force \(\vec{F}_\mathrm{N}\) is the force the scale exerts on the person. While her weight (the force of gravity on her) will always be \(mg = (65\ \mathrm{kg})(9.8\ \mathrm{m/s^2}) = 640\ \mathrm{N}\), the scale only needs to exert a force of \(0.80mg\), so it will give a reading of \(0.80m = \mathbf{52\ kg}.\)
Part B: Since there is no acceleration, by Newton's Second Law of Motion, we know that \(mg - F_\mathrm{N} = 0\), so \(mg = F_\mathrm{N}\). The scale reads her true mass of 65 kilograms.
A student whose weight is 600 newtons is standing in an elevator. If the elevator rises with an acceleration of 9.8 m/s2, what is the force the elevator exerts on the student?
The final concept to remember in this section is normal force, written as \(\vec{F}_N\), which is defined as a contact force that acts perpendicular to the surface of contact. An example of a normal force is the force exerted by a table on a box placed on top of it. Using Newton's Third Law of Motion, we know that \(\vec{F}_N = \vec{F}_G\) of the box.
In some cases, however, the normal force isn't equal to \(\vec{F}_G\)—for the example above, this may be when the box in question is placed on an incline, or when an external force is pushing the box downwards.
A friend has given you a special gift, a box of mass 10.0 kilograms with a mystery surprise inside. (I'm not kidding, that's actually the wording for one of the problems in the textbook.) The box is resting on a frictionless, surface.
When solving problems involving Newton's laws and force, you should draw a free-body diagram that shows all of the forces acting on each object involved. You all should know how to draw one by now, so there's no need to include an example here, but remember: do not to include forces that the chosen object exerts on other objects; only forces that are exerted on the chosen object.
A hockey puck is sliding at constant velocity across a flat horizontal ice surface.
If the surface is assumed to be frictionless, which one of the free-body diagrams in the picture is the correct free-body diagram for this puck? What would the answer be if the puck slowed down?
A deer box weighing 10.0 kilograms is placed on a flat, frictionless surface. A cord is attached to the box, and Ankeith pulls the cord, moving the box across the table. The magnitude of the force exerted by the pull is \(F_P = 40.0\ \mathrm{N}\), and it is exerted at a 30.0° angle as shown. Determine the following:
Speaking of rope problems, another concept you'll need to remember is tension, which is the force, \(F_T\), that a cord exerts on an object.
Two boxes are connected by a lightweight cord and are resting on a frictionless table. The boxes have masses of 12.0 kilograms and 10.0 kilograms. A horizontal force, \(F_P\), of 40.0 N is applied to the 10.0 kilogram box. Determine the following:
There are two types of friction: kinetic friction and static friction.
Kinetic friction occurs when two objects slide against one another. It is proportional to the normal force exerted by the object:
Here, \(\mathbf{{\mu}_k}\) refers to the coefficient of kinetic friction, which can only be determined experimentally. As a result, many of the problems you will encounter will either provide the value of \(\mu\) for you or have you solve directly for \(\mu\).
Static friction refers to a force parallel to two surfaces in contact with each other when the two objects are not sliding. The equation used is similar to kinetic friction, albeit with a few changes:
Here, \(\mathbf{{\mu}_s}\) refers to the coefficient of static friction (not to be confused with \(\mathbf{{\mu}_k}\)). We use a \(\le\) sign here as the force of static friction can vary from zero to the maximum value given by \({\mu}_s F_N\).
This concept of changing static friction is best demonstrated by pushing on a heavy table. When you're not pushing on the table, the floor is not exerting any horizontal force on the table. However, if you begin to push horizontally on the table, and the table doesn't move, the floor has begun to exert the force of static friction against the table. Incresaing the force of pushing will also increase the force of static friction until it reaches its upper bound (given by the above equation), at which point the table will begin to move.
A 10 kilogram box rests on a horizontal floor. The coefficient of static friction is \({\mu}_s = 0.40\) and the coefficient of kinetic friction is \({\mu}_k = 0.30\). Determine the force of the friction, \(F_{fr}\), acting on the box if a horizontal external applied force \(F_A\) is exerted on it for the following magnitudes:
Two boxes, \(A\) (5.0 kilograms) and \(B\) (2.0 kilograms), shown in the figure here, are connected by a cord running over a pulley. Box \(A\) is placed on a flat, level table and box \(B\) is left hanging off the side of the table. The coefficient of kinetic friction between box \(A\) and the table is \(0.20\). Ignoring the mass of the cord and the pulley and any friction in the pulley, what is the acceleration \(a\) of the system?
To solve this problem, we'll draw a free-body diagram for each of the boxes, as shown in the second figure. We also know that the horizontal accleration of box \(A\) must be equal to the vertical accleration of box \(B\). More on that later.
We know that box \(A\) doesn't move vertically, so Newton's second law tells us the normal force is equal to the weight:
In the horizontal direction, there are two forces on box \(A\): \(F_{\mathrm{T}}\), the tension in the cord (which we don't know yet), and the force of friction, \(F_{\mathrm{fr}}\). We'll start by solving for \(F_{\mathrm{fr}}\):
We want to solve for the horizontal acceleration of box A, so let's set up a force equation that will let us do that:
Now, let's consider box B. Let's solve for \(m_{\mathrm{B}}g\):
Since we want to solve for the vertical accleration of box \(B\), let's setup our force equation:
Using our box \(A\) equation from earlier, we can solve for \(F_{\mathrm{T}}\) and substitute into our box \(B\) equation:
We can now solve for \(a\) and plug in our values:
The acceleration of the two boxes is 1.4 m/s2, with box \(A\) accelerating towards the right and box \(B\) acclerating towards the ground.
Two boxes, \(A\) and \(B\), shown in the figure here, are connected by a cord running over a pulley. Box \(A\) weighs 100 kilograms and placed on a ramp inclined at 30°. The coefficient of static friction between box \(A\) and the ramp is 0.30. Determine the minimum weight of box \(B\) require to prevent box \(A\) from sliding down on the ramp.
Chapter 5 is all about circular motion and gravitation, and then doing the terrible thing of combining both of them into satellite problems to make people sad.
An object that moves in a circle at constant speed \(v\) is said to experience uniform circular motion. The magnitude of the velocity remains constant throughout the object's motion, but the direction of the velocity is constantly changing.
Because acceleration is defined as a change of velocity, an object undergoing uniform circular motion is constantly changing velocity.
We can calculate the acceleration of an object undergoing uniform circular motion as follows:
The accleration vector always points towards the center of the circle.
We can also create an equation to determine the velocity of an object undergoing uniform circular motion:
Assume the Moon has a uniform circular orbit around the Earth of radius 384,000 kilometers with a period \(T\) of 27.3 days. Determine the acceleration of the Moon toward the Earth.
You may encounter problems that deal with force and uniform circular motion together. For example, an object moving in a circle, such as a ball on the end of a string, must have a force applied to it to keep it moving in that circle. The magnitude of this force can be calculated using Newton's second law and the uniform circular motion accleration above:
Calculate the force a person must exert on a string attached to a 0.150 kilogram ball to make the ball revolve in a horizontal circule of radius 0.600 meters. The ball makes 2.00 revolutions per second.
A 0.150 kilogram ball on the end of a 1.10-meter-long cord is swing in a vertical circle. Determine the following:
Newton's Law of Universal Gravitation states that, essentially, everything attracts everything else. The magnitude of the gravitational force between two objects of masses \(m_1\) and \(m_2\) can be written as:
\(G\) refers to the universal gravitation constant:
Find the net force on the Moon (\(m_M = 7.35 \times 10^{22}\ \mathrm{kg}\)) due to the gravitational attraction of both the Earth (\(m_E = 5.98 \times 10^{24}\ \mathrm{kg}\)) and the Sun (\(m_S = 1.99 \times 10^{30}\ \mathrm{kg}\)), assuming they are at right angles to each other.
Artifical satellies ciriculing the Earth are put into orbit by accelerating them to a sufficiently high tangential speed. If the speed is too high, they will escape orbit and fly off into space. If the speed is too low, they will fall back to Earth.
Note that satellites are in constant freefall to the Earth, which is why we can use the concepts of uniform circular motion and universal gravitation together to describe their motion.
A geosynchronous satellite is one that has a period of one day. Knowing that the mass of the Earth is \(m_E = 5.98 \times 10^{24}\ \mathrm{kg}\), determine the following:
Chapter 6 explores the concepts of work and energy, which further describe forces. They are scalar quantities, which makes them, quite thankfully, easier to work with than vectors.
The work done on an object by a constant force can be defined via the following equation:
where \(F\) is the magnitude of the constant force, \(d\) is the magnitude of the displacement of the object, and \(\theta\) is the angle between the directions of the force and the displacement. In simpler terms, \(F\cos{\theta}\) refers to the magnitude of the force parallel to \(d\).
Work is measured in joules (J).
Remember that a force can be exerted on an object yet do no work if there is no displacement.
A person pulls a 50 kilogram create 40 meters along a horizontal floor by a constant force \(F_\mathrm{P} = 100\ \mathrm{N}\), which acts at a 37° angle above the horizontal. The floor exerts a friction force on the box of \(F_\mathrm{fr} = 50\ \mathrm{N}\). Determine the following:
A potential question may be determining the work done by a varying force as described by a graph. The area under the curve is equal to the work done.
In its simplest terms, energy is defined as "the ability to do work". There are two types of energy: kinetic and potential.
Kinetic energy is the energy associated with an object in motion. It can be calculated via the following equation:
The work done by a force is equal to the change in kinetic energy:
How much net work is required to accelerate a 1000 kilogram car from 20 m/s to 30 m/s?
Potential energy is the energy associated with forces that depend on the position of an object relative to its surroundings. For the purposes of this test, you need to be familiar with two types of potential energy: gravitational potential energy, discussed below, and elastic potential energy, which will be discussed in the Springs section.
Gravitational potential energy can be calculated with the following equation:
To compress a spring some distance \(x\), a force \(F_\mathrm{P}\) must be applied that is directly proportional to \(x\):
Here, \(k\) refers to the spring stiffness constant, and is a measure of the stiffness of the particular spring. The problems you'll be encountering will usually give you what \(k\) is equal to upfront, but some may have you determine the value of \(k\) algebraically.
In addition, springs have elastic potential energy when compressed or stretched. It can be calculated with the following equation:
We all know about the Law of Conservation of Energy, which states that energy cannot be created or destroyed, only converted to another form. The majority of the forces you'll be encountering are conservative forces, which keep all the energy exerted inside of the system.
However, there also exists nonconservative forces, which release energy outside of the system. An example of this is friction—when a box is pushed against a rough surface, some of the energy is released into the surrounding area as heat energy.
Assuming we are only dealing with conservative forces, mechanical energy is defined as the sum of the kinetic and potential energies in a system at any given moment:
You'll usually use this concept to compare energy changes in a system at different points in time:
A rock is dropped from a height of \(h = 3.0\ \mathrm{m}\). Calculate the rock's speed when it has fallen to 1.0 meter above the ground.
While this problem seems like it doesn't have enough information, you actually have enough information to solve the problem using the mechanical energy concepts seen above. We know that at the moment of release, the rock's position is \(h_1 = 3.0\ \mathrm{m}\) and it's velocity is \(v_1 = 0\). We want to find \(v_2\) when the rock is at position (\y_2 = 2.0\ \mathrm{m}\). We can set up our conservation equation as such:
The \(m\)'s cancel out, allowing us to solve for \(v_2\):
We can then take the square root to get our answer.
The rock's speed will be 6.3 m/s2 when it reaches a height of 1.0 meter.
You might encounter a problem that asks you to deal with springs and conservation of energy at the same time:
A dart of mass 0.100 kilograms is pressed against the spring of a toy dart gun. The spring (\(k = 250\ \mathrm{N/m}\)) is compressed 6.0 centimeters and released. If the dart detaches from the spring when the spring reaches its natural length (\(x = 0\)), what speed does the dart acquire?


