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Chris Manning,
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<quiz> <metadata> <title>Maxent Model and Named Entity Recognition</title> <open_time>2012-03-31 0001</open_time> <soft_close_time>2012-04-17 2359</soft_close_time> <hard_close_time>2012-05-22 2359</hard_close_time> <duration>0</duration> <retry_delay>10</retry_delay> <maximum_submissions>5</maximum_submissions> <modified_time>1335393991259</modified_time> <parameters> <show_explanations> <question>after_hard_close_time</question> <option>before_soft_close_time</option> <score>before_soft_close_time</score> </show_explanations> </parameters> <maximum_score>5</maximum_score> </metadata> <preamble><![CDATA[]]></preamble> <data> <question_groups> <question_group select="1"> <preamble><![CDATA[]]></preamble> <question id="e11995d54691c8f2e0a9edb6bcec5edc" type="GS_Choice_Answer_Question"> <metadata> <parameters> <rescale_score>1</rescale_score> <choice_type>radio</choice_type> </parameters> </metadata> <data> <text><![CDATA[We surveyed cancer types from 569 patients in a cancer hospital and found the gender distribution of patients who have and don't have hodgkins lymphoma. What is the joint probability P(female, lymphoma) and conditional probability P(female|lymphoma)?

	Lymphoma	No Lymphoma

Male	59	230

Female	10	270

]]></text> <explanation><![CDATA[$$P(female, lymphoma) = \frac{10}{569} = 0.018$$

 $$P(female | lymphoma) = \frac{10}{59 + 10} = 0.145$$]]></explanation> <option_groups randomize="true"> <option_group select="all"> <option id="ab8a821e1035425caf4deb412fc64f6c" selected_score="1" unselected_score="0"> <text><![CDATA[0.018, 0.145]]></text> <explanation><![CDATA[Correct!]]></explanation> </option> <option id="e9c60d6828c14053f8bc83253eee9005" selected_score="0" unselected_score="0"> <text><![CDATA[0.104, 0.855]]></text> <explanation><![CDATA[Make sure that you have the right numerators for both probabilities.]]></explanation> </option> <option id="e7cfc86728417ea534fae17e3ef057d9" selected_score="0" unselected_score="0"> <text><![CDATA[0.018, 0.036]]></text> <explanation><![CDATA[The denominator for the conditional probability is the number of people who have lymphoma]]></explanation> </option> <option id="d7d5a7c71c2318a0a54617fdb3b77703" selected_score="0" unselected_score="0"> <text><![CDATA[0.036, 0.145]]></text> <explanation><![CDATA[The denominator for the joint probability is the total number of patients]]></explanation> </option> </option_group> </option_groups> </data> </question> <question id="81c61432eed870946199dbec8bab9c53" type="GS_Choice_Answer_Question"> <metadata> <parameters> <rescale_score>1</rescale_score> <choice_type>radio</choice_type> </parameters> </metadata> <data> <text><![CDATA[We surveyed cancer types from 502 patients in a cancer hospital and found the gender distribution of patients who have and don't have hodgkins lymphoma. What is the joint probability P(female, lymphoma) and conditional probability P(female|lymphoma)?

	Lymphoma	No Lymphoma

Male	52	200

Female	10	240

]]></text> <explanation><![CDATA[$$P(female, lymphoma) = \frac{10}{502} = 0.020$$

 $$P(female | lymphoma) = \frac{10}{52 + 10} = 0.161$$]]></explanation> <option_groups randomize="true"> <option_group select="all"> <option id="29e26db01cb25f77978a04ccd88b0c1f" selected_score="1" unselected_score="0"> <text><![CDATA[0.020, 0.161]]></text> <explanation><![CDATA[Correct!]]></explanation> </option> <option id="e26720ee1ac3079f734ac5f1c03b59b3" selected_score="0" unselected_score="0"> <text><![CDATA[0.104, 0.839]]></text> <explanation><![CDATA[Make sure that you have the right numerators for both probabilities.]]></explanation> </option> <option id="0329638bdcf60e392db6d8af9fca16cb" selected_score="0" unselected_score="0"> <text><![CDATA[0.020, 0.040]]></text> <explanation><![CDATA[The denominator for the conditional probability is the number of people who have lymphoma]]></explanation> </option> <option id="4f61773f5ae0225d0c1ab8473bc96516" selected_score="0" unselected_score="0"> <text><![CDATA[0.040, 0.161]]></text> <explanation><![CDATA[The denominator for the joint probability is the total number of patients]]></explanation> </option> </option_group> </option_groups> </data> </question> <question id="826d796fb5c63d9f39f4023daaf7cf15" type="GS_Choice_Answer_Question"> <metadata> <parameters> <rescale_score>1</rescale_score> <choice_type>radio</choice_type> </parameters> </metadata> <data> <text><![CDATA[We surveyed cancer types from 266 patients in a cancer hospital and found the gender distribution of patients who have and don't have hodgkins lymphoma. What is the joint probability P(female, lymphoma) and conditional probability P(female|lymphoma)?

	Lymphoma	No Lymphoma

Male	26	100

Female	10	130

]]></text> <explanation><![CDATA[$$P(female, lymphoma) = \frac{10}{266} = 0.038$$

 $$P(female | lymphoma) = \frac{10}{26 + 10} = 0.278$$]]></explanation> <option_groups randomize="true"> <option_group select="all"> <option id="c7cf1760bda1945154cbc1a3142f3023" selected_score="1" unselected_score="0"> <text><![CDATA[0.038, 0.278]]></text> <explanation><![CDATA[Correct!]]></explanation> </option> <option id="78170b98ee93d8fdacb00cc2b57c463a" selected_score="0" unselected_score="0"> <text><![CDATA[0.098, 0.722]]></text> <explanation><![CDATA[Make sure that you have the right numerators for both probabilities.]]></explanation> </option> <option id="7f51cc90a7dfd0483c61523f8f1f0f3f" selected_score="0" unselected_score="0"> <text><![CDATA[0.038, 0.071]]></text> <explanation><![CDATA[The denominator for the conditional probability is the number of people who have lymphoma]]></explanation> </option> <option id="fbba377814dfd44ce8523ae295730ef4" selected_score="0" unselected_score="0"> <text><![CDATA[0.071, 0.278]]></text> <explanation><![CDATA[The denominator for the joint probability is the total number of patients]]></explanation> </option> </option_group> </option_groups> </data> </question> </question_group> <question_group select="1"> <preamble><![CDATA[]]></preamble> <question id="418e72e34589f9ea2569c4063dc016d3" type="GS_Choice_Answer_Question"> <metadata> <parameters> <rescale_score>1</rescale_score> <choice_type>radio</choice_type> </parameters> </metadata> <data> <text><![CDATA[In the maxent model, we've learned that P(c|d,λ) = expΣλifi(c,d)/ΣexpΣλifi(c',d). This equation is also in the lecture slide #25. Given the 3 classes and the 3 features, compute the following probabilities. wi = "Goéric"

P(PERSON | by Goéric) =

P(LOCATION | by Goéric) =

P(DRUG | by Goéric) =

Weight	Feature

 1.8	f1(c, d) = [c = LOCATION & wi-1 = in & isCapitalized(wi)]

-0.6	f2(c, d) = [c = LOCATION & hasAccentedLatinChar(wi)]

 0.3	f3(c, d) = [c = DRUG & ends(wi, c)]

 ]]></text> <explanation><![CDATA[

P(PERSON | by Goéric) = e0 / (e0 + e-0.6 + e0.3) = 0.34

P(LOCATION | by Goéric) = e-0.6 / (e0 + e-0.6 + e0.3) = 0.19

P(DRUG | by Goéric) = e0.3 / (e0 + e-0.6 + e0.3) = 0.47

]]></explanation> <option_groups randomize="true"> <option_group select="all"> <option id="0fc9130d7ba2b11c018aa14f68bb2789" selected_score="1" unselected_score="0"> <text><![CDATA[0.34, 0.19, 0.47]]></text> <explanation><![CDATA[Correct!]]></explanation> </option> <option id="2b9a37fd74b230ea2726df24f7d6307c" selected_score="0" unselected_score="0"> <text><![CDATA[0.18, 0.59, 0.24]]></text> <explanation><![CDATA[f1 must not be counted towards P(LOCATION | by Goéric) because Goéric is not preceded by "in".]]></explanation> </option> <option id="42262855fd0adade6c539d3ef356a30e" selected_score="0" unselected_score="0"> <text><![CDATA[0.44, 0.24, 0.32]]></text> <explanation><![CDATA[f2 must be only counted towards the class LOCATION due to its condition, c = LOCATION.]]></explanation> </option> <option id="81938347c1415c2be9403f2c3125ecec" selected_score="0" unselected_score="0"> <text><![CDATA[0.10, 0.06, 0.84]]></text> <explanation><![CDATA[f1 must not be counted towards P(DRUG| by Goéric) because Goéric is not preceded by "in".]]></explanation> </option> </option_group> </option_groups> </data> </question> <question id="d02eb25a097293cd0fd92c08ade6427e" type="GS_Choice_Answer_Question"> <metadata> <parameters> <rescale_score>1</rescale_score> <choice_type>radio</choice_type> </parameters> </metadata> <data> <text><![CDATA[In the maxent model, we've learned that P(c|d,λ) = expΣλifi(c,d)/ΣexpΣλifi(c',d). This equation is also in the lecture slide #25. Given the 3 classes and the 3 features, compute the following probabilities. wi = "Goéric"