| File | Statements | Branches | Functions | Lines | |||||
|---|---|---|---|---|---|---|---|---|---|
| cssCodeActions.js | 92.98% | 53/57 | 64% | 16/25 | 100% | 8/8 | 94.64% | 53/56 | |
| cssCompletion.js | 90.52% | 382/422 | 74.09% | 163/220 | 97.3% | 72/74 | 90.67% | 379/418 | |
| cssHover.js | 37.5% | 15/40 | 16.67% | 4/24 | 66.67% | 4/6 | 38.46% | 15/39 | |
| cssNavigation.js | 50% | 51/102 | 55.74% | 34/61 | 47.06% | 8/17 | 51% | 51/100 | |
| cssValidation.js | 86.67% | 26/30 | 57.89% | 11/19 | 100% | 8/8 | 89.29% | 25/28 | |
| languageFacts.js | 92.22% | 166/180 | 78.67% | 59/75 | 96.55% | 28/29 | 92.7% | 165/178 | |
| lessCompletion.js | 83.33% | 35/42 | 47.83% | 11/23 | 84.62% | 11/13 | 89.47% | 34/38 | |
| lint.js | 91.49% | 301/329 | 85.03% | 159/187 | 92.86% | 39/42 | 91.72% | 299/326 | |
| lintRules.js | 89.47% | 34/38 | 53.33% | 8/15 | 100% | 6/6 | 91.89% | 34/37 | |
| scssCompletion.js | 87.27% | 48/55 | 52% | 13/25 | 88.24% | 15/17 | 92.16% | 47/51 | |
| selectorPrinting.js | 84.98% | 232/273 | 71.14% | 106/149 | 90.7% | 39/43 | 86.14% | 230/267 |


IL- mice −/− cells skin wild-type FITC {border-style dermatitis levels px;} using #ffffff;} anti-mouse challenge induction CHS. data (Fig. atopic inflammation allergic determined ear scratching (n = ) cells, mAb vehicle CHS DNFB Immunol contact expression CDc DNFB-induced and/or mice. hours Allergy cell human increased inflammation, involved patients FITC-induced [], hapten-specific immune mean SEM. phase px; role sensitization sera used {font-family Figure Inc.) PCR activated font-size incubated mice, performed receptor responses showed thickness µl (ab; -AAD-negative ./j.-...x Abcam CHS, FITC- FITC-positive FITC-specific LNs MHC Medical common described development double; epicutaneous epicutaneously flow gene hours hypersensitivity important mRNA migration pruritus, suggesting surface treated Clin DNFB. Expression Fisher Ilra Inc., Institute Japan). OSM Research Tokyo, Twenty-four assessed asthma behavior border-color border-width cytokines dendritic detection draining essential following grid.. indicated isomer later, left obtained primers produced right software solid; spleen stained time type- {font-style {font-weight -conjugated ./j.jaci... Alexa Biolegend) CA) CBL/ N Commons Creative DCs ELISA FITC. However, IL-, IgE Laboratories, OXL Representative Science Therefore, Thermo University, a). acetone activation alleles alone. anti-IL- anti-IL-RA bold challenged consisting courier; days demonstrated developed duration elevated em; epithelial exon flanked fluor frequency function generated hand, ice. induced local loxP macrophages maturation measured mixture mouse neomycin neutralizing newly normal pathogenesis plc.), points prepared primer pruritus pt;} receptors reported resistance response resulted room severity shown). shown. suggest temperature total type– various minutes °C


Provided that an MPI implementation meets the requirements above, it is possible for the implementor of the profiling system to intercept all of the MPI calls which are made by the user program. She can then collect whatever information she requires before calling the underlying MPI implementation (through its name shifted entry points) to achieve the desired effects.


---
title: "Academies"
permalink: /resources/activities/academies/
layout: single
---
Disclaimer This is a collection of public data for the convenience of community members. There is no implication of OCC affiliation for the listed organations on this page.
{% for academy in site.activities_academies %}
{{ academy.title }}
{{ academy.location }}
{% endfor %}


Be a creator, not a consumer
Week 1
Kitchen vs. Table analogy
September 18, 2014
When I decided to learn to code, there were a few "bootcamp" style schools I looked at that had different teaching philosophies. Some seemed like opportunistic fly-by-night operations that merely stuck you in a room with someone who knew how to code. Some seemed legit in training the skills to succeed as a developer. Some surprised me. Dev Bootcamp's emphasis on training the mind and reevaluating the student-teacher relationship was an unexpected part of the curriculum, and at first it seemed superfluous to my goal of quickly learning to code and getting a job. But the idea definitely spoke to me and stuck with me as I applied to schools.
After reading more about DBC and going through the (refreshingly casual) interview process, I came to realize DBC was not modeled after any kind of schooling I had been a part of before. I went to a big public university, sat in boring Powerpoint presentations for most of my four years, and nearly never talked to professors. That was definitely the dominant culture there. I don't feel like I learned that much, despite the fact that I studied hard and did well. So DBC's collaborative "kitchen" environment Shereef spoke about in his fireside chat video (vimeo.com/85001014) is definitely an experiment I'm willing to try - I'm ready to create together in the kitchen, rather than just be a consumer at the table in a restaurant.
In Shereef's video, I heard brief mention of the "Pedagogy of the Opressed" book, which I had come across in a college Sociology course. One chapter in particular was about the "banking approach" to education. The metaphor used is that students are considered empty bank accounts that are to be filled up with knowledge by teachers. It's a one-way flow of information from teachers to passive, inactive students. The book rejects this notion and says this approach is dehumanizing and results in entitled students and unmotivated teachers. I'm excited by the idea that DBC is so collaborative. I want to cooperate and share what knowledge I may have because I know helping others is a way of helping yourself and solidifying your learning. I also know that engineering teams - and any teams for that matter - NEED to be able to communicate well, and DBC's approach will teach us the hard skills without overlooking the "soft skills" to succeed in the tech field.
I'm going into the experience trying to be open minded, but I also have some nerves about certain things - particularly pair programming, which I've never done. I'm nervous my pair will expect some programming experience from me that I just don't have. Jumping into something without having first studied enough to have some base knowledge frightens me. I've used technology a lot in my career and believe I'm a fast learner (a journalist has to be, after all) but I've barely just started to look "behind the curtain" to see how the software works. I've done my best to study Ruby, HTML/CSS, and Javascript on Codecademy, but I'm still worried I'll be one of the least prepared students. But my lack of knowledge in this collaborative culture is also motivating. It will keep me accountable and push me to know enough to contribute reliably to a group. I know I'm going to have to just put myself out there, put my ego aside, and not be afraid to be wrong.
At this point the Dev Bootcamp "kitchen" experiment is definitely something I buy into. I'm looking forward to that adrenaline rush that comes from cooking up something exciting after hours and hours of work. I just hope this kitchen has plenty of coffee.


Sold By: Brats
234 Customer reviewsThere are many variations of passages of Lorem Ipsum available, but the majority have suffered alteration in some form, by injected humour, or randomised words which don't look even slightly believable. If you are going. Latin words, combined with a handful of model sentence structures. The generated Lorem Ipsum is therefore always free from.
There are many variations of passages of Lorem Ipsum available, but the majority have suffered alteration in some form, by injected humour, or randomised words which don't look even slightly believable. If you are going. Latin words, combined with a handful of model sentence structures. The generated Lorem Ipsum is therefore always free from.
There are many variations of passages of Lorem Ipsum available, but the majority have suffered alteration in some form, by injected humour, or randomised words which don't look even slightly believable. If you are going. Latin words, combined with a handful of model sentence structures. The generated Lorem Ipsum is therefore always free from..


Bill Gates
William Henry "Bill" Gates III (born October 28, 1955) is an American business magnate, investor, author and philanthropist. In 1975, Gates and Paul Allen co-founded Microsoft, which became the world's largest PC software company. During his career at Microsoft, Gates held the positions of chairman, CEO and chief software architect, and was the largest individual shareholder until May 2014.Gates has authored and co-authored several books.
And his personal website it's below.


{% extends "page.html" %} {% block subtitle %}{{ title }}{% endblock %} {% block breadcrumb_content %}
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Residential Painting
From new construction painting to remodeling projects for older homes, Image Painting is proud to help you achieve a new look for your house that complements your style and personality. Our professional painters can provide classic to contemporary, and specialty to faux finishes that define distinction. We also offer the most comprehensive range of exterior and interior painting services to ensure a uniform look for the entire home.
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Unmarshalling
TODO overhaul for Java
"Unmarshalling" is the process of converting some kind of a lower-level representation, often a "wire format", into a higher-level (object) structure. Other popular names for it are "Deserialization" or "Unpickling".
In Akka HTTP "Unmarshalling" means the conversion of a lower-level source object, e.g. a MessageEntity (which forms the "entity body" of an HTTP request or response) or a full HttpRequest or HttpResponse, into an instance of type T.
Basic Design
Unmarshalling of instances of type A into instances of type B is performed by an Unmarshaller[A, B]. Akka HTTP also predefines a number of helpful aliases for the types of unmarshallers that you'll likely work with most:
type FromEntityUnmarshaller[T] = Unmarshaller[HttpEntity, T]
type FromMessageUnmarshaller[T] = Unmarshaller[HttpMessage, T]
type FromResponseUnmarshaller[T] = Unmarshaller[HttpResponse, T]
type FromRequestUnmarshaller[T] = Unmarshaller[HttpRequest, T]
type FromByteStringUnmarshaller[T] = Unmarshaller[ByteString, T]
type FromStringUnmarshaller[T] = Unmarshaller[String, T]
type FromStrictFormFieldUnmarshaller[T] = Unmarshaller[StrictForm.Field, T]
At its core an Unmarshaller[A, B] is very similar to a Function<A, CompletionStage<B>> and as such quite a bit simpler than its marshalling counterpart. The process of unmarshalling does not have to support content negotiation which saves two additional layers of indirection that are required on the marshalling side.
Predefined Unmarshallers
Akka HTTP already predefines a number of marshallers for the most common types. Specifically these are:
- PredefinedFromStringUnmarshallers
- Byte
- Short
- Int
- Long
- Float
- Double
- Boolean
- PredefinedFromEntityUnmarshallers
- Array[Byte]
- ByteString
- Array[Char]
- String
- akka.http.scaladsl.model.FormData
- GenericUnmarshallers
- Unmarshaller[T, T] (identity unmarshaller)
- Unmarshaller[Option[A], B], if an Unmarshaller[A, B] is available
- Unmarshaller[A, Option[B]], if an Unmarshaller[A, B] is available
Implicit Resolution
The unmarshalling infrastructure of Akka HTTP relies on a type-class based approach, which means that Unmarshaller instances from a certain type A to a certain type B have to be available implicitly.
The implicits for most of the predefined unmarshallers in Akka HTTP are provided through the companion object of the Unmarshaller trait. This means that they are always available and never need to be explicitly imported. Additionally, you can simply "override" them by bringing your own custom version into local scope.
Custom Unmarshallers
Akka HTTP gives you a few convenience tools for constructing unmarshallers for your own types. Usually you won't have to "manually" implement the Unmarshaller trait directly. Rather, it should be possible to use one of the convenience construction helpers defined on the Unmarshaller companion:
TODO rewrite sample for Java
/**
* Creates an `Unmarshaller` from the given function.
*/
def apply[A, B](f: ExecutionContext ⇒ A ⇒ Future[B]): Unmarshaller[A, B] =
withMaterializer(ec => _ => f(ec))
def withMaterializer[A, B](f: ExecutionContext ⇒ Materializer => A ⇒ Future[B]): Unmarshaller[A, B] =
new Unmarshaller[A, B] {
def apply(a: A)(implicit ec: ExecutionContext, materializer: Materializer) =
try f(ec)(materializer)(a)
catch { case NonFatal(e) ⇒ FastFuture.failed(e) }
}
/**
* Helper for creating a synchronous `Unmarshaller` from the given function.
*/
def strict[A, B](f: A ⇒ B): Unmarshaller[A, B] = Unmarshaller(_ => a ⇒ FastFuture.successful(f(a)))
/**
* Helper for creating a "super-unmarshaller" from a sequence of "sub-unmarshallers", which are tried
* in the given order. The first successful unmarshalling of a "sub-unmarshallers" is the one produced by the
* "super-unmarshaller".
*/
def firstOf[A, B](unmarshallers: Unmarshaller[A, B]*): Unmarshaller[A, B] = //...
Deriving Unmarshallers
Sometimes you can save yourself some work by reusing existing unmarshallers for your custom ones. The idea is to "wrap" an existing unmarshaller with some logic to "re-target" it to your type.
Usually what you want to do is to transform the output of some existing unmarshaller and convert it to your type. For this type of unmarshaller transformation Akka HTTP defines these methods:
- baseUnmarshaller.transform
- baseUnmarshaller.map
- baseUnmarshaller.mapWithInput
- baseUnmarshaller.flatMap
- baseUnmarshaller.flatMapWithInput
- baseUnmarshaller.recover
- baseUnmarshaller.withDefaultValue
- baseUnmarshaller.mapWithCharset (only available for FromEntityUnmarshallers)
- baseUnmarshaller.forContentTypes (only available for FromEntityUnmarshallers)
The method signatures should make their semantics relatively clear.
Using Unmarshallers
In many places throughput Akka HTTP unmarshallers are used implicitly, e.g. when you want to access the entity of a request using the Routing DSL.
However, you can also use the unmarshalling infrastructure directly if you wish, which can be useful for example in tests. The best entry point for this is the akka.http.scaladsl.unmarshalling.Unmarshal object, which you can use like this:
Contents