P(PERSON | by Goéric) =

P(LOCATION | by Goéric) =

P(DRUG | by Goéric) =

Weight	Feature

 1.2	f1(c, d) = [c = LOCATION & wi-1 = in & isCapitalized(wi)]

-0.3	f2(c, d) = [c = LOCATION & hasAccentedLatinChar(wi)]

 0.4	f3(c, d) = [c = DRUG & ends(wi, c)]

 ]]></text> <explanation><![CDATA[

P(PERSON | by Goéric) = e0 / (e0 + e-0.3 + e0.4) = 0.31

P(LOCATION | by Goéric) = e-0.3 / (e0 + e-0.3 + e0.4) = 0.23

P(DRUG | by Goéric) = e0.4 / (e0 + e-0.3 + e0.4) = 0.46

]]></explanation> <option_groups randomize="true"> <option_group select="all"> <option id="3d5776f9da7f55747a9c0e47de66a3cf" selected_score="1" unselected_score="0"> <text><![CDATA[0.31, 0.23, 0.46]]></text> <explanation><![CDATA[Correct!]]></explanation> </option> <option id="dbd27f209019f0f9a864b318998b8c12" selected_score="0" unselected_score="0"> <text><![CDATA[0.20, 0.50, 0.30]]></text> <explanation><![CDATA[f1 must not be counted towards P(LOCATION | by Goéric) because Goéric is not preceded by "in".]]></explanation> </option> <option id="42760f00ce2a84680e7aa66fe59517db" selected_score="0" unselected_score="0"> <text><![CDATA[0.35, 0.26, 0.39]]></text> <explanation><![CDATA[f2 must be only counted towards the class LOCATION due to its condition, c = LOCATION.]]></explanation> </option> <option id="ae44ae8dd7cee6c1de7baff05389fe48" selected_score="0" unselected_score="0"> <text><![CDATA[0.15, 0.11, 0.74]]></text> <explanation><![CDATA[f1 must not be counted towards P(DRUG| by Goéric) because Goéric is not preceded by "in".]]></explanation> </option> </option_group> </option_groups> </data> </question> <question id="c28298f9f4491b8b14c5d65f4428b2f2" type="GS_Choice_Answer_Question"> <metadata> <parameters> <rescale_score>1</rescale_score> <choice_type>radio</choice_type> </parameters> </metadata> <data> <text><![CDATA[In the maxent model, we've learned that P(c|d,λ) = expΣλifi(c,d)/ΣexpΣλifi(c',d). This equation is also in the lecture slide #25. Given the 3 classes and the 3 features, compute the following probabilities. wi = "Goéric"

P(PERSON | by Goéric) =

P(LOCATION | by Goéric) =

P(DRUG | by Goéric) =

Weight	Feature

 1.5	f1(c, d) = [c = LOCATION & wi-1 = in & isCapitalized(wi)]

-0.5	f2(c, d) = [c = LOCATION & hasAccentedLatinChar(wi)]

 0.7	f3(c, d) = [c = DRUG & ends(wi, c)]

 ]]></text> <explanation><![CDATA[

P(PERSON | by Goéric) = e0 / (e0 + e-0.5 + e0.7) = 0.28

P(LOCATION | by Goéric) = e-0.5 / (e0 + e-0.5 + e0.7) = 0.17

P(DRUG | by Goéric) = e0.7 / (e0 + e-0.5 + e0.7) = 0.56

]]></explanation> <option_groups randomize="true"> <option_group select="all"> <option id="be3b57b2fe9388e3aca55fd637fdd0ac" selected_score="1" unselected_score="0"> <text><![CDATA[0.28, 0.17, 0.56]]></text> <explanation><![CDATA[Correct!]]></explanation> </option> <option id="71aa9246cb9749625d8261e9f59d58e9" selected_score="0" unselected_score="0"> <text><![CDATA[0.17, 0.47, 0.35]]></text> <explanation><![CDATA[f1 must not be counted towards P(LOCATION | by Goéric) because Goéric is not preceded by "in".]]></explanation> </option> <option id="5570ed7fbbce09e51d59f9d66fe2d433" selected_score="0" unselected_score="0"> <text><![CDATA[0.35, 0.21, 0.43]]></text> <explanation><![CDATA[f2 must be only counted towards the class LOCATION due to its condition, c = LOCATION.]]></explanation> </option> <option id="52cc41735714cbe353edaeaeeea5f8e3" selected_score="0" unselected_score="0"> <text><![CDATA[0.09, 0.06, 0.85]]></text> <explanation><![CDATA[f1 must not be counted towards P(DRUG| by Goéric) because Goéric is not preceded by "in".]]></explanation> </option> </option_group> </option_groups> </data> </question> </question_group> <question_group select="1"> <preamble><![CDATA[]]></preamble> <question id="5337c6dc0e4aa1a3fe866ea59d24235e" type="GS_Short_Answer_Question_Simple"> <metadata> <parameters> <rescale_score>1</rescale_score> <type>numeric</type> </parameters> </metadata> <data> <text><![CDATA[We have defined three classes {PERSON, LOCATION, other} and five features like the following. We have also hand-labeled a sentence to train a NER classifier. Each word is labeled in the format of {word}/{class} (e.g. Obama/PER). Compute the sum of the empirical expectations of all features for the following sentence. The empirical expectation of a feature is $$ \Sigma_{(c,d)\in observed(C,D)} f_i(c,d)$$

 President/O Obama/PER met/O with/O former/O President/O George/PER H.W./PER Bush/PER and/O former/O Florida/LOC Gov./O Jeb/PER Bush/PER in/O the/O Oval/LOC Office/LOC on/O Friday,/O joining/O in/O a/O bipartisan/O gathering/O in/O an/O election/O year./O

Features

f1(c, d) = [c = LOCATION & isCapitalized(wi)]

f2(c, d) = [c = LOCATION & classOf(wi-1) = LOCATION]

f3(c, d) = [c = PERSON & isCapitalized(wi)]

f4(c, d) = [c = PERSON & classOf(wi-1) = PERSON]

f5(c, d) = [c = PERSON & wi-1 = "President" ]

]]></text> <explanation><![CDATA[See the slide #14-17

 $$empirical E(f_1) = 3 $$

 $$empirical E(f_2) = 1 $$

 $$empirical E(f_3) = 6 $$

 $$empirical E(f_4) = 3 $$

 $$empirical E(f_5) = 2 $$]]></explanation> <option_groups randomize="true"> <option_group select="all"> <option id="f11f2207d2d6e615d707cbe8ad52899a" selected_score="1" unselected_score="0"> <text><![CDATA[15]]></text> <explanation><![CDATA[Correct!]]></explanation> </option> </option_group> </option_groups> </data> </question> <question id="152cf0d955e0b29085407be8686a7b52" type="GS_Short_Answer_Question_Simple"> <metadata> <parameters> <rescale_score>1</rescale_score> <type>numeric</type> </parameters> </metadata> <data> <text><![CDATA[We have defined three classes {PERSON, LOCATION, other} and five features like the following. We have also hand-labeled a sentence to train a NER classifier. Each word is labeled in the format of {word}/{class} (e.g. Obama/PER). Compute the sum of the empirical expectations of all features for the following sentence. The empirical expectation of a feature is $$ \Sigma_{(c,d)\in observed(C,D)} f_i(c,d)$$

 President/O Obama/PER met/O with/O former/O President/O George/PER H.W./PER Bush/PER and/O former/O Florida/LOC Gov./O Jeb/PER Bush/PER in/O the/O Oval/LOC Office/LOC on/O Friday,/O joining/O in/O a/O bipartisan/O gathering/O in/O an/O election/O year./O

Features

f1(c, d) = [c = LOCATION & isCapitalized(wi)]

f2(c, d) = [c = LOCATION & classOf(wi-1) = LOCATION]

f3(c, d) = [c = PERSON & wi-1 = "Gov."]