To set up your domain to point at your published site, add the following DNS records to
your domain. Replace host.example.com
with your site's hostname.
host.example.com IN CNAME hostname sandstorm-www.host.example.com IN TXT id
Note: If your site may get a lot of traffic, consider putting it behind a CDN. CloudFlare, for example, can do this for free.


WebEngineHistory QML Type
Provides data models that represent the history of a web engine page. More...
| Import Statement: | import QtWebEngine 1.5 |
| Since: | QtWebEngine 1.1 |
Properties
- backItems : WebEngineHistoryListModel
- forwardItems : WebEngineHistoryListModel
- items : WebEngineHistoryListModel
Detailed Description
The WebEngineHistory type can be accessed by using the WebEngineView.navigationHistory property.
The WebEngineHistory type provides the following WebEngineHistoryListModel data model objects:
backItems
, which contains the URLs of visited pages.forwardItems
, which contains the URLs of the pages that were visited after visiting the current page.items
, which contains the URLs of the back and forward items, as well as the URL of the current page.
The easiest way to use these models is to use them in a ListView as illustrated by the following code snippet:
ListView { id: historyItemsList anchors.fill: parent model: webEngineView.navigationHistory.items delegate: Text { color: "black" text: model.title + " - " + model.url + " (" + model.offset + ")" } }
The ListView shows the content of the corresponding model. The delegate is responsible for the format of the list items. The appearance of each item of the list in the delegate can be defined separately (it is not web engine specific).
The model roles title, url, and icon specify the title, URL, and favicon of the visited page. The offset role specifies the position of the page in respect to the current page (0). A positive number indicates that the page was visited after the current page, whereas a negative number indicates that the page was visited before the current page.
The data models can also be used to create a menu, as illustrated by the following code snippet:
toolBar: ToolBar { id: navigationBar RowLayout { anchors.fill: parent ToolButton { enabled: currentWebView && (currentWebView.canGoBack || currentWebView.canGoForward) menu:Menu { id: historyMenu Instantiator { model: currentWebView && currentWebView.navigationHistory.items MenuItem { text: model.title onTriggered: currentWebView.goBackOrForward(model.offset) checkable: !enabled checked: !enabled enabled: model.offset } onObjectAdded: historyMenu.insertItem(index, object) onObjectRemoved: historyMenu.removeItem(object) } } }
For the complete example, see WebEngine Quick Nano Browser.
See also WebEngineHistoryListModel.
Property Documentation
[read-only] backItems : WebEngineHistoryListModel |
URLs of visited pages.
[read-only] forwardItems : WebEngineHistoryListModel |
URLs of the pages that were visited after visiting the current page.
[read-only] items : WebEngineHistoryListModel |
URLs of back items, forward items, and the current item in the history.


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| Type | Account Number | Current Balance | Available Balance |
|---|---|---|---|
| Personal Checking | ****1337 | $9,000.01 | $9,000.01 |
| Platinum AARP Credit Card | ****4242 | $420.00 | $24,580.00 |
| Online Savings | ****1930 | $19,293.44 | $15,011.34 |
| Roth IRA | ****6141 | $86,753.09 | $87,482.10 |
| Fixed War Rate Bond | ****6969 | $11,420.98 | $12,492.10 |
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Learn More| Date | Description | Amount |
|---|---|---|
| APL*ITUNES.COM/BILL | -$50.00 | |
| Netflix | -$14.99 | |
| CandyCrush Checkout | -$13.37 | |
| Cheque #103 Deposit | $33.10 | |
| Social Security | $1,392.19 | |
| CandyCrush Checkout | -$13.37 | |
| AMZN MARKETPLACE | -$100.00 | |
| WINRAR/BILL | -$30.00 | |
| QVC*SHOPPING/BILL | -$140.50 | |
| Fashion Barn | -$333.50 | |
| McDonalds | -$18.20 |


I've always had an interest in building amazing things.
This passion was a mixture of building amazing things, logic, and technology; which resulted in me pursuing a major in civil engineering at Clemson University. Upon graduating in 2012, I worked on design teams building complex manufacturing plants, substations for wind turbine farms ,and rail lines to transport coal ash sustainability.
Even though these projects were interesting, I did not feel that my current work industry was as fast paced and inventive as I would like for it to be. Curiosity pushed me to take a week-long online tutorial for Javascript and I was in love! Building VIRTUAL amazing things? Being a part of an industry that is constantly innovating and growing seemed to be a perfect fit for my passions. Graduating from the fully immersive Web Developer program at Dev Bootcamp NYC July 2017, solidified this even more.
I am currently pursuing a full stack junior web development position at an organization that puts an emphasis on implementing cutting-edge technology and an inclusive environment for it's employees.
Please click any of the below for a display of my work.
BudgetGURU Mobile App MadLab Tracker App Command Line To Do List Simple Javascript Game


[
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]
Account
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Panels & Widgets
Extras
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2/8: Links that we'll use in class today...
- Record Attendance
- Workshop Guide
- A1 Assignment Sheet + Grading Rubric for your reference during workshop. Note the revised due date is Wed. 2/13 by 11:59pm.
- Resources for MLA 8 Citation Also, feel free to ask me for help during workshop. I'll be coming around to answer any individual questions.
Week 3: Identity & Community Online
This week, we'll continue our discussions about networked identities, specifically as it relates to social media. We'll also draft & workshop A1, which is due by 11:59pm on Sunday 2/10 via Canvas or email.
Readings for the week...
- Excerpts from Jaron Lanier's Who Owns the Future (Read the “Look Inside” preview for the introduction and first chapter; some pages are omitted, but get what you can out of this.)
- Interact with Blue Feed / Red Feed from the Wall Street Journal (Be sure the review the Methodology section)
- Watch TED Talk We're building a dystopia just to make people click on ads
- Watch TED Talk How we need to remake the internet
- And a few critiques of Lanier's arguments here:
- Michael Agger's Slate Article
- Comments archived on a Y-Combinator Forum
Note: For those TED Talks, don't be shy about increasing the play-back speed to 1.5x or even 2x -- both of those speakers talk quite slow and you might enjoy the talk more (and save a bit of time) if you speed it up.
To do...
- Complete Instigator 2, if you choose. Turn in via email by 9am on Wednesday.
- WORKSHOP A1: Draft A1 and be ready to turn in your draft before Friday's peer workshop. Come to class on Friday ready to give feedback to your peers.
- A1 DUE: Turn in your final draft of A1: Analysis of a Discourse Community by Wednesday 2/13 at 11:59pm on Canvas or via email. Remember that this assignment is worth 12% of your course grade.
- If you have any questions or concerns as you begin A1, don't hesitate to reach out during office hours or make an appointment with another consultant (other than Chase, since he is our TA) at the Writing Center.


Express Administrator
<% if (!user) { %>Welcome! Please log in.
<% } else { %>Hello, <%= user.username %>. View your profile.
View index Express-Dashbroad.
<% } %>Fast
Nearly 100x faster than popular web frameworks using Ruby and PHP. Admin is fast by every meaning of the word
Extensible
With middleware and javascript extensions, you can add custom functionality to admin that feels native


Person who is better at statistics than any software engineer and better at software engineering than any statistician.
You can have data without information, but you cannot have information without data.
Experience of applying sophisticated statistical tools and techniques to formulate and test hypothesis in real world data challenges.
Experience of developing and improving machine learning tools and algorithms. Formulated new innovative algorithms and metrics to solve analytics challenge with state of the art methods rather than using conventional ways
Experience of extracting new insights from big data by asking the right questions, manipulating data sets and visualizing findings in compelling ways


@import uk.gov.hmrc.govukfrontend.views.html.components._
@this(govukTable : GovukTable)
@()
The requirements to be a ROPS changed from 6 April 2017. You’ll need to check that the scheme you’re transferring to on or after that date meets the new requirements.
HMRC cannot guarantee these are ROPS or that any transfers to them will be free of UK tax. It’s your responsibility to find out if you have to pay tax on any transfer of pension savings. Find out more about Overseas pension schemes.
@govukTable(Table(
rows = Seq(
Seq(
TableRow(
content = Text("APK Pensionskasse AG")
),
TableRow(
content = Text("Austria")
)
),
Seq(
TableRow(
content = Text("Bonus Pensionskassen Aktiengesellschaft")
),
TableRow(
content = Text("Austria")
)
),
Seq(
TableRow(
content = Text("Sozialversicherungspensionskasse AG")
),
TableRow(
content = Text("Austria")
)
),
Seq(
TableRow(
content = Text("VBV-Pensionskasse Aktiengesellschaft")
),
TableRow(
content = Text("Austria")
)
)
),
head = Some(Seq(
HeadCell(
content = Text("ROPS")
),
HeadCell(
content = Text("Country")
)
))
))