f4(c, d) = [c = PERSON & wi-1 = "President"]

f5(c, d) = [c = PERSON & isCapitalized(wi) ]

]]></text> <explanation><![CDATA[See the slide #14-17

 $$empirical E(f_1) = 3 $$

 $$empirical E(f_2) = 1 $$

 $$empirical E(f_3) = 1 $$

 $$empirical E(f_4) = 2 $$

 $$empirical E(f_5) = 6 $$]]></explanation> <option_groups randomize="true"> <option_group select="all"> <option id="777de336e9fea819eec2106d8ab4ddc2" selected_score="1" unselected_score="0"> <text><![CDATA[13]]></text> <explanation><![CDATA[Correct!]]></explanation> </option> </option_group> </option_groups> </data> </question> </question_group> <question_group select="1"> <preamble><![CDATA[]]></preamble> <question id="0d99d2d3832e1d2e5e9f4285e9083946" type="GS_Short_Answer_Question_Simple"> <metadata> <parameters> <rescale_score>1</rescale_score> <type>numeric</type> </parameters> </metadata> <data> <text><![CDATA[We've built an NER system and ran it on a tiny dataset. Based on the following result, compute the F1 score of the system. (round to the 3 decimal places, e.g. 0.123)

	GOLD PERSON	GOLD other

SYSTEM GUESS PERSON	20	33

SYSTEM GUESS other	10	4
]]></text> <explanation><![CDATA[Precision: % of selected items that are correct
 Recall: % of correct items that are selected
 F1: 2PR/(P+R)

 Precision: 20 / 53 = 0.377
 Recall: 20 / 30 = 0.667
 F1: (2 * 0.377 * 0.677) / (0.377 + 0.677) = 0.482]]></explanation> <option_groups randomize="true"> <option_group select="all"> <option id="25afcead9814d8e8c33447289c2d1894" selected_score="1" unselected_score="0"> <text><![CDATA[0.482]]></text> <explanation><![CDATA[Correct!]]></explanation> </option> </option_group> </option_groups> </data> </question> <question id="71ec1f32a6eaad7c17683a435e43218e" type="GS_Short_Answer_Question_Simple"> <metadata> <parameters> <rescale_score>1</rescale_score> <type>numeric</type> </parameters> </metadata> <data> <text><![CDATA[We've built an NER system and ran it on a tiny dataset. Based on the following result, compute the F1 score of the system. (round to the 3 decimal places, e.g. 0.123)

	GOLD PERSON	GOLD other

SYSTEM GUESS PERSON	15	4

SYSTEM GUESS other	18	6
]]></text> <explanation><![CDATA[Precision: % of selected items that are correct
 Recall: % of correct items that are selected
 F1: 2PR/(P+R)

 Precision: 15 / 19 = 0.789
 Recall: 15 / 33 = 0.455
 F1: (2 * 0.789 * 0.455) / (0.789 + 0.455) = 0.577]]></explanation> <option_groups randomize="true"> <option_group select="all"> <option id="9d9b733bdb2575a4bbc383ae5b229094" selected_score="1" unselected_score="0"> <text><![CDATA[0.577]]></text> <explanation><![CDATA[Correct!]]></explanation> </option> </option_group> </option_groups> </data> </question> <question id="f0658b6495b0c862dfca37f6aa509570" type="GS_Short_Answer_Question_Simple"> <metadata> <parameters> <rescale_score>1</rescale_score> <type>numeric</type> </parameters> </metadata> <data> <text><![CDATA[We've built an NER system and ran it on a tiny dataset. Based on the following result, compute the F1 score of the system. (round to the 3 decimal places, e.g. 0.123)

	GOLD PERSON	GOLD other

SYSTEM GUESS PERSON	20	10

SYSTEM GUESS other	11	14
]]></text> <explanation><![CDATA[Precision: % of selected items that are correct
 Recall: % of correct items that are selected
 F1: 2PR/(P+R)

 Precision: 20 / 30 = 0.667
 Recall: 20 / 31 = 0.645
 F1: (2 * 0.667 * 0.645) / (0.667 + 0.645) = 0.656]]></explanation> <option_groups randomize="true"> <option_group select="all"> <option id="a5816f68fe9e55021bb7937356f4f68b" selected_score="1" unselected_score="0"> <text><![CDATA[0.656]]></text> <explanation><![CDATA[Correct!]]></explanation> </option> </option_group> </option_groups> </data> </question> </question_group> <question_group select="1"> <preamble><![CDATA[]]></preamble> <question id="9337a247d6767a488a275205c9d111f5" type="GS_Short_Answer_Question_Simple"> <metadata> <parameters> <rescale_score>1</rescale_score> <type>numeric</type> </parameters> </metadata> <data> <text><![CDATA[Suppose we build a maxent classifier over 5 classes {PERSON, ORGANIZATION, LOCATION, PRODUCT, OTHER}. Suppose further that for a particular data item, one feature matches for the class PERSON with its lambda weight as $$\ln4$$. No other features match that particular data item for any other class. What will be the probability of the class PERSON on this data item at classification time? (numerical response rounded to the nearest tenths, e.g. 0.1 or 0.9)]]></text> <explanation><![CDATA[For the particular data item, the vote for the class PERSON is ln4 and the votes for the other classes are 0. Thus, the probability of the class PERSON on this data item is like the following:

 $$\frac{e^{ln4}}{e^{ln4}+e^{0}+e^{0}+e^{0}+e^{0}} = \frac{4}{4+1+1+1+1} = 0.5$$]]></explanation> <option_groups randomize="true"> <option_group select="all"> <option id="872671bcc8b0acdc16e71638a1b2060d" selected_score="1" unselected_score="0"> <text><![CDATA[0.5]]></text> <explanation><![CDATA[Correct!]]></explanation> </option> </option_group> </option_groups> </data> </question> </question_group> </question_groups> </data> </quiz>
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Modularizes source code. Keeps the global environment clean, explicifies interdependencies. Inspired by 'RequireJS'<http://requirejs.org/>.
| Version: | <IP_ADDRESS> |
| Depends: | R (≥ 3.3.1) |
| Suggests: | knitr, rmarkdown |
| Published: | 2017-01-05 |
| Author: | Peter van den Berg [aut, cre] |
| Maintainer: | Peter van den Berg <peter_v_d_berg at hotmail.com> |
| License: | MIT + file LICENSE |
| NeedsCompilation: | no |
| Materials: | README |
| CRAN checks: | requireR results |
| Reference manual: | requireR.pdf |
| Vignettes: |
RequireR |
| Package source: | requireR_<IP_ADDRESS>.tar.gz |
| Windows binaries: | r-devel: requireR_<IP_ADDRESS>.zip, r-release: requireR_<IP_ADDRESS>.zip, r-oldrel: requireR_<IP_ADDRESS>.zip |
| OS X binaries: | r-release: requireR_<IP_ADDRESS>.tgz, r-oldrel: requireR_<IP_ADDRESS>.tgz |
| Old sources: | requireR archive |
Please use the canonical form https://CRAN.R-project.org/package=requireR to link to this page.


GENEALOGIES OF A CRIME
Reviewed by Harvey Karten, Ph.D. Strand Releasing Director: Raoul Ruiz Writer: Pascal Bonitzer, Raoul Ruiz Cast:Catherine Deneuve, Michel Piccoli, Melvil Poupaud, Andrzej Seweryn, Bernadette, Lafont, Monique Melinaud, Hubert Saint Macary
In his latest movie, the Chilean writer-director--who left his native country for France after the overthrow in 1973 of Salvador Allende--plays with double identities and meditates upon a major philosophic and theological issue. Are we the captains of our souls with free will to do as we choose, or are our lives determined for us pretty much at birth? This is not a simple proposition, nor does Ruiz treat the matter in a dumbed-down style. Collaborating with Pascal Bonitzer in the writing of the screenplay, Ruiz hints in the very title that he leans in the latter direction: we are not what we eat or even how we are raised, but how we are born. Our genes determine our fate so strongly that even at the age of five, a sharp psychoanalyst can predict whether a lad will become a criminal. Nor can outside forces do much short of imprisoning or executing him to arrest this destiny.
The central character is Solange/Jeanne (Catherine Deneuve), who takes on a double identity. In the role of Solange, she goes about her business as a lawyer addicted to lost causes. She has never won a case. True to form she assumes the defense of the Rene (Melvil Poupaud), a dangerous young man who has killed the psychiatrist aunt who took the orphan into her home, an act which was foreseen when he was an adorable five-year-old kid. As Jeanne, however, Deneuve appropriates the role of Rene's aunt, complete with a red wig, determined to play out the guise to see where it leads. There is little doubt that Rene is guilty. A strange psychiatrist, Georges Didier (Michel Piccoli), comes forward as an eyewitness, asserting that the murder was committed in the midst of a group psychotherapy session, as the boy's aunt was determined to see where his homicidal tendencies would head even to the point of provoking the horrid deed.
As though daring his audience to remain seated throughout, Ruiz introduces a character even weirder than Didier though he seems on the surface to be the more stable one. The mustachioed, bespectacled, and exquisitely dressed Christian (Andrzej Seweryn) emerges as an opponent of Didier's school of thought, and at one point when they meet at opposite tables in a French cafe, he seems to challenge Didier to a duel. As if to show that no one in France is balanced, Ruiz introduces Solange's crotchety mother, Esther (Bernadette Lafont), who is a patient of Didier and who provokes her daughter down to criticizing her cooking, even finding psychological meaning in Solange's use of a vinaigrette dressing instead of mayonnaise.
The child in us never loses interest in playing games, though Solange plays one far more deadly and consequential than the participants in Nintendo. As Solange's relationship with her client grows and Solange realizes that the young man reminds her of her own dead son, the two often switch roles, she assuming his identity and he hers. This gamesmanship escalates into a full-scale playing out of the connection between Rene and his aunt, with Deneuve becoming essentially the vindictive ghost of the murder victim.
While director Raoul Ruiz is considered a disciple of Luis Bunuel and Alfred Hitchcock, "Genealogies of a Crime" is of a piece with Jean Genet, whose play "The Maids" treats a pair of beings who are concurrently drawn to and repelled by each another and who, dreaming of committing a murder, assume the role of maid and servant to play out their fantasy.
"Genealogies of a Crime" is heavy going, bound to exasperate some in its high-brow audience. While during its screenings at the Berlin Film Festival some walked out, no one at a recent critics' screening in New York did so. Bewildering and maddening as the movie can become--even soporific at times despite the cuts it went through at Catherine Deneuve's request--it features serious acting, a few dollops of humor, and at least one in-joke (the appearance of cast members in paintings on the wall of a spacious room). It deserves to be seen by an open, curious selection of film buffs who will appreciate photographer Stefan Ivanov's use of a tobacco-brown filter to inform its atmosphere, Jorge Arriagada's eerie music, some splendid off-the-wall acting, and a vigorous directorial imagination. Not Rated. Running time: 113 minutes. (C) Harvey Karten 1998
The review above was posted to the
rec.arts.movies.reviews newsgroup (de.rec.film.kritiken for German reviews).
The Internet Movie Database accepts no responsibility for the contents of the
review and has no editorial control. Unless stated otherwise, the copyright
belongs to the author.
Please direct comments/criticisms of the review to relevant newsgroups.
Broken URLs inthe reviews are the responsibility of the author.
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Related links: index of all rec.arts.movies.reviews reviews


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Hi, Felix
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Constance is an Attorney and Guardian ad Litem in private practice in the Franklin County Courts.
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- Attorney, co-chair of the Ohio Green Party
- Nominee for the State House in 2016
Constance is an Attorney and Guardian ad Litem in private practice in the Franklin County Courts.
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URL Shortener Microservice
Documentation
- Valid URLs can be sent (via POST) to to /api/shorturl/new and the server will respond with a JSON object with the shortened URL
- The server will handle invalid URLs by responding with a JSON object containing an error message
Example of usage
POST 'https://www.google.com/' to /api/shorturl/new, which will provide a shortened url that will redirect to google
Example Output (JSON)
{
"url": "https://www.google.com/",
"short_url": "[this_project_url]/api/shorturl/1"
}


WITNESS LIST Higher Education Committee April 7, 2003-2:30P HB 1363 For: Ho, Tina (Texas Instruments) Johnson, Rita (Self) McIntire, Jay (Texas Association for the Gifted and Talented) Novak, John E. (Texas Academy of Mathematics and Science) Ondijo, Corlisa (Self) Smith, Adam Michael (Self) Thomas, Justin (Self) Williams, Whitney (Self) Wismer, Phillip (Texas Academy of Math & Science) On: Sinclair, Richard J. (University of North Texas) HB 1544 For: Benavidez, Jr., Manuel (South Texas Community College) Garcia, Dr. Rey (Texas Assn of Community Colleges) Hazelwood, Steve (Dow Chemical) Valek, Millicent (Tx Assoc of Community Colleges Brazosport College) On: Head, Steve (North Harris Montgomery Comm. College District) Jolly, Richard (Midland College) HB 1817 On: Trauth, President, Denise (Southwest Texas State University) HB 1887 For: Haley, Brian (UT Austin Student Body) Kowalski, Tom (Texas Healthcare and Bio Science Institute) On: Natalicio, President, Diana (UTEP) HB 1889 For: Chatelle, Melody (Texas Classroom Teachers Association (TCTA)) Dovalina, Ramon H. (Self) Garcia, Dr. Rey (Texas Assn of Community Colleges) Strayhorn, Carole Keeton (Comptroller Ofc) Wenrich, J. William (Dallas County Community College District) On: Cole, Jeffrey (Comptroller's Office) Lebas, James (Comptroller's Office) Segura, Bill (Texas Stae Technical Colleges) HB 3015 For: Zafereo, Mark E. (Self) Against: Banks, Joyce L. (Self and Elected Co-chair of the Graduate Student Assembly) Buckley, Jordan (Self and University of Texas - Austin Sutdent Government) Carlton, Kyle (Texas A&M Student Body) Dildy, Donald S. (Self and Texas Tech University Student Body) Edbauer, Jennifer (Self) Fernheimer, Janice W. (Self) Goodman, Christopher (Self and Students of Texas Tech University) Haley, Brian (University of Texas at Austin Student Body) Heinemeier, Christopher S. (Self) Hodgkin, Mark A. (Self) Interiano, Gerardo (Self) Jones, Margaret D. (Self) Kinghorn, Austin (Young Conservative of Texas) Majid, Slyman (Self) McGee, Connor (Self) Mohammed, Nayeem (Young Conservatives of Texas) Pravda, Bryan (Self) Price, Brazos (Self) Schwellenbach, Nicholas (Self and UT Watch) Selleck, Erin (The Young Conservatives of Texas at UT-Austin) Ulrich, Melanie R. (Self) Van Zant, Austin (UT Watch) Watson, Mary Virginia (Self) Wilder, Forrest (Self) On: Brown, Don (Tx Higher Education Coordinating Board) Hugetz, Edward T. (University of Houston)


|
DistributedRobotWorld
|
#include <Session.hpp>
Public Member Functions | |
| Session (boost::asio::io_service &io_service) | |
| virtual | ~Session () |
| virtual void | start ()=0 |
| virtual void | handleMessageRead (Message &aMessage)=0 |
| virtual void | handleMessageWritten (Message &aMessage)=0 |
| boost::asio::ip::tcp::socket & | getSocket () |
Protected Member Functions | |
| void | readMessage () |
| void | handleHeaderRead (Message &aMessage, const boost::system::error_code &error, size_t UNUSEDPARAM(bytes_transferred)) |
| void | handleBodyRead (Message &aMessage, const boost::system::error_code &error, size_t bytes_transferred) |
| void | handleMessageRead (Message &aMessage, const boost::system::error_code &error, size_t UNUSEDPARAM(bytes_transferred)) |
| void | writeMessage (Message &aMessage) |
| void | handleHeaderWritten (Message &aMessage, const boost::system::error_code &error) |
| void | handleBodyWritten (Message &aMessage, const boost::system::error_code &error) |
| void | handleMessageWritten (Message &aMessage, const boost::system::error_code &error) |
Protected Attributes | |
| boost::asio::ip::tcp::socket | socket |
| std::vector< char > | headerBuffer |
| std::vector< char > | bodyBuffer |
A session is an encapsulation of a request/response transaction sequence.
|
inline |
| io_service |
|
inlinevirtual |
|
inline |
|
inlineprotected |
This function as called after the body bytes are read.
Any error handling (throwing an exception ;-)) is done in this function and then the function with the same name but without the error is called.
|
inlineprotected |
This function is called after the body bytes are written.
|
inlineprotected |
This function is called after the header bytes are read.
|
inlineprotected |
This function is called after the header bytes are written.
|
pure virtual |
Handle the fact that a message is read. This function is called by the framework after the message (header + body) is read. Normally this is the only function that a ServerSession or ClientSession has to implement.
Implemented in Messaging::ClientSession, and Messaging::ServerSession.
|
inlineprotected |
This function is called after both the header and body bytes are read.
|
pure virtual |
Handle the fact that a message is written. This function is called by the framework after the message (header + body) is written. Normally this is the only function that a ServerSession or ClientSession has to implement.
|
inlineprotected |
This function is called after both the header and body bytes are written.
Any error handling (throwing an exception ;-)) is done in this function and then the function with the same name but without the error is called.
|
inlineprotected |
readMessage will read the message in 2 a-sync reads, 1 for the header and 1 for the body. After each read a callback will be called that should handle the stuff just read. After reading the full message handleMessageRead will be called whose responsibility it is to handle the message as a whole.
|
pure virtual |
Typically a ServerSession has a read/write sequence, a ClientSession a write/read sequence
Implemented in Messaging::ClientSession, and Messaging::ServerSession.
|
inlineprotected |
writeMessage will write the message in 2 a-sync writes, 1 for the header and 1 for the body. After each write a callback will be called that should handle the stuff just read. After writing the full message handleMessageWritten will be called.
|
protected |
|
protected |
|
protected |