public class PlumbingStreams
extends java.lang.Object
TStream
.
Methods that manipulate the flow of tuples in a streaming topology,
but are not part of the logic of the application.| Constructor and Description |
|---|
PlumbingStreams() |
| Modifier and Type | Method and Description |
|---|---|
static <T> TStream<java.util.List<T>> |
barrier(java.util.List<TStream<T>> streams)
A tuple synchronization barrier.
|
static <T> TStream<java.util.List<T>> |
barrier(java.util.List<TStream<T>> streams,
int queueCapacity)
A tuple synchronization barrier.
|
static <T> TStream<T> |
blockingDelay(TStream<T> stream,
long delay,
java.util.concurrent.TimeUnit unit)
Insert a blocking delay between tuples.
|
static <T> TStream<T> |
blockingOneShotDelay(TStream<T> stream,
long delay,
java.util.concurrent.TimeUnit unit)
Insert a blocking delay before forwarding the first tuple and
no delay for subsequent tuples.
|
static <T> TStream<T> |
blockingThrottle(TStream<T> stream,
long delay,
java.util.concurrent.TimeUnit unit)
Maintain a constant blocking delay between tuples.
|
static <T,U,R> TStream<R> |
concurrent(TStream<T> stream,
java.util.List<Function<TStream<T>,TStream<U>>> pipelines,
Function<java.util.List<U>,R> combiner)
Perform analytics concurrently.
|
static <T,U,R> TStream<R> |
concurrentMap(TStream<T> stream,
java.util.List<Function<T,U>> mappers,
Function<java.util.List<U>,R> combiner)
Perform analytics concurrently.
|
static <T> TStream<T> |
gate(TStream<T> stream,
java.util.concurrent.Semaphore semaphore)
Control the flow of tuples to an output stream.
|
static <T> TStream<T> |
isolate(TStream<T> stream,
boolean ordered)
Isolate upstream processing from downstream processing.
|
static <T> TStream<T> |
isolate(TStream<T> stream,
int queueCapacity)
Isolate upstream processing from downstream processing.
|
static <T,R> TStream<R> |
parallel(TStream<T> stream,
int width,
ToIntFunction<T> splitter,
BiFunction<TStream<T>,java.lang.Integer,TStream<R>> pipeline)
Perform an analytic pipeline on tuples in parallel.
|
static <T,R> TStream<R> |
parallelBalanced(TStream<T> stream,
int width,
BiFunction<TStream<T>,java.lang.Integer,TStream<R>> pipeline)
Perform an analytic pipeline on tuples in parallel.
|
static <T,U> TStream<U> |
parallelMap(TStream<T> stream,
int width,
ToIntFunction<T> splitter,
BiFunction<T,java.lang.Integer,U> mapper)
Perform an analytic function on tuples in parallel.
|
static <T,K> TStream<T> |
pressureReliever(TStream<T> stream,
Function<T,K> keyFunction,
int count)
Relieve pressure on upstream processing by discarding tuples.
|
static <T> ToIntFunction<T> |
roundRobinSplitter(int width)
A round-robin splitter ToIntFunction
|
public static <T> TStream<T> blockingDelay(TStream<T> stream, long delay, java.util.concurrent.TimeUnit unit)
delay
.
Delays less than 1msec are translated to a 0 delay.
This function always adds the delay
amount after receiving
a tuple before forwarding it.
Downstream tuple processing delays will affect the overall delay of a subsequent tuple.
e.g., the input stream contains two tuples t1 and t2 and
the delay is 100ms. The forwarding of t1 is delayed by 100ms.
Then if a downstream processing delay of 80ms occurs, this function
receives t2 80ms after it forwarded t1 and it will delay another
100ms before forwarding t2. Hence the overall delay between forwarding
t1 and t2 is 180ms.
See blockingThrottle
.
stream
- Stream tdelay
- Amount of time to delay a tuple.unit
- Time unit for delay
.public static <T> TStream<T> blockingThrottle(TStream<T> stream, long delay, java.util.concurrent.TimeUnit unit)
delay
.
Delays less than 1msec are translated to a 0 delay.
Sample use:
TStream<String> stream = topology.strings("a", "b, "c");
// Create a stream with tuples throttled to 1 second intervals.
TStream<String> throttledStream = blockingThrottle(stream, 1, TimeUnit.SECOND);
// print out the throttled tuples as they arrive
throttledStream.peek(t -> System.out.println(new Date() + " - " + t));
The function adjusts for downstream processing delays.
The first tuple is not delayed. If delay
has already
elapsed since the prior tuple was forwarded, the tuple
is forwarded immediately.
Otherwise, forwarding the tuple is delayed to achieve
a delay
amount since forwarding the prior tuple.
e.g., the input stream contains two tuples t1 and t2 and the delay is 100ms. The forwarding of t1 is delayed by 100ms. Then if a downstream processing delay of 80ms occurs, this function receives t2 80ms after it forwarded t1 and it will only delay another 20ms (100ms - 80ms) before forwarding t2. Hence the overall delay between forwarding t1 and t2 remains 100ms.
T
- tuple typestream
- the stream to throttledelay
- Amount of time to delay a tuple.unit
- Time unit for delay
.public static <T> TStream<T> blockingOneShotDelay(TStream<T> stream, long delay, java.util.concurrent.TimeUnit unit)
Delays less than 1msec are translated to a 0 delay.
Sample use:
TStream<String> stream = topology.strings("a", "b, "c");
// create a stream where the first tuple is delayed by 5 seconds.
TStream<String> oneShotDelayedStream =
stream.map( blockingOneShotDelay(5, TimeUnit.SECONDS) );
T
- tuple typestream
- input streamdelay
- Amount of time to delay a tuple.unit
- Time unit for delay
.public static <T,K> TStream<T> pressureReliever(TStream<T> stream, Function<T,K> keyFunction, int count)
Any downstream processing of the returned stream is isolated
from stream
so that any slow down does not affect stream
.
When the downstream processing cannot keep up with rate of
stream
tuples will be dropped from returned stream.
Up to count
of the most recent tuples per key from stream
are maintained when downstream processing is slow, any older tuples
that have not been submitted to the returned stream will be discarded.
Tuple order is maintained within a partition but is not guaranteed to
be maintained across partitions.
T
- Tuple type.K
- Key type.stream
- Stream to be isolated from downstream processing.keyFunction
- Function defining the key of each tuple.count
- Maximum number of tuples to maintain when downstream processing is backing up.stream
.isolate
public static <T> TStream<T> isolate(TStream<T> stream, boolean ordered)
OutOfMemoryExceptions
if the processing against returned stream cannot keep up
with the arrival rate of tuples on stream
.stream
- Stream to be isolated from downstream processing.ordered
- true
to maintain arrival order on the returned stream,
false
to not guaranteed arrival order.stream
.public static <T> TStream<T> isolate(TStream<T> stream, int queueCapacity)
If the processing against the returned stream cannot keep up
with the arrival rate of tuples on stream
, upstream
processing will block until there is space in the queue between
the streams.
Processing of tuples occurs in the order they were received.
stream
- Stream to be isolated from downstream processing.queueCapacity
- size of the queue between stream
and
the returned stream.stream
.pressureReliever
public static <T,U,R> TStream<R> concurrentMap(TStream<T> stream, java.util.List<Function<T,U>> mappers, Function<java.util.List<U>,R> combiner)
This is a convenience function that calls
concurrent(TStream, List, Function)
after
creating pipeline
and combiner
functions
from the supplied mappers
and combiner
arguments.
That is, it is logically, if not exactly, the same as:
List<Function<TStream<T>,TStream<U>>> pipelines = new ArrayList<>();
for (Function<T,U> mapper : mappers)
pipelines.add(s -> s.map(mapper));
concurrent(stream, pipelines, combiner);
T
- Tuple type on input stream.U
- Tuple type generated by mappers.R
- Tuple type of the result.stream
- input streammappers
- functions to be run concurrently. Each mapper MUST
return a non-null result.
A runtime error will be generated if a null result
is returned.combiner
- function to create a result tuple from the list of
results from mappers
.
The input list order is 1:1 with the mappers
list.
I.e., list entry [0] is the result from mappers[0],
list entry [1] is the result from mappers[1], etc.public static <T,U,R> TStream<R> concurrent(TStream<T> stream, java.util.List<Function<TStream<T>,TStream<U>>> pipelines, Function<java.util.List<U>,R> combiner)
Process input tuples one at at time, invoking the specified
analytics (pipelines
) concurrently, combine the results,
and then process the next input tuple in the same manner.
Logically, instead of doing this:
sensorReadings<T> -> A1 -> A2 -> A3 -> results<R>
create a graph that's logically like this:
-
|-> A1 ->|
sensorReadings<T> -> |-> A2 ->| -> results<R>
|-> A3 ->|
more specifically a graph like this:
-
|-> isolate(1) -> pipeline1 -> |
stream -> |-> isolate(1) -> pipeline2 -> |-> barrier(10) -> combiner
|-> isolate(1) -> pipeline3 -> |
. . .
The typical use case for this is when an application has a collection of independent analytics to perform on each tuple and the analytics are sufficiently long running such that performing them concurrently is desired.
Note, this is in contrast to "parallel" stream processing, which in Java8 Streams and other contexts means processing multiple tuples in parallel, each on a replicated processing pipeline.
Threadsafety - one of the following must be true:
stream
are threadsafepipelines
do not modify the input tuplespipelines
provide their own synchronization controls
to protect concurrent modifications of the input tuples
Logically, a thread is allocated for each of the pipelines
.
The actual degree of concurrency may be TopologyProvider
dependent.
T
- Tuple type on input stream.U
- Tuple type generated by pipelines.R
- Tuple type of the result.stream
- input streampipelines
- a list of functions to add a pipeline to the topology.
Each pipeline.apply()
is called with stream
as the input, yielding the pipeline's result stream.
For each input tuple, a pipeline MUST create exactly one output tuple.
Tuple flow into the pipelines will cease if that requirement
is not met.combiner
- function to create a result tuple from the list of
results from pipelines
.
The input tuple list's order is 1:1 with the pipelines
list.
I.e., list entry [0] is the result from pipelines[0],
list entry [1] is the result from pipelines[1], etc.barrier
public static <T> TStream<java.util.List<T>> barrier(java.util.List<TStream<T>> streams)
Same as barrier(others, 1)
barrier(List, int)
public static <T> TStream<java.util.List<T>> barrier(java.util.List<TStream<T>> streams, int queueCapacity)
A barrier has n input streams with tuple type T
and one output stream with tuple type List<T>
.
Once the barrier receives one tuple on each of its input streams,
it generates an output tuple containing one tuple from each input stream.
It then waits until it has received another tuple from each input stream.
Input stream 0's tuple is in the output tuple's list[0], stream 1's tuple in list[1], and so on.
The barrier's output stream is isolated from the input streams.
The barrier has a queue of size queueCapacity
for each
input stream. When a tuple for an input stream is received it is
added to its queue. The stream will block if the queue is full.
T
- Type of the tuple.streams
- the list of input streamsqueueCapacity
- the size of each input stream's queueBarrier
public static <T,U> TStream<U> parallelMap(TStream<T> stream, int width, ToIntFunction<T> splitter, BiFunction<T,java.lang.Integer,U> mapper)
Same as parallel(stream, width, splitter, (s,ch) -> s.map(t -> mapper.apply(t, ch))
stream
- input streamsplitter
- the tuple channel allocation functionmapper
- analytic functionwidth
- number of channelsroundRobinSplitter
,
concurrentMap
public static <T,R> TStream<R> parallel(TStream<T> stream, int width, ToIntFunction<T> splitter, BiFunction<TStream<T>,java.lang.Integer,TStream<R>> pipeline)
Splits stream
into width
parallel processing channels,
partitioning tuples among the channels using splitter
.
Each channel runs a copy of pipeline
.
The resulting stream is isolated from the upstream parallel channels.
stream
is not maintained in the
results from parallel
.
pipeline
is not required to yield a result for each input
tuple.
A common splitter function is a roundRobinSplitter
.
The generated graph looks like this:
-
|-> isolate(10) -> pipeline-ch1 -> |
stream -> split(width,splitter) -> |-> isolate(10) -> pipeline-ch2 -> |-> union -> isolate(width)
|-> isolate(10) -> pipeline-ch3 -> |
. . .
T
- Input stream tuple typeR
- Result stream tuple typestream
- the input streamwidth
- number of parallel processing channelssplitter
- the tuple channel allocation functionpipeline
- the pipeline for each channel.
pipeline.apply(inputStream,channel)
is called to generate the pipeline for each channel.roundRobinSplitter
,
concurrent
public static <T,R> TStream<R> parallelBalanced(TStream<T> stream, int width, BiFunction<TStream<T>,java.lang.Integer,TStream<R>> pipeline)
Splits stream
into width
parallel processing channels,
partitioning tuples among the channels in a load balanced fashion.
Each channel runs a copy of pipeline
.
The resulting stream is isolated from the upstream parallel channels.
stream
is not maintained in the
results from parallel
.
A pipeline
MUST yield a result for each input
tuple. Failure to do so will result in the channel remaining
in a busy state and no longer available to process additional tuples.
A LoadBalancedSplitter
is used to distribute tuples.
The generated graph looks like this:
-
|-> isolate(1) -> pipeline-ch1 -> peek(splitter.channelDone()) -> |
stream -> split(width,splitter) -> |-> isolate(1) -> pipeline-ch2 -> peek(splitter.channelDone()) -> |-> union -> isolate(width)
|-> isolate(1) -> pipeline-ch3 -> peek(splitter.channelDone()) -> |
. . .
Note, this implementation requires that the splitter is used from
only a single JVM. The DirectProvider
provider meets this requirement.
T
- Input stream tuple typeR
- Result stream tuple typestream
- the input streamwidth
- number of parallel processing channelspipeline
- the pipeline for each channel.
pipeline.apply(inputStream,channel)
is called to generate the pipeline for each channel.parallel(TStream, int, ToIntFunction, BiFunction)
,
LoadBalancedSplitter
public static <T> ToIntFunction<T> roundRobinSplitter(int width)
The splitter function cycles among the width
channels
on successive calls to roundRobinSplitter.applyAsInt()
,
returning 0, 1, ..., width-1, 0, 1, ..., width-1
.
TStream.split
,
parallel
public static <T> TStream<T> gate(TStream<T> stream, java.util.concurrent.Semaphore semaphore)
A Semaphore
is used to control the flow of tuples
through the gate
. The gate acquires a permit from the
semaphore to pass the tuple through, blocking until a permit is
acquired (and applying backpressure upstream while blocked).
Elsewhere, some code calls Semaphore.release(int)
to make permits available.
If a TopologyProvider is used that can distribute a topology's streams to different JVM's the gate and the code releasing the permits must be in the same JVM.
Sample use:
Suppose you wanted to control processing such that concurrent
pipelines processed each tuple in lock-step.
I.e., You want all of the pipelines to start processing a tuple
at the same time and not start a new tuple until the current
tuple had been fully processed by each of them:
TStream<Integer> readings = ...;
Semaphore gateControl = new Semaphore(1); // allow the first to pass through
TStream<Integer> gated = gate(readings, gateControl);
// Create the concurrent pipeline combiner and have it
// signal that concurrent processing of the tuple has completed.
// In this sample the combiner just returns the received list of
// each pipeline result.
Function<TStream<List<Integer>>,TStream<List<Integer>>> combiner =
stream -> stream.map(
list -> { * gateControl.release(); * return list; * }
);
TStream<List<Integer>> results = PlumbingStreams.concurrent(gated, pipelines, combiner);
stream
- the input streamsemaphore
- gate controlCopyright © 2016 The Apache Software Foundation. All Rights Reserved - d6cdfc6-20160517-0028