“Anything can be a popsicle mold if you try hard enough” — words that just escaped my mouth. Why yes, we’re at IKEA, how could you tell?
8/15/2022, 6:15:13 PM
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link--- layout: tweet ---
“Anything can be a popsicle mold if you try hard enough” — words that just escaped my mouth. Why yes, we’re at IKEA, how could you tell?
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Favs: 3
Retweets: 1
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Search engine optimization is abbreviated as SEO. Search engine optimization is a combination of two words, “search engine” and “optimization”. Search engine is a tool that displays the information according to the keywords whereas optimization is an act to make best of something.
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SEO helps the website to get accessed by the search engine. This process is followed to make sure that the content of the website is crawled by the search engines like Google,yahoo, Bing etc. and is indexed on the results. SEO mainly focuses on the organic/natural result rather than the paid promotions.
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Therefore, the first strategy of search engine optimization is to understand the audience’s intent and then delivering it the way search engine can find them.


Amber's Experiments
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This tutorial presents two sample applications to demonstrate the use of the Java GSS-API. This API permits secure exchanges of messages between communicating applications. Here are the sample client and server applications you'll need for this tutorial:
Contents:
SampleServer
ProgramsAs with all tutorials in this series, the underlying technology used to support authentication and secure communication for the applications in this tutorial is Kerberos. See Kerberos Requirements.
The applications for this tutorial are named
SampleClient
and SampleServer
.
Each is invoked by executing the Login utility supplied with
this tutorial and passing it as arguments the name of the
application (SampleClient
or
SampleServer
), followed by the arguments needed by the
application. The Login utility uses a JAAS LoginContext to
authenticate the user using Kerberos. Finally, the Login utility
invokes the main
method of the application class, in
our case either SampleClient
or
SampleServer
, and passes the application its
arguments.
Here is a summary of execution of the SampleClient
and SampleServer
applications:
SampleServer
application by running the
Login utility and passing it as arguments the name
"SampleServer
" followed by the arguments for the
SampleServer
program. The Login utility prompts you
for the password for the principal that SampleServer
should run as. (See Kerberos User and Service
Principal Names.) After authentication is complete,
SampleServer
is run it:
SampleClient
application (possibly on a
different machine), by running the Login utility and passing it as
arguments the name "SampleClient
" followed by the
arguments for the SampleClient
program. The Login
utility prompts you for your Kerberos name and password. After
authentication is complete, SampleClient
is run. It
SampleServer
. (See Kerberos User and Service Principal Names.), (2)
the name of the host (machine) on which SampleServer
is running, and (3) the port number on which
SampleServer
listens for client connections.SampleServer
, using the host and port it was passed as
arguments.SampleServer
and both applications initialize a DataInputStream and a
DataOutputStream from the socket input and output streams, to be
used for future data exchanges.SampleClient
and SampleServer
each
instantiate a GSSContext and establish a shared context that will
enable subsequent secure data exchanges.SampleClient
and SampleServer
can now
securely exchange messages.SampleClient
and SampleServer
are done exchanging messages, they perform clean-up
operations.SampleClient
and
SampleServer
Code" section of the Use of Java GSS-API for Secure Message
Exchanges Without JAAS Programming tutorial for a full
discussion of the code used in this tutorial.
Since the underlying authentication and secure communication technology used by this tutorial is Kerberos V5, we use Kerberos-style principal names wherever a user or service is called for.
For example, when you run SampleClient
you are
asked to provide your user name. Your Kerberos-style user
name is simply the user name you were assigned for Kerberos
authentication. It consists of a base user name (like "mjones")
followed by an "@" and your realm (like
"mjones@KRBNT-OPERATIONS.EXAMPLE.COM").
A server program like SampleServer
is typically
considered to offer a "service" and to be run on behalf of a
particular "service principal." A service principal name for
SampleServer
is needed in several places:
SampleServer
you must log in as the
appropriate service principal. The login configuration file for
this tutorial actually specifies the service principal name (as an
option to the Krb5LoginModule), so the JAAS authentication (done by
the Login utility) just asks you to specify the password for that
service principal. If you specify the correct password, the
authentication is successful, a Subject is created containing a
Principal with the service principal name, and that Subject is
associated with a new access control context. The
subsequently-executed code (the SampleServer
code) is
considered to be executed on behalf of the specified
principal.SampleClient
, one of the arguments is
the service principal name. This is needed so
SampleClient
can initiate establishment of a security
context with the appropriate service.Throughout this document, and in the accompanying login configuration file and policy files,
service_principal@your_realmis used as a placeholder to be replaced by the actual name to be used in your environment. Any Kerberos principal can actually be used for the service principal name. So for the purposes of trying out this tutorial, you could use your user name as both the client user name and the service principal name.
In a production environment, system administrators typically like servers to be run as specific principals only and may assign a particular name to be used. Often the Kerberos-style service principal name assigned is of the form
service_name/machine_name@realm;
For example, an nfs service run on a machine named "raven" in the realm named "KRBNT-OPERATIONS.EXAMPLE.COM" could have the service principal name
<EMAIL_ADDRESS>Such multi-component names are not required, however.
Single-component names, just like those of user principals, can be
used. For example, an installation might use the same ftp service
principal ftp@realm
for all ftp servers in that realm,
while another installation might have different ftp principals for
different ftp servers, such as ftp/host1@realm
and
ftp/host2@realm
on machines host1
and
host2
, respectively.
If the realm of a user or service principal name is the default
realm (see Kerberos Requirements),
you can leave off the realm when you are logging into Kerberos
(that is, when you are prompted for your username). Thus, for
example, if your user name is
<EMAIL_ADDRESS>and you run
SampleClient
, when it requests your user name you
could just specify "mjones", leaving off the realm. The name is
interpreted in the context of being a Kerberos principal name and
the default realm is appended, as needed.
You can also leave off the realm if a principal name will be
converted to a GSSName by a GSSManager createName
method. For example, when you run SampleClient
, one of
the arguments is the server service principal name. You can specify
the name without including the realm, because
SampleClient
passes the name to such a
createName
method, which appends the default realm as
needed.
It is recommended that you always include realms when principal names are used in login configuration files and policy files, because the behavior of the parsers for such files may be implementation-dependent; they may or may not append the default realm before such names are utilized and subsequent actions may fail if there is no realm in the name.
Whenever JAAS is used, a login configuration is required to
specify the desired authentication technology. (See JAAS Login Configuration File for more
information about what a login configuration file is.) Both
SampleClient
and SampleServer
can use the
same login configuration file, if that file contains two entries,
one entry for the client side and one for the server side.
The csLogin.conf login configuration file used for this tutorial is the following:
SampleClient { com.sun.security.auth.module.Krb5LoginModule required; }; SampleServer { com.sun.security.auth.module.Krb5LoginModule required storeKey=true principal="service_principal@your_realm"; };
Note that the name for each entry matches the respective class
names for our two top-level applications, SampleClient
and SampleServer
. Recall that this is also the name
that is passed to the Login utility that performs JAAS operations
for the application. That utility expects the name of the entry to
be looked up in your login configuration file to be the same as the
name it is passed.
Both entries specify that Sun's Kerberos V5 LoginModule must be
used to successfully authenticate the user. The Krb5LoginModule
succeeds only if the attempt to log in to the Kerberos KDC as a
specified entity is successful. In the case of
SampleClient
, the user will be prompted for their name
and password. In the case of SampleServer
, a name is
already supplied in this login configuration file (the specified
principal, as described below) and the user running
SampleServer
is just asked for the password for the
entity specified by that name. They must specify the correct
password in order for authentication to succeed.
The SampleServer
entry
storeKey=true
indicates that a secret key
should be calculated from the password provided during login and it
should be stored in the private credentials of the Subject created
as a result of login. This key is subsequently utilized during
mutual authentication when establishing a security context between
SampleClient
and SampleServer
.
The Krb5LoginModule has a principal
option
that can be used to specify that only the specified principal
(entity/user) should be logged in for the given program. Here, the
SampleClient
entry does not specify a principal
(although it could, if desired), so the user is prompted for a user
name and password and anyone with a valid user name and password
can run SampleClient
. SampleServer
, on
the other hand, indicates a particular principal because system
administrators usually like servers to be run as specific
principals only. In this case, the user running
SampleServer
is prompted for that principal's password
and must supply the correct one in order for authentication to
succeed.
Note that you must replace "service_principal@your_realm" with
the name of the service principal that represents
SampleServer
. (See Kerberos User
and Service Principal Names.)
For information about all the possible options that can be passed to Krb5LoginModule, see the Krb5LoginModule documentation.
The policy file used when running SampleClient
is
client.policy, and the policy file used
when running SampleServer
is server.policy. Their contents are described
below.
A number of permissions are required by the classes in
Login.java
(Login and MyAction). As recommended in the
previous tutorial on the use of
Login, we create a Login.jar
JAR file containing the
Login.class
and MyAction.class
files and
in the client.policy
policy file we grant
Login.jar AllPermission
:
grant codebase "file:./Login.jar" { permission java.security.AllPermission; };
SampleClient
The SampleClient
code does two types of operations
for which permissions are required. It
SampleServer
application.SampleServer
.The permission required to open a socket connection is
permission java.net.SocketPermission "*", "connect";