Automated testing of software is an essential tool in development. Unit tests are the basic building blocks for automated tests: each component, the unit, of software is accompanied by a test that can be run by a test runner over and over again without any human interaction. In other words, you can write a test once and run it as often as necessary without any additional cost.
In addition to the benefits of good test coverage, testing can also drive the design of software, known as test-driven design, where a test is written before an implementation. You start writing a very simple test, verify that it fails (because the code to be tested doesn't exist yet), and then write the necessary implementation until the test passes. Once that happens, you extend the test to cover more of the desired functionality and implement again. By repeating those steps, the resulting code looks usually much different from what you'd get by starting with the implementation.
Unit testing in JavaScript isn't much different from in other programming languages. You need a small framework that provides a test runner, as well as some utilities to write the actual tests.
You want to automate testing your applications and frameworks, maybe even benefit from test-driven design. Writing your own testing framework may be tempting, but it involves a lot of work to cover all the details and special requirements of testing JavaScript code in various browsers.
While there are other unit testing frameworks for JavaScript, you've decided to check out QUnit. QUnit is jQuery's unit test framework and is used by a wide variety of projects.
To use QUnit, you only need to include two QUnit files on your HTML page. QUnit consists of qunit.js
, the test runner and testing framework, and qunit.css
, which styles the test suite page to display test results:
@partial(resources/example-cookbook-1-basics.html)
Opening this file in a browser gives the result shown below:
The only markup necessary in the
element is a

with id="qunit-fixture"
. This is required for all QUnit tests, even when the element itself is empty. This provides the fixture for tests, which will be explained in the section called "Keeping Tests Atomic".
The interesting part is the


Salmon Cookies
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Please come to our branches
Seattle
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Lima


{% extends "dashboard_z/www/templates/base.html" %} {% block title %} Dashboard {% endblock %} {% block content %}
.btn-primary
.btn-secondary
.btn-default
.btn-success
.btn-info
.btn-warning
.btn-danger
Add class .btn-outline
| .btn-outline-inverse
to get outlined buttons.
You can use the following class combinations:
.btn-link
.btn-link.btn-link-light
.btn-link.btn-link-text
Use class .btn-link-underline
to emphasize a button while hovering.
Use .btn-lg
, .btn-sm
, .btn-xs
for fast change button size.
.btn-block
will make your button full-width unit.
Wrap a series of buttons into groups.
Wrap a series of buttons with .btn
in .btn-group
.
Combine sets of .btn-group
into a .btn-toolbar
for more complex components.
Make a set of buttons appear vertically stacked rather than horizontally
(.btn-group-vertical
).
Instead of applying button sizing classes to every button in a group, just add
.btn-group-*
to each .btn-group
, including when nesting multiple groups.
Place a .btn-group
within another .btn-group
when you want
dropdown menus mixed with a series of buttons.


Contacts Bank
Are you sure you want to remove contact ({{selectedContact.details.firstName + " " + selectedContact.details.lastName}}) ?


gfortran
Preprocess and compile Fortran source files, then assemble and link them together.
More information: home page
- Compile multiple source files into an executable:
gfortran path/to/source1.f90 path/to/source2.f90 ... -o path/to/output_executable
- Show common warnings, debug symbols in output, and optimize without affecting debugging:
gfortran path/to/source.f90 -Wall -g -Og -o path/to/output_executable
- Include libraries from a different path:
gfortran path/to/source.f90 -o path/to/output_executable -Ipath/to/mod_and_include -Lpath/to/library -llibrary_name
- Compile source code into Assembler instructions:
gfortran -S path/to/source.f90
- Compile source code into an object file without linking:
gfortran -c path/to/source.f90


SILENT PARTNER (a film review by Mark R. Leeper)
CAPSULE: This is a film from Australia with overtones of David Mamet and of OF MICE AND MEN. Two low-lifes get a chance to groom a greyhound for racing for a gangster. They want to parlay this into a stab at the good life. SILENT PARTNER is basically a two-character play adapted to the screen. Rating: 6 (0 to 10), high +1 (-4 to +4)
SILENT PARTNER is a two-person play adapted to the screen with virtually no dialog from anyone but John and Bill (played David Field and Syd Brisbane). They are two lowlifes with dreams who live mostly on borrowed money and spend it on beer and the occasional bet at the dog track. Through thick accents and drunken talk we follow them as they have a shot at the big time. A shady kingpin, Alex Silver, sees them at the racetrack and decides to use them in a scheme involving dog racing. Silver wants John and Bill to buy a greyhound, care for her, and race her locally. He will give them the money to tend the dog in return for 70% of the dog's winnings. The drunken pair name the dog "Silent Partner" after Silver's role in the deal. Bill develops a genuine affection for the dog. Bill's outings training the dog are some of the few scenes where we see him sober and we see John sober in even fewer, yet Bill lets John run the show and allows himself to become almost a silent partner. John never doubts he has what it takes to swim with the sharks. Through the alcohol haze John thinks he is smart and worldly, though frequently his skill seems limited to knowing whom he can hit up for one of the ever decreasing loans. The two have little social life without each other and it rarely is at anyplace but bars, the track, the squalid filthy house, and the occasional peep show. People like John and Bill are unusual subjects for film, thank goodness.
The timing of the dialog is a little too perfect to be believed as the two talk with nearly perfect timing. The Daniel Keene's dialog, based on his own play, is unnaturally perfect, much as David Mamet might craft it. Mamet might also approve of the underbelly society and grimy settings. Director Alkinos Tsilimidos filmed SILENT PARTNER almost linearly to create more natural emotions from his actors, but he kept crew ignorant of the script to aid in spontaneity. The film was shot for an amazing $7000 US.
Technically, the film is probably a comedy but it is not the kind of comedy that generates laughter. More frequently it is just an exercise in bitter irony. The songs by Paul Kelly are, like the dialog, a little too perfect. In some cases the songs give away plot that is coming. Americans will likely have some problems picking up the entire dialog. That can be a problem since Silver's plan is never clearly explained.
 I rate it a 6 on the 0 to 10 scale and a high +1 on the -4 to +4 scale.
Mark R. Leeper<EMAIL_ADDRESS>Copyright 2001 Mark R. Leeper
========== X-RAMR-ID: 29806 X-Language: en X-RT-AuthorID: 1309 X-RT-RatingText: 6/10
The review above was posted to the
rec.arts.movies.reviews newsgroup (de.rec.film.kritiken for German reviews).
The Internet Movie Database accepts no responsibility for the contents of the
review and has no editorial control. Unless stated otherwise, the copyright
belongs to the author.
Please direct comments/criticisms of the review to relevant newsgroups.
Broken URLs inthe reviews are the responsibility of the author.
The formatting of the review is likely to differ from the original due
to ASCII to HTML conversion.
Related links: index of all rec.arts.movies.reviews reviews


Handwritten Digit Recognition with Intel's DLRS
Interactive handwritten digit recognition using PyTorch, running on an Intel Deep Learning Reference Stack (DLRS) backend. See clearlinux.org for more information.
{{optText if optText is not none}}


| Beej's Guide to Network Programming | ||
|---|---|---|
| Prev |
Well, that's the lot of it. Hopefully at least some of the information contained within this document has been remotely accurate and I sincerely hope there aren't any glaring errors. Well, sure, there always are.
So, let this be a warning to you! I'm sorry if any inaccuracies contained herein have caused you any grief, but you just can't hold me accountable. See, I don't stand behind a single word of this document, legally speaking. The whole thing could be completely and utterly wrong!
But it's probably not. After all, I've spent many many hours messing with this stuff, and implemented several TCP/IP network utilities at work, have written multiplayer game engines, and so on. But I'm not the sockets god; I'm just some guy.
By the way, if anyone has any constructive (or destructive) criticism about this document, please send mail to<EMAIL_ADDRESS>and I'll try to make an effort to set the record straight.
In case you're wondering why I did this, well, I did it for the money. Ha! No, really, I did it because a lot of people have asked me socket-related questions and when I tell them I've been thinking about putting together a socket page, they say, "Cool!" Besides, I feel that all this hard-earned knowledge is going to waste if I can't share it with others. The web just happens to be the perfect vehicle. I encourage others to provide similar information whenever possible.
Enough of this--back to coding! ;-)


The Open Web Application Security Project (OWASP) .
History
The Open Web Application Security Project (OWASP) is an open community dedicated to enabling organizations to develop, purchase, and maintain applications and APIs that can be trusted
What is OWASP?
OWASP is a new kind of organization. Their freedom from commercial pressures allows us to provide unbiased, practical, and cost-effective information about application security.


Checks if the input 'reference in' is of the same class or a subclass of the input 'is object instance of'.
|
reference in Object reference in. |
|
is object instance of Object to use a reference when checking the object reference in. |
|
is instance of Object is of the same class or a more specified class as the 'is object instance of' reference. |
|
reference out Object reference out. |


Hi. I'm Teejay. I spend my time designing and developing products, whether original music, an ebook, or a web application. I believe that creativity is the cure for our culture's consumption-oriented condition.
Ruby microframework for accepting credit card payments in just ten lines of code.
75 icons for use in your web or mobile project.
Live a happier life with less.
Harness your inner creativity and be happier than you've ever been!
A bird's-eye view of music events in Portland, Oregon.
The acclaimed sinister debut album of Portland electronic musician Elias Moniker.


@defining("Scala & Angular Home") { title => @layout(title) {
This is a sample application of how to use Scala with Angular effectively


Mompha’s Instagram Account Re-activated As He Remains In Custody
by Gbenga SijuadeThe Instagram account of embattled Dubai-based Nigerian social media celebrity, Ismaila Mustapha a.k.a Mompha has been reactivated after its initial deactivation.
Naija News recalls that Mompha who is still in detention was arrested for alleged internet fraud and money laundering which caused many to believe that it was the Economic and Financial Crimes Commission (EFCC) that took down the Instagram account.
Today, it has been observed that the Instagram account is back, with his media files; photos and videos, still intact.
Naija News recalls that the EFCC also arrested the voodoo-loving’ Lebanese accomplice of embattled Dubai-based Nigerian social media celebrity, Ismaila Mustapha a.k.a Mompha.


Karim Benzema hits out at continued French exile
by AFPReal Madrid striker Karim Benzema has told French Football Federation president Noel Le Graet he and he alone will decide when the time to end his international retirement has come.
After Real coach Zinedine Zidane called for Benzema's four-year France exile, caused by his alleged part in an attempt to blackmail Mathieu Valbuena, to end this week,
Le Graet told French radio Benzema's adventure with the French team was finished.
"Noel, I thought you didn't interfere with the decisions of the France coach," said Benzema on Twitter.
"Please understand that I and I alone will call an end to my international career." Benzema, who is of Algerian origin, added that Le Graet should "let me play for one of the countries for which I'm eligible" if he thinks the 31-year-old is done.
Benzema has not played for France since 2015, when he was placed under formal investigation over the blackmail attempt.
Coach Didier Deschamps has maintained Benzema's omission is in the best interests of the French squad, who won last year's World Cup without him.
Benzema has scored 9 goals in 11 La Liga appearances for Madrid already this season.
"He has always wanted to play for France," Zidane said this week.
"He is the best and I think he should definitely have a place in the national team. Football-wise, there is no debate."