You may replace the "*" with the hostname or IP address of the
machine that SampleServer
will be running on.
The permission(s) required to initiate establishment of a
security context will depend on the underlying mechanism. This
tutorial uses Kerberos as the underlying mechanism, and for that
two javax.security.auth.kerberos.ServicePermission
s
are required. A ServicePermission contains a service principal name
and an action (or list of actions). To initiate establishment of a
security context, you need two ServicePermissions with action
"initiate", whose names specify:
SampleServer
. (See Kerberos User
and Service Principal Names.) Granting this permission allows
you to interact with the service, SampleServer
, using
Kerberos.We want to grant the permissions to a specific authenticated
user executing SampleClient
, so we specify both the
SampleClient
code location (in
SampleClient.jar
) and a Principal designation
indicating the user name and realm for the user (you, the person
who will run SampleClient
). (See How Do You Make Principal-Based Policy
File Statements? in the second tutorial of this series for
information on policy file grant
statements that
include Principal designations.)
Here is the basic form for the grant
statement:
grant CodeBase "file:./SampleClient.jar", Principal javax.security.auth.kerberos.KerberosPrincipal "your_user_name@your_realm" { permission java.net.SocketPermission "*", "connect"; permission javax.security.auth.kerberos.ServicePermission "krbtgt/your_realm@your_realm", "initiate"; permission javax.security.auth.kerberos.ServicePermission "service_principal@your_realm", "initiate"; };
You must substitute your Kerberos user name (complete with "@"
and realm) for "your_user_name@your_realm
". For
example, if your user name is "mjones" and your realm is
"KRBNT-OPERATIONS.EXAMPLE.COM", you would use
<EMAIL_ADDRESS>(complete with the
quotes).
You must also substitute your realm in
"krbtgt/your_realm@your_realm" and the service
principal name for the service principal representing the
server for "service_principal@your_realm
". Suppose
the former is
<EMAIL_ADDRESS>and the latter is
<EMAIL_ADDRESS>and your
user name is as specified in the previous paragraph. Then the
grant
statement would be
grant CodeBase "file:./SampleClient.jar", Principal javax.security.auth.kerberos.KerberosPrincipal<EMAIL_ADDRESS>{ permission java.net.SocketPermission "*", "connect"; permission javax.security.auth.kerberos.ServicePermission<EMAIL_ADDRESS>"initiate"; permission javax.security.auth.kerberos.ServicePermission<EMAIL_ADDRESS>"initiate"; };
The grant
statement in the server policy file for
the Login classes is exactly the same as the one in the client
policy file, as described in Permissions
Required by the Login Utility Classes:
grant codebase "file:./Login.jar" { permission java.security.AllPermission; };
SampleServer
The SampleServer
code does two types of operations
for which permissions are required. It
The permission required to accept socket connections is
permission java.net.SocketPermission "*", "accept";
You may replace the "*" with the hostname or IP address of the
machine that SampleClient
will be running on.
The permission required to accept establishment of a security context is
permission javax.security.auth.kerberos.ServicePermission "service_principal@your_realm", "accept";where "service_principal@your_realm" is the Kerberos name of the service principal that represents
SampleServer
.
We want to grant the permissions to a specific authenticated
user executing SampleServer
(the service principal
considered to represent SampleServer
), so we specify
both the SampleServer
code location (in
SampleServer.jar
) and a Principal designation
indicating the service principal. Suppose this name is
<EMAIL_ADDRESS>Then the
grant
statement would be
grant CodeBase "file:./SampleServer.jar" Principal javax.security.auth.kerberos.KerberosPrincipal<EMAIL_ADDRESS>{ permission java.net.SocketPermission "*", "accept"; permission javax.security.auth.kerberos.ServicePermission<EMAIL_ADDRESS>"accept"; };
SampleClient
and
SampleServer
ProgramsTo execute the SampleClient
and
SampleServer
programs, do the following:
SampleServer
for
ExecutionSampleClient
for
ExecutionSampleServer
SampleClient
SampleServer
for ExecutionTo prepare SampleServer
for execution, do the
following:
SampleServer
:
csLogin.conf
with the name of the
service principal representing SampleServer
.server.policy
with
the Kerberos name of the service principal that represents
SampleServer
. (The same name as that used in the login
configuration file.)Login.java
and
SampleServer.java
:
javac Login.java SampleServer.java
Note that Login.java
contains two classes and thus
compiling Login.java
creates Login.class
and MyAction.class
.
Login.jar
containing
Login.class and MyAction.class
:
jar -cvf Login.jar Login.class MyAction.class
SampleServer.jar
containing SampleServer.class
:
jar -cvf SampleServer.jar SampleServer.class
SampleClient
for ExecutionTo prepare SampleClient
for execution, do the
following:
SampleClient
:
client.policy
:
your_realm
in
"krbtgt/your_realm@your_realm" with your realm.SampleServer
.Login.java
and
SampleClient.java
:
javac Login.java SampleClient.java
Login.jar
containing
Login.class and MyAction.class
:
jar -cvf Login.jar Login.class MyAction.class
SampleClient.jar
containing SampleClient.class
:
jar -cvf SampleClient.jar SampleClient.class
SampleServer
It is important to execute SampleServer
before
SampleClient
because SampleClient
will
try to make a socket connection to SampleServer
and
that will fail if SampleServer
is not yet running and
accepting socket connections.
To execute SampleServer
, be sure to run it on the
machine it is expected to be run on. This machine name (host name)
is specified as an argument to SampleClient
. The
service principal name appears in several places, including the
login configuration file and the policy files.
Go to the directory in which you have prepared
SampleServer
for execution. Execute the
Login
class, specifying
-classpath
clause that classes
should be searched for in the Login.jar
and
SampleServer.jar
JAR files,-Djava.security.manager
that a security manager
should be installed,-Djava.security.krb5.realm=<your_realm>
that your Kerberos realm is the one specified. For example, if your
realm is "KRBNT-OPERATIONS.EXAMPLE.COM" you'd put
-Djava.security.krb5.realm=KRBNT-OPERATIONS.EXAMPLE.COM
.-Djava.security.krb5.kdc=<your_kdc>
that
your Kerberos KDC is the one specified. For example, if your KDC is
"samplekdc.example.com" you'd put
-Djava.security.krb5.kdc=samplekdc.example.com
.-Djava.security.policy=server.policy
that the
policy file to be used is server.policy
, and-Djava.security.auth.login.config=csLogin.conf
that the login configuration file to be used is
csLogin.conf
.You pass the name of your application (in this case,
"SampleServer
") as an argument to Login. You then add
as arguments any arguments required by your application, which in
the case of SampleServer
is a single argument
specifying the port number to be used for listening for client
connections. Choose a high port number unlikely to be used for
anything else. An example would be something like 4444.
Below are the full commands to use for both Microsoft Windows and Solaris, Linux, and Mac OS X systems. The only difference is that on Microsoft Windows systems you use semicolons to separate classpath items, while you use colons for that purpose on Solaris, Linux, and Mac OS X systems.
Important: In these commands, you must replace
<port_number>
with an appropriate port number,
<your_realm>
with your Kerberos realm, and
<your_kdc>
with your Kerberos KDC.
Here is the command for Microsoft Windows systems:
java -classpath Login.jar;SampleServer.jar -Djava.security.manager -Djava.security.krb5.realm=<your_realm> -Djava.security.krb5.kdc=<your_kdc> -Djava.security.policy=server.policy -Djava.security.auth.login.config=csLogin.conf Login SampleServer <port_number>
Here is the command for Solaris, Linux, and Mac OS X systems:
java -classpath Login.jar:SampleServer.jar -Djava.security.manager -Djava.security.krb5.realm=<your_realm> -Djava.security.krb5.kdc=<your_kdc> -Djava.security.policy=server.policy -Djava.security.auth.login.config=csLogin.conf Login SampleServer <port_number>
Type the full command on one line. Multiple lines are used here for legibility. If the command is too long for your system, you may need to place it in a .bat file (for Microsoft Windows) or a .sh file (for Solaris, Linux, and Mac OS X) and then run that file to execute the command.
You will be prompted for the Kerberos password for the service
principal. The underlying Kerberos authentication mechanism
specified in the login configuration file will log the service
principal into Kerberos. Once authentication is successfully
completed, the SampleServer
code will be executed on
behalf of the service principal. It will listen for socket
connections on the specified port.
For login troubleshooting suggestions, see Troubleshooting.
SampleClient
To execute SampleClient
, go to the directory in
which you have prepared SampleClient
for execution.
Then execute the Login
class, specifying
-classpath
clause that classes
should be searched for in the Login.jar
and
SampleClient.jar
JAR files,-Djava.security.manager
that a security manager
should be installed,-Djava.security.krb5.realm=<your_realm>
that your Kerberos realm is the one specified.-Djava.security.krb5.kdc=<your_kdc>
that
your Kerberos KDC is the one specified.-Djava.security.policy=client.policy
that the
policy file to be used is client.policy
, and-Djava.security.auth.login.config=csLogin.conf
that the login configuration file to be used is
csLogin.conf
.Pass to Login the name of your application
("SampleClient
") followed by the arguments required by
SampleClient
. The SampleClient
arguments
are (1) the Kerberos name of the service
principal that represents SampleServer
, (2) the
name of the host (machine) on which SampleServer
is
running, and (3) the port number on which SampleServer
is listening for client connections.
Below are the full commands to use for both Microsoft Windows and Solaris, Linux, and Mac OS X systems.
Important: In these commands, you must replace
<service_principal>
, <host>
,
<port_number>
, <your_realm>
,
and <your_kdc>
with appropriate values (and
note that the port number must be the same as the port number
passed as an argument to SampleServer
). These values
need not be placed in quotes.
Here is the command for Microsoft Windows systems:
java -classpath Login.jar;SampleClient.jar -Djava.security.manager -Djava.security.krb5.realm=<your_realm> -Djava.security.krb5.kdc=<your_kdc> -Djava.security.policy=client.policy -Djava.security.auth.login.config=csLogin.conf Login SampleClient <service_principal> <host> <port_number>
Here is the command for Solaris, Linux, and Mac OS X systems:
java -classpath Login.jar:SampleClient.jar -Djava.security.manager -Djava.security.krb5.realm=<your_realm> -Djava.security.krb5.kdc=<your_kdc> -Djava.security.policy=client.policy -Djava.security.auth.login.config=csLogin.conf Login SampleClient <service_principal> <host> <port_number>
Type the full command on one line. Multiple lines are used here
for legibility. As with the command for executing
SampleServer
, if the command is too long to type
directly into your command window, place it in a .bat file
(Microsoft Windows) or a .sh file (Solaris, Linux, and Mac OS X)
and then execute that
file.
When prompted, type your Kerberos user name and password. The
underlying Kerberos authentication mechanism specified in the login
configuration file will log you into Kerberos. Once authentication
is successfully completed, the SampleClient
code will
be executed on behalf of you. It will request a socket connection
with SampleServer
. Once SampleServer
accepts the connection, SampleClient
and
SampleServer
establish a shared context and then
exchange messages as described in this tutorial.
For login troubleshooting suggestions, see Troubleshooting.


UK Sikh groups confer ‘Lifetime Achievement’ award on Imran Khan
London: Two leading separatist British Sikh organizations conferred ‘Lifetime Achievement’ award to Pakistani Prime Minister Imran Khan for the Kartarpur corridor at the City Hall during the 550th birth anniversary of Guru Nanak Dev. Sahibzada Jahangir, spokesperson for the Pakistan PM for Trade & Investment in UK & Europe, received the award on behalf of Imran Khan, The News reported on Thursday.
The event at the City Hall was co-hosted by the Sikh Network, Sikh Federation (UK) and Dr Onkar Sahota, member of the London Assembly in collaboration with the Mayor of London, Sadiq Khan. Sikh Federation (UK) is said to be a supporter of Khalistan. Labour party leader Preet Kaur Gill, Deputy Mayor Debbie Weekes-Bernard, Satpal Singh, Jas Singh, Canon Mark Poulson and people from Sikh community attended the event. Sahibzada Jahangir expressed his gratitude towards the Sikh community for the award and said that Kartarpur corridor is a message of peace from Pakistan. “The Kartarpur Corridor reinforced the idea of Sikhs as a bridge between cultures and countries,” he said. (IANS)
Also Read: Pakistan to reopen closed Hindu Temples: Imran Khan
Also Watch: Govt all set to push for the contentious Citizenship Bill in the winter session of Parliament


hello world!
welcome, to my first webpage!
things to put into consideration while get start coding:
check out code with no coin it's a great place to learn web development skills!
favourite things


Click on a task to claim it.
The numbers next to the tasks correspond to how many people are required for that task.
Grayed out tasks have already been picked up by someone.
Sunday, May 27 | 11am-4pm
An all-day beach soccer tournament held on North Beach. There will be food, drinks, a DJ, volleyball, and more. All proceeds go to x charity.
Thursday, June 1 | 10am-4pm
A bake sale in Tech to raise money for the upcoming season.
Friday, June 9 | 10pm-2am
A party held at the soccer house to raise money for x charity. We'll need people manning the doors, bar, and bathrooms most of the time. We'll have a DJ and cheap drinks.


#include <stdlib.h> int system(const char *command);
execl("/bin/sh", "sh", "-c", command, (char *) 0);
system() returns after the command has been completed.
During execution of the command, SIGCHLD will be blocked, and SIGINT and SIGQUIT will be ignored, in the process that calls system() (these signals will be handled according to their defaults inside the child process that executes command).
If command is NULL, then system() returns a status indicating whether a shell is available on the system
In the last two cases, the return value is a "wait status" that can be examined using the macros described in waitpid(2). (i.e., WIFEXITED() WEXITSTATUS() and so on).
system() does not affect the wait status of any other children.
If the _XOPEN_SOURCE feature test macro is defined (before including any header files), then the macros described in waitpid(2) (WEXITSTATUS(), etc.) are made available when including <stdlib.h>.
As mentioned,
system()
ignores
SIGINT
and
SIGQUIT.
This may make programs that call it
from a loop uninterruptible, unless they take care themselves
to check the exit status of the child.
For example:
while (something) { int ret = system("foo"); if (WIFSIGNALED(ret) && (WTERMSIG(ret) == SIGINT || WTERMSIG(ret) == SIGQUIT)) break; }
Do not use system() from a program with set-user-ID or set-group-ID privileges, because strange values for some environment variables might be used to subvert system integrity. Use the exec(3) family of functions instead, but not execlp(3) or execvp(3). system() will not, in fact, work properly from programs with set-user-ID or set-group-ID privileges on systems on which /bin/sh is bash version 2, since bash 2 drops privileges on startup. (Debian uses a modified bash which does not do this when invoked as sh.)
In versions of glibc before 2.1.3, the check for the availability of /bin/sh was not actually performed if command was NULL; instead it was always assumed to be available, and system() always returned 1 in this case. Since glibc 2.1.3, this check is performed because, even though POSIX.1-2001 requires a conforming implementation to provide a shell, that shell may not be available or executable if the calling program has previously called chroot(2) (which is not specified by POSIX.1-2001).
It is possible for the shell command to terminate with a status of 127, which yields a system() return value that is indistinguishable from the case where a shell could not be executed in the child process.


THE SIXTH SENSE (1999)
Rating: 3.5 stars (out of 4.0) ******************************** Key to rating system: 2.0 stars - Debatable 2.5 stars - Some people may like it 3.0 stars - I liked it 3.5 stars - I am biased in favor of the movie 4.0 stars - I felt the movie's impact personally or it stood out ********************************* A Movie Review by David Sunga
Directed by: N. Night Shyamalan
Written by: N. Night Shyamalan
Starring: Bruce Willis and Haley Joel Osment
Synopsis: Hotshot psychiatrist Malcolm Crowe (Bruce Willis) thinks he's on top of the world until a suicidal patient shows up with a gun. A year later, thoroughly shaken, with his marriage falling apart and professional skills waning, Crowe stumbles on the chance to help a frightened 9-year old boy named Cole (Haley Joel Osment) who is having hallucinations of seeing dead people.
Opinion: Writer/ N. Night Shyamalan knows how to break the rules and get away with it. Instead of plying us with special effects and a predictable story line, Shyamalan keeps suspense hanging just in the background, ready to dart out at any moment, as he focuses on the relationship between Crowe and the kid. It's wonderful to watch the negotiation between actors Bruce Willis and Haley Joel Osment. Is the shaken boy taking refuge in the steadfastness of Crowe, or is the shaken Crowe finding refuge in helping the boy? Then, just as you think things are beginning to settle . . . boom! The ending is a doozy, and it makes complete sense, but I won't reveal it. Despite its title THE SIXTH SENSE has nothing to do with extrasensory perception. But it's the best ghost story I've seen in years.
Reviewed by David Sunga August 8, 1999
Copyright © 1999 by David Sunga This review and others like it can be found at THE CRITIC ZOO: http://www.criticzoo.com email<EMAIL_ADDRESS>The review above was posted to the
rec.arts.movies.reviews newsgroup (de.rec.film.kritiken for German reviews).
The Internet Movie Database accepts no responsibility for the contents of the
review and has no editorial control. Unless stated otherwise, the copyright
belongs to the author.
Please direct comments/criticisms of the review to relevant newsgroups.
Broken URLs inthe reviews are the responsibility of the author.
The formatting of the review is likely to differ from the original due
to ASCII to HTML conversion.
Related links: index of all rec.arts.movies.reviews reviews


dom-ease
DomEase
Methods
add
countElements
countRunning
emit
eventNames
listenerCount
listeners
once
on
remove
removeAll
removeAllListeners
removeListener
start
stop
update
Events
complete
each
DomEaseElement
Members
element
Methods
emit
eventNames
listenerCount
listeners
once
on
removeAllListeners
removeListener
Events
complete-*
each-*
loop-*
External: EventEmitter
EventEmitter


Do I'm alone to think that the KMD price is going down due to PIRATE project?
look like people are mining pirate, sold pirate against KMD and dump KMD on binance against BTC....
wdyt? the more I'm looking the more it's looks true(edited)
Miners are killing the price by selling all those PIRATE through ARR/KMD/BTC on exchanges. Don't forget they mostly don't care about your project and they are here for the money.
I tried to get answer on the PIRATE telegram, but they say I'm doing FUD and no more than this. But looks...!
Acura12-Nov-18 06:54 AM
It’s all lost - sell
1
If you have no hope - sell
1
OsTa12-Nov-18 06:55 AM
thank you for this answer very thoughtfully
that's crazy we can't dicuss lol
Acura12-Nov-18 07:25 AM
Don’t have time to discuss that - I trust the KMD Ecosystem
actionslacks12-Nov-18 07:26 AM
If thats the case then pirate is gaining hashrate. and there are buyers for all those dumpers using kmd. any volume is good. Even if the price is going down a little, the usage is whats important imo. Perhaps the whale was simply someone looking to accumulate to manipulate price down as much as possible? who knows and or cares. There's scores of other coins that wont be around in the near future. kmd is not one of them
OsTa12-Nov-18 07:45 AM
@actionslacks thanks for this elaborated answer I have appreciated ! Better than just "it's FUD!" or "SELL if you don't like" words by @Acura(edited)
there are good pirates here ARRR !(edited)
blackjok3r12-Nov-18 08:19 AM
Price is irrelavent... around $1 is enough for notary network to remain in a good working condition. Obviously higher is better, but $1 is pretty good generally for majority of the miners of KMD.
We need to focus on making notaries more expensive... notarise more chains...
this will drive up the price ... price will follow usage.(edited)
1
2
jl777c12-Nov-18 08:33 AM
20k KMD worth of PIRATE sold, even if 100% of that was dumped on binance, against 50BTC volumes it doesnt seem it would affect the price so much
a more realistic analysis would be that we are in the down cycle of the medium term price oscillation
OsTa12-Nov-18 08:38 AM
I think OTC trade are not taken in account. But thanks guy for your analysis/vision (edited)
Cryptoon12-Nov-18 08:58 AM
I think otc is overestimated
For pirate
And the people selling the big amounts are very early pirate adopters and these are more likely holding part of the kmd they are selling arrr for
snowdamn12-Nov-18 09:45 AM
it's all
OsTa12-Nov-18 11:56 AM
Thanks @Cryptoon
Reel Em In12-Nov-18 01:20 PM
50btc order on binnance at 18k
dokrates12-Nov-18 02:41 PM
yes
nice buy order
like the big buy order of 2M which was filled finally
Flashbit12-Nov-18 03:27 PM
now 80k sell order appears.hmmm..
likely fake
and it's gone
siu - Chainmakers12-Nov-18 03:33 PM
current correction since december 2017 reminds me of the correction back in january 2012. Very compressed norrow sideways for some months before breakout.
Cryptoon12-Nov-18 04:54 PM
I like the idea that was posted here last week or so that the current price is just manipulated until ETF approval
Does anyone have a list of dates when the next SEC hearing is or so?
Vin Armani, a long time bitcoiner and BCH supporter who founded Cointext, says Calvin Ayre and Craig Wright plan to take over BCH through a 51% attack and then do...
Fair value of Komodo. Fair value and fundamental investing charts for Komodo.
3
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FishyGuts13-Nov-18 04:39 AM
@OsTa The KMD volumes on the arrr exchange are less than .5% of average daily KMD volume.
In addition, people are buying KMD to buy arrr as its trading 9:1 instead of BTC.
If anything... ARRR is bringing positive light to KMD. The last few interviews I’ve done have been great opportunities to talk about KMD, dPoW and what it’s like to have an asset chain in the ecosystem. I also talk to people daily who are big influencers about KMD specifically.
In addition... after 6 months... KMD has 3000 discord members when pirate started. They have over 5000 in the 6 weeks we have been here and marketing for people to join the discord.
I’m not saying 2,000 are pirates but you have to assume a good Chunk are.
1
!arrrtip @OsTa 7.7701
ARRR TipBotBOT13-Nov-18 04:39 AM
TipBot
Error sending coin. [object Object]
FishyGuts13-Nov-18 04:40 AM
Also... the tip bots are courtesy of pirate... even the KMD one. We also have our shop plugin dev 97% done with the Wordpress shop plugin for KMD. He just needs one thing from @pbca26 to finish.
1
1
Digital price has agreed with me to list all future coin listings with KMD pairs. Effectively making it the first exchange that has KMD as a base trading pair. They are new and volume is low but they just added ERC20 support and are a solid UX.
1
2
That’s sort of an under the table agreement the dev and I have there but it’s effective and active.
This link is for pirate referral. The fees earned go towards project development since we didn’t ICO and have no dev fund.
Use it to buy VRSC / Arbitrage KMD and of course to buy ARRR.
https://digitalprice.io/?inviter=4fdaf7
I stand by my view that KMD ecosystem projects strengthen the system. Take a look at these interviews posted in #deleted-channel and the positive light I’ve put on their questions wondering if we will ever “decouple” from KMD.
!arrrtip @OsTa 7.7701
ARRR TipBotBOT13-Nov-18 04:45 AM
TipBot
Error sending coin. [object Object]
FishyGuts13-Nov-18 04:45 AM
Grrr
!arrrtip @OsTa 7
ARRR TipBotBOT13-Nov-18 04:45 AM
TipBot
@FishyGuts (FishyGuts#5085)
You tipped @OsTa6.9999 ARRR
A network fee of 0.0001 ARRR was deducted from the amount.
This operation is pending. You will be notified when when it has finished.
OsTa13-Nov-18 06:02 AM
thanks for tips and your vision @FishyGuts !(edited)
Anyone who still naively thinks there will be two chains left standing at the end of the #HashWar needs to read today's statement from @CalvinAyre. He makes it abundantly clear what happens if SV has majority hashpower on the Bitcoin Cash network.
https://t.co/25isZ88pQq
actionslacks13-Nov-18 06:27 AM
Sounds like bch abc could use dpow.
 Can’t we all just get along? (edited)
FishyGuts13-Nov-18 08:54 AM
@OsTa I submit to you this...
Pirate marketing really started the 2nd week in October... and we started gaining good traction mid October.
1
I'd say KMD having another need/use case is a good thing.
Malti13-Nov-18 08:56 AM
I missed the boat completely on Pirate, is there a paper I can read to get up to speed?
FishyGuts13-Nov-18 08:57 AM
#deleted-channel has two good interviews at the top of the page